如何在我的分支中只存储多个已更改文件中的一个?
当前回答
我没有找到我需要的答案,这很简单:
git add -A
git reset HEAD fileThatYouWantToStash
git commit -m "committing all but one file"
git stash
这只存储了一个文件。
其他回答
git add . //stage all the files
git reset <pathToFileWillBeStashed> //unstage file which will be stashed
git stash //stash the file(s)
git reset . // unstage all staged files
git stash pop // unstash file(s)
将以下代码保存到一个文件中,例如,名为stash。用法是stash<filename_regex>。参数是文件完整路径的正则表达式。例如,要隐藏a/b/c.txt、隐藏a/b/c.txt或隐藏.*/c.txt等。
$ chmod +x stash
$ stash .*.xml
$ stash xyz.xml
要复制到文件中的代码:
#! /usr/bin/expect --
log_user 0
set filename_regexp [lindex $argv 0]
spawn git stash -p
for {} 1 {} {
expect {
-re "diff --git a/($filename_regexp) " {
set filename $expect_out(1,string)
}
"diff --git a/" {
set filename ""
}
"Stash this hunk " {
if {$filename == ""} {
send "n\n"
} else {
send "a\n"
send_user "$filename\n"
}
}
"Stash deletion " {
send "n\n"
}
eof {
exit
}
}
}
git stash push -p -m "my commit message"
-p让我们选择应该隐藏的大块;也可以选择整个文件。
系统将提示您对每个大块执行一些操作:
y - stash this hunk
n - do not stash this hunk
q - quit; do not stash this hunk or any of the remaining ones
a - stash this hunk and all later hunks in the file
d - do not stash this hunk or any of the later hunks in the file
g - select a hunk to go to
/ - search for a hunk matching the given regex
j - leave this hunk undecided, see next undecided hunk
J - leave this hunk undecided, see next hunk
k - leave this hunk undecided, see previous undecided hunk
K - leave this hunk undecided, see previous hunk
s - split the current hunk into smaller hunks
e - manually edit the current hunk
? - print help
要隐藏单个文件,请使用git stash--patch[file]。
这将提示:Stash This hunk[y,n,q,a,d,j,j,g,/,e,?]?。只需键入一个(将此大块和所有后续大块存储在文件中),就可以了。
当git stash-p(或git add-p with stash--keep index)太麻烦时,我发现使用diff、checkout和apply更容易:
仅“隐藏”特定文件/dir:
git diff path/to/dir > stashed.diff
git checkout path/to/dir
然后
git apply stashed.diff