是否有一种方法可以在JavaScript中返回两个数组之间的差异?
例如:
var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];
// need ["c", "d"]
是否有一种方法可以在JavaScript中返回两个数组之间的差异?
例如:
var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];
// need ["c", "d"]
当前回答
var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];
var diff = [];
for (var i in a2) {
var found = false;
for (var j in a1) {
if (a2[i] === a1[j]) found = true;
}
if (found === false) diff.push(a2[i]);
}
那么简单。也可以用于对象,检查对象的一个属性。 就像,
if (a2[i].id === a1[j].id) found = true;
其他回答
const dbData = [{name:'ally'},
{name:'James'}]
const localData = [{name:'James'}]
const diff = dbData.filter(a =>!localData.some(b => { return a.name === b.name}))
另一种解决问题的方法
function diffArray(arr1, arr2) {
return arr1.concat(arr2).filter(function (val) {
if (!(arr1.includes(val) && arr2.includes(val)))
return val;
});
}
diffArray([1, 2, 3, 7], [3, 2, 1, 4, 5]); // return [7, 4, 5]
同样,你可以使用箭头函数语法:
const diffArray = (arr1, arr2) => arr1.concat(arr2)
.filter(val => !(arr1.includes(val) && arr2.includes(val)));
diffArray([1, 2, 3, 7], [3, 2, 1, 4, 5]); // return [7, 4, 5]
只是修整字符串以确保....空格不会影响差异
function arr_diff(a1, a2) {
var a=[], diff=[];
for(var i=0;i<a1.length;i++)
a[a1[i]]=true;
for(var i=0;i<a2.length;i++)
if(a[a2[i].trim()]) delete a[a2[i].trim()];
else a[a2[i].trim()]=true;
for(var k in a)
diff.push(k);
return diff;
}
var arrayDifference = function(arr1, arr2){
if(arr1 && arr1.length){
if(arr2 && arr2.length > 0){
for (var i=0, itemIndex; i<arr2.length; i++){
itemIndex = arr1.indexOf(arr2[i]);
if(itemIndex !== -1){
arr1.splice(itemIndex, 1);
}
}
}
return arr1;
}
return [];
};
arrayDifference([1,2,3,4,5], [1,5,6]);
Array.prototype.diff =函数(a) { return this.filter(function(i) {return a.f index_of (i) < 0;}); }; ////////////// //示例// ////////////// Const dif1 =[1,2,3,4,5,6]。Diff ([3,4,5]); console.log (dif1);// => [1,2,6] const dif2 =[“test1”、“test2”,“test3”,“test4”,“test5”,“test6”].diff([“test1”、“test2”,“test3”、“test4”)); console.log (dif2);// => ["test5", "test6"]
注意:. indexof()和.filter()在IE9之前是不可用的。