当我试图从一个片段导航到另一个片段时,我遇到了新的Android导航架构组件的问题,我得到了这个奇怪的错误:
java.lang.IllegalArgumentException: navigation destination XXX
is unknown to this NavController
其他导航都很好,除了这个。
我使用Fragment的findNavController()函数来访问NavController。
任何帮助都将不胜感激。
当我试图从一个片段导航到另一个片段时,我遇到了新的Android导航架构组件的问题,我得到了这个奇怪的错误:
java.lang.IllegalArgumentException: navigation destination XXX
is unknown to this NavController
其他导航都很好,除了这个。
我使用Fragment的findNavController()函数来访问NavController。
任何帮助都将不胜感激。
当前回答
I caught this exception after some renames of classes. For example: I had classes called FragmentA with @+is/fragment_a in navigation graph and FragmentB with @+id/fragment_b. Then I deleted FragmentA and renamed FragmentB to FragmentA. So after that node of FragmentA still stayed in navigation graph, and android:name of FragmentB's node was renamed path.to.FragmentA. I had two nodes with the same android:name and different android:id, and the action I needed were defined on node of removed class.
其他回答
我写了这个扩展
fun Fragment.navigateAction(action: NavDirections) {
val navController = this.findNavController()
if (navController.currentDestination?.getAction(action.actionId) == null) {
return
} else {
navController.navigate(action)
}
}
在我的情况下,我通过验证所有导航操作都正确地管理到各自的图形中,并更新了设备后退按钮的代码来解决这个问题,如下所示:
onBackPressedDispatcher.addCallback(this /* lifecycle owner */, object : OnBackPressedCallback(true) {
override fun handleOnBackPressed() {
// Back is pressed... Finishing the activity
if (navHostFragment.childFragmentManager.backStackEntryCount == 0) {
// First fragment is open, backstack is empty
finish()
} else {
navHostFragment.navController.popBackStack()
}
}
})
更新到@AlexNuts回答以支持导航到嵌套图。当一个动作使用一个嵌套图作为目的地时,如下所示:
<action
android:id="@+id/action_foo"
android:destination="@id/nested_graph"/>
此操作的目的ID不能与当前目的进行比较,因为当前目的不能是图形。必须解析嵌套图的起始目的地。
fun NavController.navigateSafe(directions: NavDirections) {
// Get action by ID. If action doesn't exist on current node, return.
val action = (currentDestination ?: graph).getAction(directions.actionId) ?: return
var destId = action.destinationId
val dest = graph.findNode(destId)
if (dest is NavGraph) {
// Action destination is a nested graph, which isn't a real destination.
// The real destination is the start destination of that graph so resolve it.
destId = dest.startDestination
}
if (currentDestination?.id != destId) {
navigate(directions)
}
}
然而,这将防止导航到同一目的地两次,这是有时需要的。为了允许这一点,你可以添加一个检查action.navOptions?. shouldlaunchsingletop(),并添加app:launchSingleTop="true"的动作,你不希望重复的目的地。
还有另一种解决快速点击导航崩溃问题的方法:
fun NavController.doIfCurrentDestination(@IdRes destination: Int, action: NavController.()-> Unit){
if(this.currentDestination?.id == destination){action()}
}
然后像这样使用:
findNavController().doIfCurrentDestination(R.id.my_destination){ navigate(...) }
这种解决方案的好处是,您可以轻松地用您已经使用的任何签名包装任何现有的naagte()调用,而不需要进行一百万次重载
您可以在导航控制器的当前目标中检查请求的操作。
更新 为安全导航增加了全局操作的使用。
fun NavController.navigateSafe(
@IdRes resId: Int,
args: Bundle? = null,
navOptions: NavOptions? = null,
navExtras: Navigator.Extras? = null
) {
val action = currentDestination?.getAction(resId) ?: graph.getAction(resId)
if (action != null && currentDestination?.id != action.destinationId) {
navigate(resId, args, navOptions, navExtras)
}
}