最近我一直在iPhone上玩一款名为《Scramble》的游戏。有些人可能知道这个游戏叫拼字游戏。从本质上讲,当游戏开始时,你会得到一个字母矩阵:

F X I E
A M L O
E W B X
A S T U

The goal of the game is to find as many words as you can that can be formed by chaining letters together. You can start with any letter, and all the letters that surround it are fair game, and then once you move on to the next letter, all the letters that surround that letter are fair game, except for any previously used letters. So in the grid above, for example, I could come up with the words LOB, TUX, SEA, FAME, etc. Words must be at least 3 characters, and no more than NxN characters, which would be 16 in this game but can vary in some implementations. While this game is fun and addictive, I am apparently not very good at it and I wanted to cheat a little bit by making a program that would give me the best possible words (the longer the word the more points you get).

(来源:boggled.org)

不幸的是,我不太擅长算法或它们的效率等等。我的第一次尝试使用一个像这样的字典(约2.3MB),并进行线性搜索,试图匹配字典条目的组合。这需要花费很长时间来找到可能的单词,因为你每轮只有2分钟的时间,这是不够的。

我很有兴趣看看是否有任何Stackoverflowers可以提出更有效的解决方案。我主要是在寻找使用三大p的解决方案:Python、PHP和Perl,尽管任何使用Java或c++的东西也很酷,因为速度是至关重要的。

目前的解决方案:

Adam Rosenfield, Python, ~20岁 John Fouhy, Python, ~3秒 Kent Fredric, Perl, ~1s Darius Bacon, Python, ~1s rvarcher, VB。净,~ 1 s Paolo Bergantino, PHP(实时链接),~5s(本地~2s)


当前回答

I wrote my solver in C++. I implemented a custom tree structure. I'm not sure it can be considered a trie but it's similar. Each node has 26 branches, 1 for each letter of the alphabet. I traverse the branches of the boggle board in parallel with the branches of my dictionary. If the branch does not exist in the dictionary, I stop searching it on the Boggle board. I convert all the letters on the board to ints. So 'A' = 0. Since it's just arrays, lookup is always O(1). Each node stores if it completes a word and how many words exist in its children. The tree is pruned as words are found to reduce repeatedly searching for the same words. I believe pruning is also O(1).

CPU: Pentium SU2700 1.3GHz 内存:3 gb

在< 1秒内加载178,590个单词的字典。 在4秒内解决100x100 Boggle (Boggle .txt)。约44000字。 解决4x4 Boggle游戏的速度太快,无法提供有意义的基准。:)

快速Boggle求解GitHub回购

其他回答

我不得不对一个完整的解决方案进行更多的思考,但作为一种方便的优化,我想知道是否值得根据字典中的所有单词预先计算一个图表和三字母组合(2字母和3字母组合)的频率表,并使用它来确定搜索的优先级。我会选择单词的首字母。因此,如果你的字典包含“印度”、“水”、“极端”和“非凡”这些词,那么你预先计算的表可能是:

'IN': 1
'WA': 1
'EX': 2

然后按照共性的顺序(首先是EX,然后是WA/ in)搜索这些图表

下面是我的java实现:https://github.com/zouzhile/interview/blob/master/src/com/interview/algorithms/tree/BoggleSolver.java

