我如何使用杰克逊JSON映射与Java 8 LocalDateTime?

jsonmappingexception:不能实例化类型[简单类型,java.time类]的值。LocalDateTime] from JSON字符串;没有单字符串构造函数/工厂方法(通过引用链:MyDTO["field1"]->SubDTO["date"])


当前回答

如果你考虑使用fastjson,你可以解决你的问题,注意版本

 <dependency>
        <groupId>com.alibaba</groupId>
        <artifactId>fastjson</artifactId>
        <version>1.2.56</version>
 </dependency>

其他回答

@JsonDeserialize(using = LocalDateTimeDeserializer.class)
@JsonSerialize(using = LocalDateTimeSerializer.class)
private LocalDateTime createTime;

这对我来说很有效。

如果你因为任何原因不能使用jackson-modules-java8,你可以(反)序列化即时字段,只要使用@JsonIgnore和@JsonGetter和@JsonSetter:

public class MyBean {

    private Instant time = Instant.now();

    @JsonIgnore
    public Instant getTime() {
        return this.time;
    }

    public void setTime(Instant time) {
        this.time = time;
    }

    @JsonGetter
    private long getEpochTime() {
        return this.time.toEpochMilli();
    }

    @JsonSetter
    private void setEpochTime(long time) {
        this.time = Instant.ofEpochMilli(time);
    }
}

例子:

@Test
public void testJsonTime() throws Exception {
    String json = new ObjectMapper().writeValueAsString(new MyBean());
    System.out.println(json);
    MyBean myBean = new ObjectMapper().readValue(json, MyBean.class);
    System.out.println(myBean.getTime());
}

收益率

{"epochTime":1506432517242}
2017-09-26T13:28:37.242Z
ObjectMapper objectMapper = new ObjectMapper().configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
objectMapper.registerModule(new JavaTimeModule());

这对我很有效

如果你正在使用Jersey,那么你需要像其他人建议的那样添加Maven依赖项(jackson- dattype -jsr310),并像这样注册你的对象映射器实例:

@Provider
public class JacksonObjectMapper implements ContextResolver<ObjectMapper> {

  final ObjectMapper defaultObjectMapper;

  public JacksonObjectMapper() {
    defaultObjectMapper = createDefaultMapper();
  }

  @Override
  public ObjectMapper getContext(Class<?> type) {
    return defaultObjectMapper;
  }

  private static ObjectMapper createDefaultMapper() {
    final ObjectMapper mapper = new ObjectMapper();    
    mapper.registerModule(new JavaTimeModule());
    return mapper;
  }
}

当在你的资源中注册Jackson时,你需要像这样添加这个映射器:

final ResourceConfig rc = new ResourceConfig().packages("<your package>");
rc
  .register(JacksonObjectMapper.class)
  .register(JacksonJaxbJsonProvider.class);

如果您因为GraphQL Java工具而遇到此问题,并试图从日期字符串编组Java Instant,则需要设置SchemaParser以使用具有特定配置的ObjectMapper:

在GraphQLSchemaBuilder类中,注入ObjectMapper并添加以下模块:

        ObjectMapper objectMapper = 
    new ObjectMapper().registerModule(new JavaTimeModule())
            .configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);

并将其添加到选项中:

final SchemaParserOptions options = SchemaParserOptions.newOptions()
            .objectMapperProvider(fieldDefinition -> objectMapper)
            .typeDefinitionFactory(new YourTypeDefinitionFactory())
            .build();

参见https://github.com/graphql-java-kickstart/graphql-spring-boot/issues/32