我正在集成一个API到我的网站,它与存储在对象中的数据一起工作,而我的代码是使用数组编写的。

我想要一个快速和肮脏的函数将对象转换为数组。


当前回答

当你从数据库中以对象的形式获取数据时,你可能想这样做:

// Suppose 'result' is the end product from some query $query

$result = $mysqli->query($query);
$result = db_result_to_array($result);

function db_result_to_array($result)
{
    $res_array = array();

    for ($count=0; $row = $result->fetch_assoc(); $count++)
        $res_array[$count] = $row;

    return $res_array;
}

其他回答

我认为使用trait来存储对象到数组的转换逻辑是一个不错的想法。举个简单的例子:

trait ArrayAwareTrait
{
    /**
     * Return list of Entity's parameters
     * @return array
     */
    public function toArray()
    {
        $props = array_flip($this->getPropertiesList());
        return array_map(
            function ($item) {
                if ($item instanceof \DateTime) {
                    return $item->format(DATE_ATOM);
                }
                return $item;
            },
            array_filter(get_object_vars($this), function ($key) use ($props) {
                return array_key_exists($key, $props);
            }, ARRAY_FILTER_USE_KEY)
        );
    }


    /**
     * @return array
     */
    protected function getPropertiesList()
    {
        if (method_exists($this, '__sleep')) {
            return $this->__sleep();
        }
        if (defined('static::PROPERTIES')) {
            return static::PROPERTIES;
        }
        return [];
    }
}

class OrderResponse
{
    use ArrayAwareTrait;

    const PROP_ORDER_ID = 'orderId';
    const PROP_TITLE = 'title';
    const PROP_QUANTITY = 'quantity';
    const PROP_BUYER_USERNAME = 'buyerUsername';
    const PROP_COST_VALUE = 'costValue';
    const PROP_ADDRESS = 'address';

    private $orderId;
    private $title;
    private $quantity;
    private $buyerUsername;
    private $costValue;
    private $address;

    /**
     * @param $orderId
     * @param $title
     * @param $quantity
     * @param $buyerUsername
     * @param $costValue
     * @param $address
     */
    public function __construct(
        $orderId,
        $title,
        $quantity,
        $buyerUsername,
        $costValue,
        $address
    ) {
        $this->orderId = $orderId;
        $this->title = $title;
        $this->quantity = $quantity;
        $this->buyerUsername = $buyerUsername;
        $this->costValue = $costValue;
        $this->address = $address;
    }

    /**
     * @inheritDoc
     */
    public function __sleep()
    {
        return [
            static::PROP_ORDER_ID,
            static::PROP_TITLE,
            static::PROP_QUANTITY,
            static::PROP_BUYER_USERNAME,
            static::PROP_COST_VALUE,
            static::PROP_ADDRESS,
        ];
    }

    /**
     * @return mixed
     */
    public function getOrderId()
    {
        return $this->orderId;
    }

    /**
     * @return mixed
     */
    public function getTitle()
    {
        return $this->title;
    }

    /**
     * @return mixed
     */
    public function getQuantity()
    {
        return $this->quantity;
    }

    /**
     * @return mixed
     */
    public function getBuyerUsername()
    {
        return $this->buyerUsername;
    }

    /**
     * @return mixed
     */
    public function getCostValue()
    {
        return $this->costValue;
    }

    /**
     * @return string
     */
    public function getAddress()
    {
        return $this->address;
    }
}

$orderResponse = new OrderResponse(...);
var_dump($orderResponse->toArray());

由于很多人发现这个问题是因为在动态访问对象属性时遇到了麻烦,我只想指出,你可以在PHP中这样做:

在上下文(删除HTML输出可读性):

$valueRows = json_decode("{...}"); // Rows of unordered values decoded from a JSON object

foreach ($valueRows as $valueRow) {

    foreach ($references as $reference) {

        if (isset($valueRow->{$reference->valueName})) {
            $tableHtml .= $valueRow->{$reference->valueName};
        }
        else {
            $tableHtml .= " ";
        }
    }
}

当你从数据库中以对象的形式获取数据时,你可能想这样做:

// Suppose 'result' is the end product from some query $query

$result = $mysqli->query($query);
$result = db_result_to_array($result);

function db_result_to_array($result)
{
    $res_array = array();

    for ($count=0; $row = $result->fetch_assoc(); $count++)
        $res_array[$count] = $row;

    return $res_array;
}

我在Laravel Collections中测试了它,这工作得很好。

function objectToArray($data)
{
    if (is_array($data) || is_object($data))
    {
        $result = [];
        foreach ($data as $key => $value)
        {
            $result[$key] = (is_array($data) || is_object($data)) ? objectToArray($value) : $value;
        }
        return $result;
    }
    return $data;
}

@SpYk3HH的简短解决方案

function objectToArray($o)
{
    $a = array();
    foreach ($o as $k => $v)
        $a[$k] = (is_array($v) || is_object($v)) ? objectToArray($v): $v;

    return $a;
}