如何在Python中创建目录结构的zip存档?
当前回答
使用pathlib.Path的解决方案,它独立于所使用的操作系统:
import zipfile
from pathlib import Path
def zip_dir(path: Path, zip_file_path: Path):
"""Zip all contents of path to zip_file"""
files_to_zip = [
file for file in path.glob('*') if file.is_file()]
with zipfile.ZipFile(
zip_file_path, 'w', zipfile.ZIP_DEFLATED) as zip_f:
for file in files_to_zip:
print(file.name)
zip_f.write(file, file.name)
current_dir = Path.cwd()
zip_dir = current_dir / "test"
tools.zip_dir(
zip_dir, current_dir / 'Zipped_dir.zip')
其他回答
要保留要归档的父目录下的文件夹层次结构,请执行以下操作:
import glob
import os
import zipfile
with zipfile.ZipFile(fp_zip, "w", zipfile.ZIP_DEFLATED) as zipf:
for fp in glob(os.path.join(parent, "**/*")):
base = os.path.commonpath([parent, fp])
zipf.write(fp, arcname=fp.replace(base, ""))
如果需要,可以将其更改为使用pathlib进行文件globbing。
要将mydirectory的内容添加到新的zip文件中,包括所有文件和子目录:
import os
import zipfile
zf = zipfile.ZipFile("myzipfile.zip", "w")
for dirname, subdirs, files in os.walk("mydirectory"):
zf.write(dirname)
for filename in files:
zf.write(os.path.join(dirname, filename))
zf.close()
使用pathlib.Path的解决方案,它独立于所使用的操作系统:
import zipfile
from pathlib import Path
def zip_dir(path: Path, zip_file_path: Path):
"""Zip all contents of path to zip_file"""
files_to_zip = [
file for file in path.glob('*') if file.is_file()]
with zipfile.ZipFile(
zip_file_path, 'w', zipfile.ZIP_DEFLATED) as zip_f:
for file in files_to_zip:
print(file.name)
zip_f.write(file, file.name)
current_dir = Path.cwd()
zip_dir = current_dir / "test"
tools.zip_dir(
zip_dir, current_dir / 'Zipped_dir.zip')
如果您想要一个类似于任何通用图形文件管理器的压缩文件夹的功能,可以使用以下代码,它使用zipfile模块。使用这段代码,您将得到以路径为根文件夹的zip文件。
import os
import zipfile
def zipdir(path, ziph):
# Iterate all the directories and files
for root, dirs, files in os.walk(path):
# Create a prefix variable with the folder structure inside the path folder.
# So if a file is at the path directory will be at the root directory of the zip file
# so the prefix will be empty. If the file belongs to a containing folder of path folder
# then the prefix will be that folder.
if root.replace(path,'') == '':
prefix = ''
else:
# Keep the folder structure after the path folder, append a '/' at the end
# and remome the first character, if it is a '/' in order to have a path like
# folder1/folder2/file.txt
prefix = root.replace(path, '') + '/'
if (prefix[0] == '/'):
prefix = prefix[1:]
for filename in files:
actual_file_path = root + '/' + filename
zipped_file_path = prefix + filename
zipf.write( actual_file_path, zipped_file_path)
zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
zipdir('/tmp/justtest/', zipf)
zipf.close()
要向生成的zip文件添加压缩,请查看此链接。
您需要更改:
zip = zipfile.ZipFile('Python.zip', 'w')
to
zip = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
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