在Swift 3.0中尝试以下实现

func delayWithSeconds(_ seconds: Double, completion: @escaping () -> ()) {
    DispatchQueue.main.asyncAfter(deadline: .now() + seconds) { 
        completion()
    }
}

使用

delayWithSeconds(1) {
   //Do something
}

我同意Palle的观点，在这里使用dispatch_after是一个很好的选择。但是您可能不喜欢GCD调用，因为编写它们非常烦人。相反，你可以添加这个方便的助手:

public func delay(bySeconds seconds: Double, dispatchLevel: DispatchLevel = .main, closure: @escaping () -> Void) {
    let dispatchTime = DispatchTime.now() + seconds
    dispatchLevel.dispatchQueue.asyncAfter(deadline: dispatchTime, execute: closure)
}

public enum DispatchLevel {
    case main, userInteractive, userInitiated, utility, background
    var dispatchQueue: DispatchQueue {
        switch self {
        case .main:                 return DispatchQueue.main
        case .userInteractive:      return DispatchQueue.global(qos: .userInteractive)
        case .userInitiated:        return DispatchQueue.global(qos: .userInitiated)
        case .utility:              return DispatchQueue.global(qos: .utility)
        case .background:           return DispatchQueue.global(qos: .background)
        }
    }
}

现在你只需在后台线程上延迟你的代码，就像这样:

delay(bySeconds: 1.5, dispatchLevel: .background) { 
    // delayed code that will run on background thread
}

在主线程上延迟代码甚至更简单:

delay(bySeconds: 1.5) { 
    // delayed code, by default run in main thread
}

如果你喜欢一个框架，也有一些更方便的功能，然后签出handysswift。你可以通过SwiftPM将它添加到你的项目中，然后像上面的例子一样使用它:

import HandySwift    

delay(by: .seconds(1.5)) { 
    // delayed code
}

NSTimer

@nneonneo的回答建议使用NSTimer，但没有说明如何使用。这是基本语法:

let delay = 0.5 // time in seconds
NSTimer.scheduledTimerWithTimeInterval(delay, target: self, selector: #selector(myFunctionName), userInfo: nil, repeats: false)

这里有一个非常简单的项目来展示如何使用它。当一个按钮被按下时，它会启动一个计时器，在延迟半秒后调用一个函数。

import UIKit
class ViewController: UIViewController {

    var timer = NSTimer()
    let delay = 0.5
    
    // start timer when button is tapped
    @IBAction func startTimerButtonTapped(sender: UIButton) {

        // cancel the timer in case the button is tapped multiple times
        timer.invalidate()

        // start the timer
        timer = NSTimer.scheduledTimerWithTimeInterval(delay, target: self, selector: #selector(delayedAction), userInfo: nil, repeats: false)
    }

    // function to be called after the delay
    func delayedAction() {
        print("action has started")
    }
}

使用dispatch_time(如Palle的回答)是另一个有效的选项。然而，这很难取消。使用NSTimer，在延迟事件发生之前取消它，你所需要做的就是调用

timer.invalidate()

不建议使用sleep，特别是在主线程上，因为它会停止线程上正在完成的所有工作。

在这里可以看到我更完整的答案。

在Swift 4.2和Xcode 10.1中

你总共有4种方法来延迟。在这些选项中，首选选项1是在一段时间后调用或执行函数。sleep()是使用最少的情况。

选项1。

DispatchQueue.main.asyncAfter(deadline: .now() + 5.0) {
    self.yourFuncHere()
}
//Your function here    
func yourFuncHere() {

}

第二个选项。

perform(#selector(yourFuncHere2), with: nil, afterDelay: 5.0)

//Your function here  
@objc func yourFuncHere2() {
    print("this is...")
}

选项3。

Timer.scheduledTimer(timeInterval: 5.0, target: self, selector: #selector(yourFuncHere3), userInfo: nil, repeats: false)

//Your function here  
@objc func yourFuncHere3() {

}

选项4。

sleep(5)

如果你想在一段时间后调用一个函数来执行一些东西，不要使用sleep。

Using a dispatch_after block is in most cases better than using sleep(time) as the thread on which the sleep is performed is blocked from doing other work. when using dispatch_after the thread which is worked on does not get blocked so it can do other work in the meantime. If you are working on the main thread of your application, using sleep(time) is bad for the user experience of your app as the UI is unresponsive during that time. Dispatch after schedules the execution of a block of code instead of freezing the thread:

斯威夫特≥ 3.0

let seconds = 4.0
DispatchQueue.main.asyncAfter(deadline: .now() + seconds) {
    // Put your code which should be executed with a delay here
}

Swift≥5.5(异步):

func foo() async {
    try await Task.sleep(nanoseconds: UInt64(seconds * Double(NSEC_PER_SEC)))
    // Put your code which should be executed with a delay here
}

Swift < 3.0

let time = dispatch_time(dispatch_time_t(DISPATCH_TIME_NOW), 4 * Int64(NSEC_PER_SEC))
dispatch_after(time, dispatch_get_main_queue()) {
    // Put your code which should be executed with a delay here
}

使用DispatchQueue的. asyncafter方法，可以在给定时间后执行代码。例如，执行…在主线程中，1秒后看起来是这样的:

DispatchQueue.main.asyncAfter(deadline: .now() + 1) { ... }

使用我方便的延迟包装器结构，你可以以更奇特的方式执行它:

struct Delay {

    @discardableResult
    init(_ timeInterval: TimeInterval, queue: DispatchQueue = .main, executingBlock: @escaping () -> Void) {
        queue.asyncAfter(deadline: .now() + timeInterval, execute: executingBlock)
    }

}

用法:

Delay(0.4) { ... }