我如何使用杰克逊JSON映射与Java 8 LocalDateTime?
jsonmappingexception:不能实例化类型[简单类型,java.time类]的值。LocalDateTime] from JSON字符串;没有单字符串构造函数/工厂方法(通过引用链:MyDTO["field1"]->SubDTO["date"])
我如何使用杰克逊JSON映射与Java 8 LocalDateTime?
jsonmappingexception:不能实例化类型[简单类型,java.time类]的值。LocalDateTime] from JSON字符串;没有单字符串构造函数/工厂方法(通过引用链:MyDTO["field1"]->SubDTO["date"])
当前回答
这只是一个例子,如何使用它在一个单元测试,我黑调试这个问题。 关键成分是
mapper。registerModule(从新JavaTimeModule (); <artifactId>jack -datatyp -jsr310</artifactId>的maven dependency
代码:
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.datatype.jsr310.JavaTimeModule;
import org.testng.Assert;
import org.testng.annotations.Test;
import java.io.IOException;
import java.io.Serializable;
import java.time.Instant;
class Mumu implements Serializable {
private Instant from;
private String text;
Mumu(Instant from, String text) {
this.from = from;
this.text = text;
}
public Mumu() {
}
public Instant getFrom() {
return from;
}
public String getText() {
return text;
}
@Override
public String toString() {
return "Mumu{" +
"from=" + from +
", text='" + text + '\'' +
'}';
}
}
public class Scratch {
@Test
public void JacksonInstant() throws IOException {
ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(new JavaTimeModule());
Mumu before = new Mumu(Instant.now(), "before");
String jsonInString = mapper.writeValueAsString(before);
System.out.println("-- BEFORE --");
System.out.println(before);
System.out.println(jsonInString);
Mumu after = mapper.readValue(jsonInString, Mumu.class);
System.out.println("-- AFTER --");
System.out.println(after);
Assert.assertEquals(after.toString(), before.toString());
}
}
其他回答
如果你正在使用Spring引导,并且在OffsetDateTime上有这个问题,那么需要使用上面@greperror回答的registerModules(5月28日16日13:04回答),但注意有一个区别。不需要添加提到的依赖项,因为我猜spring boot已经有它了。我有这个问题与春季启动,它为我工作,没有添加这个依赖。
您可以在应用程序中设置此参数。yml文件解析即时时间,即java8中的Date API:
spring.jackson.serialization.write-dates-as-timestamps=false
@JsonDeserialize(using = LocalDateTimeDeserializer.class)
@JsonSerialize(using = LocalDateTimeSerializer.class)
private LocalDateTime createTime;
这对我来说很有效。
对于spring引导api:
@Configuration
public class JsonConfig {
@Bean
public MappingJackson2HttpMessageConverter mappingJackson2HttpMessageConverter() {
MappingJackson2HttpMessageConverter jsonConverter = new MappingJackson2HttpMessageConverter();
ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(new ParameterNamesModule())
.registerModule(new Jdk8Module())
.registerModule(new JavaTimeModule());
mapper.setSerializationInclusion(JsonInclude.Include.NON_NULL);// will remove value properties
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
jsonConverter.setObjectMapper(mapper);
return jsonConverter;
}
}
导入以下依赖项:
implementation 'com.fasterxml.jackson.core:jackson-core:2.13.0'
implementation 'com.fasterxml.jackson.core:jackson-databind:2.13.0'
implementation 'com.fasterxml.jackson.datatype:jackson-datatype-jsr310:2.13.0'
如果你因为任何原因不能使用jackson-modules-java8,你可以(反)序列化即时字段,只要使用@JsonIgnore和@JsonGetter和@JsonSetter:
public class MyBean {
private Instant time = Instant.now();
@JsonIgnore
public Instant getTime() {
return this.time;
}
public void setTime(Instant time) {
this.time = time;
}
@JsonGetter
private long getEpochTime() {
return this.time.toEpochMilli();
}
@JsonSetter
private void setEpochTime(long time) {
this.time = Instant.ofEpochMilli(time);
}
}
例子:
@Test
public void testJsonTime() throws Exception {
String json = new ObjectMapper().writeValueAsString(new MyBean());
System.out.println(json);
MyBean myBean = new ObjectMapper().readValue(json, MyBean.class);
System.out.println(myBean.getTime());
}
收益率
{"epochTime":1506432517242}
2017-09-26T13:28:37.242Z