两个对象。assign和Object spread只做浅合并。

这个问题的一个例子:

// No object nesting
const x = { a: 1 }
const y = { b: 1 }
const z = { ...x, ...y } // { a: 1, b: 1 }

输出是您所期望的。然而,如果我尝试这样做:

// Object nesting
const x = { a: { a: 1 } }
const y = { a: { b: 1 } }
const z = { ...x, ...y } // { a: { b: 1 } }

而不是

{ a: { a: 1, b: 1 } }

你得到

{ a: { b: 1 } }

X被完全覆盖,因为扩展语法只覆盖了一层。这与Object.assign()相同。

有办法做到这一点吗?


当前回答

有人知道深度合并在ES6/ES7规范中存在吗?

对象。赋值文档建议它不做深度克隆。

其他回答

如果您想合并多个普通对象(不要修改输入对象)。基于对象。分配polyfill

function isPlainObject(a) { return (!!a) && (a.constructor === Object); } function merge(target) { let to = Object.assign({}, target); for (let index = 1; index < arguments.length; index++) { let nextSource = arguments[index]; if (nextSource !== null && nextSource !== undefined) { for (let nextKey in nextSource) { // Avoid bugs when hasOwnProperty is shadowed if (Object.prototype.hasOwnProperty.call(nextSource, nextKey)) { if (isPlainObject(to[nextKey]) && isPlainObject(nextSource[nextKey])) { to[nextKey] = merge(to[nextKey], nextSource[nextKey]); } else { to[nextKey] = nextSource[nextKey]; } } } } } return to; } // Usage var obj1 = { a: 1, b: { x: 2, y: { t: 3, u: 4 } }, c: "hi" }; var obj2 = { b: { x: 200, y: { u: 4000, v: 5000 } } }; var obj3 = { c: "hello" }; console.log("result", merge(obj1, obj2, obj3)); console.log("obj1", obj1); console.log("obj2", obj2); console.log("obj3", obj3);

如果你想合并有限的深度

function isPlainObject(a) { return (!!a) && (a.constructor === Object); } function merge(target) { let to = Object.assign({}, target); const hasDepth = arguments.length > 2 && typeof arguments[arguments.length - 1] === 'number'; const depth = hasDepth ? arguments[arguments.length - 1] : Infinity; const lastObjectIndex = hasDepth ? arguments.length - 2 : arguments.length - 1; for (let index = 1; index <= lastObjectIndex; index++) { let nextSource = arguments[index]; if (nextSource !== null && nextSource !== undefined) { for (let nextKey in nextSource) { // Avoid bugs when hasOwnProperty is shadowed if (Object.prototype.hasOwnProperty.call(nextSource, nextKey)) { if (depth > 0 && isPlainObject(to[nextKey]) && isPlainObject(nextSource[nextKey])) { to[nextKey] = merge(to[nextKey], nextSource[nextKey], depth - 1); } else { to[nextKey] = nextSource[nextKey]; } } } } } return to; } // Usage var obj1 = { a: 1, b: { x: 2, y: { t: 3, u: 4, z: {zzz: 100} } }, c: "hi" }; var obj2 = { b: { y: { u: 4000, v: 5000, z: {} } } }; var obj3 = { c: "hello" }; console.log('deep 0', merge(obj1, obj2, obj3, 0)); console.log('deep 1', merge(obj1, obj2, obj3, 1)); console.log('deep 2', merge(obj1, obj2, obj3, 2)); console.log('deep 2', merge(obj1, obj2, obj3, 4));

我不喜欢现有的解决方案。所以,我开始写我自己的。

Object.prototype.merge = function(object) {
    for (const key in object) {
        if (object.hasOwnProperty(key)) {
            if (typeof this[key] === "object" && typeof object[key] === "object") {
                this[key].merge(object[key]);

                continue;
            }

            this[key] = object[key];
        }
    }

    return this;
}

我希望这能帮助那些努力理解正在发生的事情的人。我在这里看到了很多无意义的变量。

谢谢

ES5的一个简单解决方案(覆盖现有值):

function merge(current, update) { Object.keys(update).forEach(function(key) { // if update[key] exist, and it's not a string or array, // we go in one level deeper if (current.hasOwnProperty(key) && typeof current[key] === 'object' && !(current[key] instanceof Array)) { merge(current[key], update[key]); // if update[key] doesn't exist in current, or it's a string // or array, then assign/overwrite current[key] to update[key] } else { current[key] = update[key]; } }); return current; } var x = { a: { a: 1 } } var y = { a: { b: 1 } } console.log(merge(x, y));

我试着写一个对象。基于Object的pollyfill的assignDeep。在mdn上赋值。

(ES5)

Object.assignDeep = function (target, varArgs) { // .length of function is 2 'use strict'; if (target == null) { // TypeError if undefined or null throw new TypeError('Cannot convert undefined or null to object'); } var to = Object(target); for (var index = 1; index < arguments.length; index++) { var nextSource = arguments[index]; if (nextSource != null) { // Skip over if undefined or null for (var nextKey in nextSource) { // Avoid bugs when hasOwnProperty is shadowed if (Object.prototype.hasOwnProperty.call(nextSource, nextKey)) { if (typeof to[nextKey] === 'object' && to[nextKey] && typeof nextSource[nextKey] === 'object' && nextSource[nextKey]) { Object.assignDeep(to[nextKey], nextSource[nextKey]); } else { to[nextKey] = nextSource[nextKey]; } } } } } return to; }; console.log(Object.assignDeep({},{a:{b:{c:1,d:1}}},{a:{b:{c:2,e:2}}}))

如果你正在使用ImmutableJS,你可以使用mergeDeep:

fromJS(options).mergeDeep(options2).toJS();