如何在我的路由中定义路由。jsx文件捕获__firebase_request_key参数值从一个URL生成的Twitter的单点登录过程后,从他们的服务器重定向?

http://localhost:8000/#/signin?_k=v9ifuf&__firebase_request_key=blablabla

我尝试了以下路由配置,但:redirectParam没有捕获提到的参数:

<Router>
  <Route path="/" component={Main}>
    <Route path="signin" component={SignIn}>
      <Route path=":redirectParam" component={TwitterSsoButton} />
    </Route>
  </Route>
</Router>

当前回答

容易解构分配URLSearchParams

测试尝试如下:

1 扫描:https://www.google.com/?param1=apple&param2=banana

2 右键单击>页,单击Inspect > goto Console选项卡 然后粘贴下面的代码:

const { param1, param2 } = Object.fromEntries(new URLSearchParams(location.search));
console.log("YES!!!", param1, param2 );

输出:

YES!!! apple banana

你可以扩展params,如param1, param2,想扩展多少就扩展多少。

其他回答

使用let {redirectParam} = useParams();如果你用的是功能组件

它是一个类组件

constructor (props) {  
        super(props);
        console.log(props);
        console.log(props.match.params.redirectParam)
}
async componentDidMount(){ 
        console.log(this.props.match.params.redirectParam)
}

在没有第三方库或复杂的解决方案的情况下,在一行中完成这一切。以下是如何

let myVariable = new URLSearchParams(history.location.search).get('business');

你唯一需要改变的是你自己的参数名称的单词“business”。

业务= url.com例子吗?你好

myVariable的结果将是hello

从v4开始,React路由器不再直接在其location对象中提供查询参数。原因是

There are a number of popular packages that do query string parsing/stringifying slightly differently, and each of these differences might be the "correct" way for some users and "incorrect" for others. If React Router picked the "right" one, it would only be right for some people. Then, it would need to add a way for other users to substitute in their preferred query parsing package. There is no internal use of the search string by React Router that requires it to parse the key-value pairs, so it doesn't have a need to pick which one of these should be "right".

包含了这个之后,只解析location会更有意义。在需要查询对象的视图组件中搜索。

你可以通过覆盖react-router中的withRouter来实现这一点

customWithRouter.js

import { compose, withPropsOnChange } from 'recompose';
import { withRouter } from 'react-router';
import queryString from 'query-string';

const propsWithQuery = withPropsOnChange(
    ['location', 'match'],
    ({ location, match }) => {
        return {
            location: {
                ...location,
                query: queryString.parse(location.search)
            },
            match
        };
    }
);

export default compose(withRouter, propsWithQuery)

React路由器v6

来源:在React路由器中获取查询字符串(搜索参数)

使用新的useSearchParams钩子和.get()方法:

const Users = () => {
  const [searchParams] = useSearchParams();
  console.log(searchParams.get('sort')); // 'name'

  return <div>Users</div>;
};

使用这种方法,您可以读取一个或几个参数。

将参数作为一个对象:

如果你需要一次性获得所有的查询字符串参数,那么我们可以像这样使用Object.fromEntries:

const Users = () => {
  const [searchParams] = useSearchParams();
  console.log(Object.fromEntries([...searchParams])); // ▶ { sort: 'name', order: 'asecnding' }
  return <div>Users</div>;
};

阅读更多和现场演示:在React路由器中获取查询字符串(搜索参数)

在React Router v4中,只有withRoute才是正确的方式

您可以通过withRouter高阶组件访问历史对象的属性和最近的匹配。withRouter将在包装组件呈现时将更新的匹配、位置和历史道具传递给它。

import React from 'react'
import PropTypes from 'prop-types'
import { withRouter } from 'react-router'

// A simple component that shows the pathname of the current location
class ShowTheLocation extends React.Component {
  static propTypes = {
    match: PropTypes.object.isRequired,
    location: PropTypes.object.isRequired,
    history: PropTypes.object.isRequired
  }

  render() {
    const { match, location, history } = this.props

    return (
      <div>You are now at {location.pathname}</div>
    )
  }
}

// Create a new component that is "connected" (to borrow redux
// terminology) to the router.
const ShowTheLocationWithRouter = withRouter(ShowTheLocation)

https://reacttraining.com/react-router/web/api/withRouter