不可能，但是布局文件夹是按名称排序的。因此，我在布局文件名前加上包名。例如，对于“购买”和“玩”两个包:

buying_bought_tracks.xml
buying_buy_tracks.xml
playing_edit_playlist.xml
playing_play_playlist.xml
playing_show_playlists.xml

I think the most elegant solution to this problem (given that subfolders are not allowed) is to prepend the file names with the name of the folder you would have placed it inside of. For example, if you have a bunch of layouts for an Activity, Fragment, or just general view called "places" then you should just prepend it with places_my_layout_name. At least this solves the problem of organizing them in a way that they are easier to find within the IDE. It's not the most awesome solution, but it's better than nothing.

小问题

我能够通过遵循这个问题的顶部答案来实现子文件夹。

然而，随着项目越来越大，你会有很多子文件夹:

sourceSets {
    main {
        res.srcDirs = [
            'src/main/res/layouts/somethingA',
            'src/main/res/layouts/somethingB',
            'src/main/res/layouts/somethingC',
            'src/main/res/layouts/somethingD',
            'src/main/res/layouts/somethingE',
            'src/main/res/layouts/somethingF',
            'src/main/res/layouts/somethingG',
            'src/main/res/layouts/somethingH',
            'src/main/res/layouts/...many more',
            'src/main/res'
        ]
    }
}

不是什么大问题，但是:

当清单变得很长时，它就不好看了。 你必须改变你的应用/构建。每次添加新文件夹时Gradle。

---

改进

所以我写了一个简单的Groovy方法来抓取所有嵌套文件夹:

def getLayoutList(path) {
    File file = new File(path)
    def throwAway = file.path.split("/")[0]
    def newPath = file.path.substring(throwAway.length() + 1)
    def array = file.list().collect {
        "${newPath}/${it}"
    }
    array.push("src/main/res");
    return array
}

将此方法粘贴到android{…}块在你的app/build.gradle。

---

如何使用

对于这样的结构:

<project root>
├── app <---------- TAKE NOTE
├── build
├── build.gradle
├── gradle
├── gradle.properties
├── gradlew
├── gradlew.bat
├── local.properties
└── settings.gradle

像这样使用它:

android {
    sourceSets {
        main {
            res.srcDirs = getLayoutList("app/src/main/res/layouts/")
        }
    }
}

如果你有一个这样的结构:

<project root>
├── my_special_app_name <---------- TAKE NOTE
├── build
├── build.gradle
├── gradle
├── gradle.properties
├── gradlew
├── gradlew.bat
├── local.properties
└── settings.gradle

你可以这样使用它:

android {
    sourceSets {
        main {
            res.srcDirs = getLayoutList("my_special_app_name/src/main/res/layouts/")
        }
    }
}

---

解释

getLayoutList()接受一个相对路径作为参数。相对路径相对于项目的根路径。所以当我们输入"app/src/main/res/layouts/"时，它会以数组的形式返回所有子文件夹的名称，这将与:

[
    'src/main/res/layouts/somethingA',
    'src/main/res/layouts/somethingB',
    'src/main/res/layouts/somethingC',
    'src/main/res/layouts/somethingD',
    'src/main/res/layouts/somethingE',
    'src/main/res/layouts/somethingF',
    'src/main/res/layouts/somethingG',
    'src/main/res/layouts/somethingH',
    'src/main/res/layouts/...many more',
    'src/main/res'
]

下面是带有注释的脚本，便于理解:

def getLayoutList(path) {
    // let's say path = "app/src/main/res/layouts/
    File file = new File(path)

    def throwAway = file.path.split("/")[0]
    // throwAway = 'app'

    def newPath = file.path.substring(throwAway.length() + 1) // +1 is for '/'
    // newPath = src/main/res/layouts/

    def array = file.list().collect {
        // println "filename: ${it}" // uncomment for debugging
        "${newPath}/${it}"
    }

    array.push("src/main/res");
    // println "result: ${array}" // uncomment for debugging

    return array
}

---

希望能有所帮助!

不可能，但是布局文件夹是按名称排序的。因此，我在布局文件名前加上包名。例如，对于“购买”和“玩”两个包:

buying_bought_tracks.xml
buying_buy_tracks.xml
playing_edit_playlist.xml
playing_play_playlist.xml
playing_show_playlists.xml

我使用Android文件分组插件的Android工作室。它不允许你创建子文件夹，但是它可以显示你的文件和资源，因为它们在不同的文件夹中。这正是我想要的。

你可以安装“Android文件分组”插件通过

窗口:

Android Studio ->文件->设置->插件。

Mac:

Android Studio标签(左上)->首选项->插件->安装JetBrains插件..

对于Mac，我能够测试它，不能搜索插件。所以我从这里下载了插件，并从上面的设置中使用了从磁盘安装插件选项。

现在我们可以很容易地使用JetBrains插件“Android文件分组”

看看这个链接

Android文件分组