Trie构建耗时0小时0分1秒532毫秒 单词搜索花了0小时0分0秒92毫秒

eel eeler eely eer eke eker eld eleut elk ell 
elle epee epihippus ere erept err error erupt eurus eye 
eyer eyey hip hipe hiper hippish hipple hippus his hish 
hiss hist hler hsi ihi iphis isis issue issuer ist 
isurus kee keek keeker keel keeler keep keeper keld kele 
kelek kelep kelk kell kelly kelp kelper kep kepi kept 
ker kerel kern keup keuper key kyl kyle lee leek 
leeky leep leer lek leo leper leptus lepus ler leu 
ley lleu lue lull luller lulu lunn lunt lunule luo 
lupe lupis lupulus lupus lur lure lurer lush lushly lust 
lustrous lut lye nul null nun nupe nurture nurturer nut 
oer ore ort ouphish our oust out outpeep outpeer outpipe 
outpull outpush output outre outrun outrush outspell outspue outspurn outspurt 
outstrut outstunt outsulk outturn outusure oyer pee peek peel peele 
peeler peeoy peep peeper peepeye peer pele peleus pell peller 
pelu pep peplus pepper pepperer pepsis per pern pert pertussis 
peru perule perun peul phi pip pipe piper pipi pipistrel 
pipistrelle pipistrellus pipper pish piss pist plup plus plush ply 
plyer psi pst puerer pul pule puler pulk pull puller 
pulley pullus pulp pulper pulu puly pun punt pup puppis 
pur pure puree purely purer purr purre purree purrel purrer 
puru purupuru pus push puss pustule put putt puture ree 
reek reeker reeky reel reeler reeper rel rely reoutput rep 
repel repeller repipe reply repp reps reree rereel rerun reuel 
roe roer roey roue rouelle roun roup rouper roust rout 
roy rue ruelle ruer rule ruler rull ruller run runt 
rupee rupert rupture ruru rus rush russ rust rustre rut 
shi shih ship shipper shish shlu sip sipe siper sipper 
sis sish sisi siss sissu sist sistrurus speel speer spelk 
spell speller splurt spun spur spurn spurrer spurt sput ssi 
ssu stre stree streek streel streeler streep streke streperous strepsis 
strey stroup stroy stroyer strue strunt strut stu stue stull 
stuller stun stunt stupe stupeous stupp sturnus sturt stuss stut 
sue suer suerre suld sulk sulker sulky sull sully sulu 
sun sunn sunt sunup sup supe super superoutput supper supple 
supplely supply sur sure surely surrey sus susi susu susurr 
susurrous susurrus sutu suture suu tree treey trek trekker trey 
troupe trouper trout troy true truer trull truller truly trun 
trush truss trust tshi tst tsun tsutsutsi tue tule tulle 
tulu tun tunu tup tupek tupi tur turn turnup turr 
turus tush tussis tussur tut tuts tutu tutulus ule ull 
uller ulu ululu unreel unrule unruly unrun unrust untrue untruly 
untruss untrust unturn unurn upper upperer uppish uppishly uppull uppush 
upspurt upsun upsup uptree uptruss upturn ure urn uro uru 
urus urushi ush ust usun usure usurer utu yee yeel 
yeld yelk yell yeller yelp yelper yeo yep yer yere 
yern yoe yor yore you youl youp your yourn yoy 

注意: 我在这个线程的开头使用了字典和字符矩阵。代码在我的MacBookPro上运行,下面是关于这台机器的一些信息。

型号:MacBook Pro 型号标识符:MacBookPro8,1 处理器名称:Intel Core i5 处理器速度:2.3 GHz 处理器数量:1 总核数:2 L2缓存(每核):256kb L3 Cache: 3mb 内存:4gb 引导ROM版本:MBP81.0047.B0E SMC版本(系统):1.68f96

我在Java上的尝试。读取文件和构建trie大约需要2秒,解决谜题大约需要50毫秒。我用了问题中链接的字典(里面有几个我不知道在英语中存在的单词,比如fae, ima)

0 [main] INFO gineer.bogglesolver.util.Util  - Reading the dictionary
2234 [main] INFO gineer.bogglesolver.util.Util  - Finish reading the dictionary
2234 [main] INFO gineer.bogglesolver.Solver  - Found: FAM
2234 [main] INFO gineer.bogglesolver.Solver  - Found: FAME
2234 [main] INFO gineer.bogglesolver.Solver  - Found: FAMBLE
2234 [main] INFO gineer.bogglesolver.Solver  - Found: FAE
2234 [main] INFO gineer.bogglesolver.Solver  - Found: IMA
2234 [main] INFO gineer.bogglesolver.Solver  - Found: ELI
2234 [main] INFO gineer.bogglesolver.Solver  - Found: ELM
2234 [main] INFO gineer.bogglesolver.Solver  - Found: ELB
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AXIL
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AXILE
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AXLE
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AMI
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AMIL
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AMLI
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AME
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AMBLE
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AMBO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AES
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWEST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MIX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MIL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MILE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MILO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MAX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MAE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MAW
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MEW
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MEWL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MES
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MESA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMAX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIME
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMES
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMB
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMBO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMBU
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LEI
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LEO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LOB
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LOX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: OIME
2250 [main] INFO gineer.bogglesolver.Solver  - Found: OIL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: OLE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: OLM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: EMIL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: EMBOLE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: EMBOX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: EAST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAF
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAME
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAMBLE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WEA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WEAM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WEM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WEA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WES
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WEST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAS
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WASE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: BLEO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: BLO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: BOIL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: BOLE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: BUT
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AES
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWEST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: ASE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: ASEM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEAX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEAM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEMI
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEMBLE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEW
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SWAM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SWAMI
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SAW
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SAWT
2250 [main] INFO gineer.bogglesolver.Solver  - Found: STU
2250 [main] INFO gineer.bogglesolver.Solver  - Found: STUB
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TWAE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TWAE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TWAS
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TUB
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TUX

