我如何获得屏幕的宽度和高度,并使用这个值在:
@Override protected void onMeasure(int widthSpecId, int heightSpecId) {
Log.e(TAG, "onMeasure" + widthSpecId);
setMeasuredDimension(SCREEN_WIDTH, SCREEN_HEIGHT -
game.findViewById(R.id.flag).getHeight());
}
我如何获得屏幕的宽度和高度,并使用这个值在:
@Override protected void onMeasure(int widthSpecId, int heightSpecId) {
Log.e(TAG, "onMeasure" + widthSpecId);
setMeasuredDimension(SCREEN_WIDTH, SCREEN_HEIGHT -
game.findViewById(R.id.flag).getHeight());
}
当前回答
DisplayMetrics lDisplayMetrics = getResources().getDisplayMetrics();
int widthPixels = lDisplayMetrics.widthPixels;
int heightPixels = lDisplayMetrics.heightPixels;
其他回答
我使用下面的代码来获取屏幕尺寸
getWindow().getDecorView().getWidth()
getWindow().getDecorView().getHeight()
我建议您创建扩展函数。
/**
* Return the width and height of the screen
*/
val Context.screenWidth: Int
get() = resources.displayMetrics.widthPixels
val Context.screenHeight: Int
get() = resources.displayMetrics.heightPixels
/**
* Pixel and Dp Conversion
*/
val Float.toPx get() = this * Resources.getSystem().displayMetrics.density
val Float.toDp get() = this / Resources.getSystem().displayMetrics.density
val Int.toPx get() = (this * Resources.getSystem().displayMetrics.density).toInt()
val Int.toDp get() = (this / Resources.getSystem().displayMetrics.density).toInt()
似乎所有这些答案都不适合我的Galaxy M51和Android 11。在做了一些研究之后,我发现了这个代码:
WindowMetrics windowmetrics = MainActivity.getWindowManager().getCurrentWindowMetrics();
Rect rect = windowmetrics.getBounds();
int width = rect.right;
int height =rect.bottom;
显示我的真实设备分辨率为1080x2400,其余只返回810x1800。
Display display = ((WindowManager) this.getSystemService(Context.WINDOW_SERVICE)).getDefaultDisplay();
int mWidthScreen = display.getWidth();
int mHeightScreen = display.getHeight();
DisplayMetrics lDisplayMetrics = getResources().getDisplayMetrics();
int widthPixels = lDisplayMetrics.widthPixels;
int heightPixels = lDisplayMetrics.heightPixels;