如何在Python中创建目录结构的zip存档?
当前回答
下面是Nux给出的答案的一个变体,对我有用:
def WriteDirectoryToZipFile( zipHandle, srcPath, zipLocalPath = "", zipOperation = zipfile.ZIP_DEFLATED ):
basePath = os.path.split( srcPath )[ 0 ]
for root, dirs, files in os.walk( srcPath ):
p = os.path.join( zipLocalPath, root [ ( len( basePath ) + 1 ) : ] )
# add dir
zipHandle.write( root, p, zipOperation )
# add files
for f in files:
filePath = os.path.join( root, f )
fileInZipPath = os.path.join( p, f )
zipHandle.write( filePath, fileInZipPath, zipOperation )
其他回答
试试下面的一个。它对我有用。
import zipfile, os
zipf = "compress.zip"
def main():
directory = r"Filepath"
toZip(directory)
def toZip(directory):
zippedHelp = zipfile.ZipFile(zipf, "w", compression=zipfile.ZIP_DEFLATED )
list = os.listdir(directory)
for file_list in list:
file_name = os.path.join(directory,file_list)
if os.path.isfile(file_name):
print file_name
zippedHelp.write(file_name)
else:
addFolderToZip(zippedHelp,file_list,directory)
print "---------------Directory Found-----------------------"
zippedHelp.close()
def addFolderToZip(zippedHelp,folder,directory):
path=os.path.join(directory,folder)
print path
file_list=os.listdir(path)
for file_name in file_list:
file_path=os.path.join(path,file_name)
if os.path.isfile(file_path):
zippedHelp.write(file_path)
elif os.path.isdir(file_name):
print "------------------sub directory found--------------------"
addFolderToZip(zippedHelp,file_name,path)
if __name__=="__main__":
main()
# import required python modules
# You have to install zipfile package using pip install
import os,zipfile
# Change the directory where you want your new zip file to be
os.chdir('Type your destination')
# Create a new zipfile ( I called it myfile )
zf = zipfile.ZipFile('myfile.zip','w')
# os.walk gives a directory tree. Access the files using a for loop
for dirnames,folders,files in os.walk('Type your directory'):
zf.write('Type your Directory')
for file in files:
zf.write(os.path.join('Type your directory',file))
使用python3.9、pathlib&zipfile模块,您可以从系统中的任何位置创建zip文件。
def zip_dir(dir: Union[Path, str], filename: Union[Path, str]):
"""Zip the provided directory without navigating to that directory using `pathlib` module"""
# Convert to Path object
dir = Path(dir)
with zipfile.ZipFile(filename, "w", zipfile.ZIP_DEFLATED) as zip_file:
for entry in dir.rglob("*"):
zip_file.write(entry, entry.relative_to(dir))
它整洁、打字,代码更少。
此函数将递归地压缩目录树,压缩文件,并在存档中记录正确的相对文件名。存档条目与zip-r output.zip source_dir生成的条目相同。
import os
import zipfile
def make_zipfile(output_filename, source_dir):
relroot = os.path.abspath(os.path.join(source_dir, os.pardir))
with zipfile.ZipFile(output_filename, "w", zipfile.ZIP_DEFLATED) as zip:
for root, dirs, files in os.walk(source_dir):
# add directory (needed for empty dirs)
zip.write(root, os.path.relpath(root, relroot))
for file in files:
filename = os.path.join(root, file)
if os.path.isfile(filename): # regular files only
arcname = os.path.join(os.path.relpath(root, relroot), file)
zip.write(filename, arcname)
您可能想看看zipfile模块;文档位于http://docs.python.org/library/zipfile.html.
您可能还需要os.walk()来索引目录结构。
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