源代码由6个类组成。我将把它们贴在下面(如果这不是StackOverflow的正确做法,请告诉我)。

gineer.bogglesolver.Main

package gineer.bogglesolver;

import org.apache.log4j.BasicConfigurator;
import org.apache.log4j.Logger;

public class Main
{
    private final static Logger logger = Logger.getLogger(Main.class);

    public static void main(String[] args)
    {
        BasicConfigurator.configure();

        Solver solver = new Solver(4,
                        "FXIE" +
                        "AMLO" +
                        "EWBX" +
                        "ASTU");
        solver.solve();

    }
}

gineer.bogglesolver.Solver

package gineer.bogglesolver;

import gineer.bogglesolver.trie.Trie;
import gineer.bogglesolver.util.Constants;
import gineer.bogglesolver.util.Util;
import org.apache.log4j.Logger;

public class Solver
{
    private char[] puzzle;
    private int maxSize;

    private boolean[] used;
    private StringBuilder stringSoFar;

    private boolean[][] matrix;
    private Trie trie;

    private final static Logger logger = Logger.getLogger(Solver.class);

    public Solver(int size, String puzzle)
    {
        trie = Util.getTrie(size);
        matrix = Util.connectivityMatrix(size);

        maxSize = size * size;
        stringSoFar = new StringBuilder(maxSize);
        used = new boolean[maxSize];

        if (puzzle.length() == maxSize)
        {
            this.puzzle = puzzle.toCharArray();
        }
        else
        {
            logger.error("The puzzle size does not match the size specified: " + puzzle.length());
            this.puzzle = puzzle.substring(0, maxSize).toCharArray();
        }
    }

    public void solve()
    {
        for (int i = 0; i < maxSize; i++)
        {
            traverseAt(i);
        }
    }

    private void traverseAt(int origin)
    {
        stringSoFar.append(puzzle[origin]);
        used[origin] = true;

        //Check if we have a valid word
        if ((stringSoFar.length() >= Constants.MINIMUM_WORD_LENGTH) && (trie.containKey(stringSoFar.toString())))
        {
            logger.info("Found: " + stringSoFar.toString());
        }

        //Find where to go next
        for (int destination = 0; destination < maxSize; destination++)
        {
            if (matrix[origin][destination] && !used[destination] && trie.containPrefix(stringSoFar.toString() + puzzle[destination]))
            {
                traverseAt(destination);
            }
        }

        used[origin] = false;
        stringSoFar.deleteCharAt(stringSoFar.length() - 1);
    }

}

gineer.bogglesolver.trie.Node

package gineer.bogglesolver.trie;

import gineer.bogglesolver.util.Constants;

class Node
{
    Node[] children;
    boolean isKey;

    public Node()
    {
        isKey = false;
        children = new Node[Constants.NUMBER_LETTERS_IN_ALPHABET];
    }

    public Node(boolean key)
    {
        isKey = key;
        children = new Node[Constants.NUMBER_LETTERS_IN_ALPHABET];
    }

    /**
     Method to insert a string to Node and its children

     @param key the string to insert (the string is assumed to be uppercase)
     @return true if the node or one of its children is changed, false otherwise
     */
    public boolean insert(String key)
    {
        //If the key is empty, this node is a key
        if (key.length() == 0)
        {
            if (isKey)
                return false;
            else
            {
                isKey = true;
                return true;
            }
        }
        else
        {//otherwise, insert in one of its child

            int childNodePosition = key.charAt(0) - Constants.LETTER_A;
            if (children[childNodePosition] == null)
            {
                children[childNodePosition] = new Node();
                children[childNodePosition].insert(key.substring(1));
                return true;
            }
            else
            {
                return children[childNodePosition].insert(key.substring(1));
            }
        }
    }

    /**
     Returns whether key is a valid prefix for certain key in this trie.
     For example: if key "hello" is in this trie, tests with all prefixes "hel", "hell", "hello" return true

     @param prefix the prefix to check
     @return true if the prefix is valid, false otherwise
     */
    public boolean containPrefix(String prefix)
    {
        //If the prefix is empty, return true
        if (prefix.length() == 0)
        {
            return true;
        }
        else
        {//otherwise, check in one of its child
            int childNodePosition = prefix.charAt(0) - Constants.LETTER_A;
            return children[childNodePosition] != null && children[childNodePosition].containPrefix(prefix.substring(1));
        }
    }

