ES6 Generator版本

function* chunkArray(array,size=1){
    var clone = array.slice(0);
    while (clone.length>0) 
      yield clone.splice(0,size); 
};
var a = new Array(100).fill().map((x,index)=>index);
for(const c of chunkArray(a,10)) 
    console.log(c);

对源数组进行突变:

let a = [ 1, 2, 3, 4, 5, 6, 7, 8, 9 ], aa = [], x
while((x = a.splice(0, 2)).length) aa.push(x)

// aa == [ [ 1, 2 ], [ 3, 4 ], [ 5, 6 ], [ 7, 8 ], [ 9 ] ]
// a == []

不改变源数组:

let a = [ 1, 2, 3, 4, 5, 6, 7, 8, 9 ], aa = []
for(let i = 0; i < a.length; i += 2) aa.push(a.slice(i, i + 2))

// aa == [ [ 1, 2 ], [ 3, 4 ], [ 5, 6 ], [ 7, 8 ], [ 9 ] ]
// a == [ 1, 2, 3, 4, 5, 6, 7, 8, 9 ]

我的目标是在纯ES6中创建一个简单的非突变解决方案。javascript的特性使得在映射之前必须填充空数组:-(

function chunk(a, l) { 
    return new Array(Math.ceil(a.length / l)).fill(0)
        .map((_, n) => a.slice(n*l, n*l + l)); 
}

这个带有递归的版本似乎更简单，也更引人注目:

function chunk(a, l) { 
    if (a.length == 0) return []; 
    else return [a.slice(0, l)].concat(chunk(a.slice(l), l)); 
}

ES6中荒谬的弱数组函数可以制作出很好的谜题:-)

下面是一个使用ImmutableJS的解决方案，其中items是一个不可变列表，size是所需的分组大小。

const partition = ((items, size) => {
  return items.groupBy((items, i) => Math.floor(i/size))
})

这是我能想到的最有效、最直接的解决方案:

function chunk(array, chunkSize) {
    let chunkCount = Math.ceil(array.length / chunkSize);
    let chunks = new Array(chunkCount);
    for(let i = 0, j = 0, k = chunkSize; i < chunkCount; ++i) {
        chunks[i] = array.slice(j, k);
        j = k;
        k += chunkSize;
    }
    return chunks;
}

我只是在groupBy函数的帮助下写了这个。

// utils const group = (source) => ({ by: (grouping) => { const groups = source.reduce((accumulator, item) => { const name = JSON.stringify(grouping(item)); accumulator[name] = accumulator[name] || []; accumulator[name].push(item); return accumulator; }, {}); return Object.keys(groups).map(key => groups[key]); } }); const chunk = (source, size) => group(source.map((item, index) => ({ item, index }))) .by(x => Math.floor(x.index / size)) .map(x => x.map(v => v.item)); // 103 items const arr = [6,2,6,6,0,7,4,9,3,1,9,6,1,2,7,8,3,3,4,6,8,7,6,9,3,6,3,5,0,9,3,7,0,4,1,9,7,5,7,4,3,4,8,9,0,5,1,0,0,8,0,5,8,3,2,5,6,9,0,0,1,5,1,7,0,6,1,6,8,4,9,8,9,1,6,5,4,9,1,6,6,1,8,3,5,5,7,0,8,3,1,7,1,1,7,6,4,9,7,0,5,1,0]; const chunks = chunk(arr, 10); console.log(JSON.stringify(chunks));