首先，我知道这是一个老帖子，但它仍然是相关的，我发现投票最高的两个答案并没有尽早检测到震动。下面是如何做到这一点:

将CoreMotion链接到目标构建阶段的项目: 在你的ViewController中: - (BOOL)canBecomeFirstResponder { 返回YES; ｝ - (void)motionBegan:(UIEventSubtype)motion withEvent:(UIEvent *)event ｛ if(运动== UIEventSubtypeMotionShake) { //检测到震动。 ｝ ｝

I came across this post looking for a "shaking" implementation. millenomi's answer worked well for me, although i was looking for something that required a bit more "shaking action" to trigger. I've replaced to Boolean value with an int shakeCount. I also reimplemented the L0AccelerationIsShaking() method in Objective-C. You can tweak the ammount of shaking required by tweaking the ammount added to shakeCount. I'm not sure i've found the optimal values yet, but it seems to be working well so far. Hope this helps someone:

- (void)accelerometer:(UIAccelerometer *)accelerometer didAccelerate:(UIAcceleration *)acceleration {
    if (self.lastAcceleration) {
        if ([self AccelerationIsShakingLast:self.lastAcceleration current:acceleration threshold:0.7] && shakeCount >= 9) {
            //Shaking here, DO stuff.
            shakeCount = 0;
        } else if ([self AccelerationIsShakingLast:self.lastAcceleration current:acceleration threshold:0.7]) {
            shakeCount = shakeCount + 5;
        }else if (![self AccelerationIsShakingLast:self.lastAcceleration current:acceleration threshold:0.2]) {
            if (shakeCount > 0) {
                shakeCount--;
            }
        }
    }
    self.lastAcceleration = acceleration;
}

- (BOOL) AccelerationIsShakingLast:(UIAcceleration *)last current:(UIAcceleration *)current threshold:(double)threshold {
    double
    deltaX = fabs(last.x - current.x),
    deltaY = fabs(last.y - current.y),
    deltaZ = fabs(last.z - current.z);

    return
    (deltaX > threshold && deltaY > threshold) ||
    (deltaX > threshold && deltaZ > threshold) ||
    (deltaY > threshold && deltaZ > threshold);
}

PS: 我将更新间隔设置为1/15秒。

[[UIAccelerometer sharedAccelerometer] setUpdateInterval:(1.0 / 15)];

首先，我知道这是一个老帖子，但它仍然是相关的，我发现投票最高的两个答案并没有尽早检测到震动。下面是如何做到这一点:

将CoreMotion链接到目标构建阶段的项目: 在你的ViewController中: - (BOOL)canBecomeFirstResponder { 返回YES; ｝ - (void)motionBegan:(UIEventSubtype)motion withEvent:(UIEvent *)event ｛ if(运动== UIEventSubtypeMotionShake) { //检测到震动。 ｝ ｝

首先，肯德尔7月10日的回答是正确的。

现在…我想做一些类似的事情(在iPhone OS 3.0+)，只是在我的情况下，我想在整个应用程序范围内，这样我就可以在震动发生时提醒应用程序的各个部分。这是我最后做的事情。

首先，我子类化了UIWindow。这很容易。创建一个带有接口的类文件，如MotionWindow: UIWindow(随意选择你自己的)。添加一个这样的方法:

- (void)motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event {
    if (event.type == UIEventTypeMotion && event.subtype == UIEventSubtypeMotionShake) {
        [[NSNotificationCenter defaultCenter] postNotificationName:@"DeviceShaken" object:self];
    }
}

更改@"DeviceShaken"为您选择的通知名称。保存文件。

现在，如果你使用主窗口。xib (Xcode模板中常用的东西)然后把Window对象的类从UIWindow改成MotionWindow或者其他什么。保存xib。如果你以编程的方式设置UIWindow，请使用你的新Window类。

现在你的应用正在使用专门的UIWindow类。无论你想在哪里被告知摇晃，注册他们的通知!是这样的:

[[NSNotificationCenter defaultCenter] addObserver:self
selector:@selector(deviceShaken) name:@"DeviceShaken" object:nil];

把自己从观察者的身份移开:

[[NSNotificationCenter defaultCenter] removeObserver:self];

我把我的放在viewWillAppear:和viewWillDisappear:视图控制器相关的地方。确保您对震动事件的响应知道它是否“已经在进行中”。否则，如果设备连续摇晃两次，你就会遇到小塞车。通过这种方式，您可以忽略其他通知，直到真正完成对原始通知的响应。

你也可以选择motionBegan和motionEnded的cue off。由你决定。在我的例子中，效果总是需要在设备休息后发生(而不是当它开始摇晃时)，所以我使用motionEnded。两个都试一下，看看哪个更有意义……或者检测/通知两者!

这里还有一个(奇怪的?)观察:注意，这段代码中没有第一响应器管理的迹象。到目前为止，我只尝试了表视图控制器，一切似乎都很好地工作在一起!但我不能保证其他情况。

Kendall等人——有人能解释一下为什么UIWindow子类会这样吗?是因为窗户位于食物链的顶端吗?

在我的Diceshaker应用中:

// Ensures the shake is strong enough on at least two axes before declaring it a shake.
// "Strong enough" means "greater than a client-supplied threshold" in G's.
static BOOL L0AccelerationIsShaking(UIAcceleration* last, UIAcceleration* current, double threshold) {
    double
        deltaX = fabs(last.x - current.x),
        deltaY = fabs(last.y - current.y),
        deltaZ = fabs(last.z - current.z);

    return
        (deltaX > threshold && deltaY > threshold) ||
        (deltaX > threshold && deltaZ > threshold) ||
        (deltaY > threshold && deltaZ > threshold);
}

@interface L0AppDelegate : NSObject <UIApplicationDelegate> {
    BOOL histeresisExcited;
    UIAcceleration* lastAcceleration;
}

@property(retain) UIAcceleration* lastAcceleration;

@end

@implementation L0AppDelegate

- (void)applicationDidFinishLaunching:(UIApplication *)application {
    [UIAccelerometer sharedAccelerometer].delegate = self;
}

- (void) accelerometer:(UIAccelerometer *)accelerometer didAccelerate:(UIAcceleration *)acceleration {

    if (self.lastAcceleration) {
        if (!histeresisExcited && L0AccelerationIsShaking(self.lastAcceleration, acceleration, 0.7)) {
            histeresisExcited = YES;

            /* SHAKE DETECTED. DO HERE WHAT YOU WANT. */

        } else if (histeresisExcited && !L0AccelerationIsShaking(self.lastAcceleration, acceleration, 0.2)) {
            histeresisExcited = NO;
        }
    }

    self.lastAcceleration = acceleration;
}

// and proper @synthesize and -dealloc boilerplate code

@end

组织性可以防止震动事件多次触发，直到用户停止震动。

最简单的解决方案是为你的应用程序派生一个新的根窗口:

@implementation OMGWindow : UIWindow

- (void)motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event {
    if (event.type == UIEventTypeMotion && motion == UIEventSubtypeMotionShake) {
        // via notification or something   
    }
}
@end

然后在你的应用委托中:

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
    self.window = [[OMGWindow alloc] initWithFrame:[UIScreen mainScreen].bounds];
    //…
}

如果你使用的是故事板，这可能会更棘手，我不知道你在应用委托中需要精确的代码。