    /**
     Returns whether key is a valid key in this trie.
     For example: if key "hello" is in this trie, tests with all prefixes "hel", "hell" return false

     @param key the key to check
     @return true if the key is valid, false otherwise
     */
    public boolean containKey(String key)
    {
        //If the prefix is empty, return true
        if (key.length() == 0)
        {
            return isKey;
        }
        else
        {//otherwise, check in one of its child
            int childNodePosition = key.charAt(0) - Constants.LETTER_A;
            return children[childNodePosition] != null && children[childNodePosition].containKey(key.substring(1));
        }
    }

    public boolean isKey()
    {
        return isKey;
    }

    public void setKey(boolean key)
    {
        isKey = key;
    }
}

gineer.bogglesolver.trie.Trie

package gineer.bogglesolver.trie;

public class Trie
{
    Node root;

    public Trie()
    {
        this.root = new Node();
    }

    /**
     Method to insert a string to Node and its children

     @param key the string to insert (the string is assumed to be uppercase)
     @return true if the node or one of its children is changed, false otherwise
     */
    public boolean insert(String key)
    {
        return root.insert(key.toUpperCase());
    }

    /**
     Returns whether key is a valid prefix for certain key in this trie.
     For example: if key "hello" is in this trie, tests with all prefixes "hel", "hell", "hello" return true

     @param prefix the prefix to check
     @return true if the prefix is valid, false otherwise
     */
    public boolean containPrefix(String prefix)
    {
        return root.containPrefix(prefix.toUpperCase());
    }

    /**
     Returns whether key is a valid key in this trie.
     For example: if key "hello" is in this trie, tests with all prefixes "hel", "hell" return false

     @param key the key to check
     @return true if the key is valid, false otherwise
     */
    public boolean containKey(String key)
    {
        return root.containKey(key.toUpperCase());
    }


}

gineer.bogglesolver.util.Constants

package gineer.bogglesolver.util;

public class Constants
{

    public static final int NUMBER_LETTERS_IN_ALPHABET = 26;
    public static final char LETTER_A = 'A';
    public static final int MINIMUM_WORD_LENGTH = 3;
    public static final int DEFAULT_PUZZLE_SIZE = 4;
}

gineer.bogglesolver.util.Util

package gineer.bogglesolver.util;

import gineer.bogglesolver.trie.Trie;
import org.apache.log4j.Logger;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class Util
{
    private final static Logger logger = Logger.getLogger(Util.class);
    private static Trie trie;
    private static int size = Constants.DEFAULT_PUZZLE_SIZE;

    /**
     Returns the trie built from the dictionary.  The size is used to eliminate words that are too long.

     @param size the size of puzzle.  The maximum lenght of words in the returned trie is (size * size)
     @return the trie that can be used for puzzle of that size
     */
    public static Trie getTrie(int size)
    {
        if ((trie != null) && size == Util.size)
            return trie;

        trie = new Trie();
        Util.size = size;

        logger.info("Reading the dictionary");
        final File file = new File("dictionary.txt");
        try
        {
            Scanner scanner = new Scanner(file);
            final int maxSize = size * size;
            while (scanner.hasNext())
            {
                String line = scanner.nextLine().replaceAll("[^\\p{Alpha}]", "");

                if (line.length() <= maxSize)
                    trie.insert(line);
            }
        }
        catch (FileNotFoundException e)
        {
            logger.error("Cannot open file", e);
        }

        logger.info("Finish reading the dictionary");
        return trie;
    }

    static boolean[] connectivityRow(int x, int y, int size)
    {
        boolean[] squares = new boolean[size * size];
        for (int offsetX = -1; offsetX <= 1; offsetX++)
        {
            for (int offsetY = -1; offsetY <= 1; offsetY++)
            {
                final int calX = x + offsetX;
                final int calY = y + offsetY;
                if ((calX >= 0) && (calX < size) && (calY >= 0) && (calY < size))
                    squares[calY * size + calX] = true;
            }
        }

        squares[y * size + x] = false;//the current x, y is false

        return squares;
    }

    /**
     Returns the matrix of connectivity between two points.  Point i can go to point j iff matrix[i][j] is true
     Square (x, y) is equivalent to point (size * y + x).  For example, square (1,1) is point 5 in a puzzle of size 4

     @param size the size of the puzzle
     @return the connectivity matrix
     */
    public static boolean[][] connectivityMatrix(int size)
    {
        boolean[][] matrix = new boolean[size * size][];
        for (int x = 0; x < size; x++)
        {
            for (int y = 0; y < size; y++)
            {
                matrix[y * size + x] = connectivityRow(x, y, size);
            }
        }
        return matrix;
    }
}

令人惊讶的是,没有人尝试使用PHP版本。

这是John Fouhy的Python解决方案的PHP版本。

虽然我从其他人的答案中得到了一些建议,但这主要是抄袭约翰的。

$boggle = "fxie
           amlo
           ewbx
           astu";

$alphabet = str_split(str_replace(array("\n", " ", "\r"), "", strtolower($boggle)));
$rows = array_map('trim', explode("\n", $boggle));
$dictionary = file("C:/dict.txt");
$prefixes = array(''=>'');
$words = array();
$regex = '/[' . implode('', $alphabet) . ']{3,}$/S';
foreach($dictionary as $k=>$value) {
    $value = trim(strtolower($value));
    $length = strlen($value);
    if(preg_match($regex, $value)) {
        for($x = 0; $x < $length; $x++) {
            $letter = substr($value, 0, $x+1);
            if($letter == $value) {
                $words[$value] = 1;
            } else {
                $prefixes[$letter] = 1;
            }
        }
    }
}

$graph = array();
$chardict = array();
$positions = array();
$c = count($rows);
for($i = 0; $i < $c; $i++) {
    $l = strlen($rows[$i]);
    for($j = 0; $j < $l; $j++) {
        $chardict[$i.','.$j] = $rows[$i][$j];
        $children = array();
        $pos = array(-1,0,1);
        foreach($pos as $z) {
            $xCoord = $z + $i;
            if($xCoord < 0 || $xCoord >= count($rows)) {
                continue;
            }
            $len = strlen($rows[0]);
            foreach($pos as $w) {
                $yCoord = $j + $w;
                if(($yCoord < 0 || $yCoord >= $len) || ($z == 0 && $w == 0)) {
                    continue;
                }
                $children[] = array($xCoord, $yCoord);
            }
        }
        $graph['None'][] = array($i, $j);
        $graph[$i.','.$j] = $children;
    }
}

function to_word($chardict, $prefix) {
    $word = array();
    foreach($prefix as $v) {
        $word[] = $chardict[$v[0].','.$v[1]];
    }
    return implode("", $word);
}

function find_words($graph, $chardict, $position, $prefix, $prefixes, &$results, $words) {
    $word = to_word($chardict, $prefix);
    if(!isset($prefixes[$word])) return false;

    if(isset($words[$word])) {
        $results[] = $word;
    }

    foreach($graph[$position] as $child) {
        if(!in_array($child, $prefix)) {
            $newprefix = $prefix;
            $newprefix[] = $child;
            find_words($graph, $chardict, $child[0].','.$child[1], $newprefix, $prefixes, $results, $words);
        }
    }
}

$solution = array();
find_words($graph, $chardict, 'None', array(), $prefixes, $solution);
print_r($solution);

如果你想尝试的话,这里有一个实时链接。虽然在我的本地机器上需要大约2秒,但在我的web服务器上需要大约5秒。无论哪种情况,它都不是很快。尽管如此,它还是很可怕,所以我可以想象时间可以大大缩短。任何关于如何实现这一目标的建议都将不胜感激。PHP缺少元组,这使得坐标处理起来很奇怪,而且我无法理解到底发生了什么,这对我一点帮助都没有。

编辑:一些修复使它在本地少于1秒。

我已经在OCaml中实现了一个解决方案。它将字典预编译为trie,并使用双字母序列频率来消除单词中永远不会出现的边,以进一步加快处理速度。

它在0.35ms内解决了示例板的问题(额外的6ms启动时间主要与将trie加载到内存有关)。

找到的解决方案:

["swami"; "emile"; "limbs"; "limbo"; "limes"; "amble"; "tubs"; "stub";
 "swam"; "semi"; "seam"; "awes"; "buts"; "bole"; "boil"; "west"; "east";
 "emil"; "lobs"; "limb"; "lime"; "lima"; "mesa"; "mews"; "mewl"; "maws";
 "milo"; "mile"; "awes"; "amie"; "axle"; "elma"; "fame"; "ubs"; "tux"; "tub";
 "twa"; "twa"; "stu"; "saw"; "sea"; "sew"; "sea"; "awe"; "awl"; "but"; "btu";
 "box"; "bmw"; "was"; "wax"; "oil"; "lox"; "lob"; "leo"; "lei"; "lie"; "mes";
 "mew"; "mae"; "maw"; "max"; "mil"; "mix"; "awe"; "awl"; "elm"; "eli"; "fax"]