I caught this exception after some renames of classes. For example: I had classes called FragmentA with @+is/fragment_a in navigation graph and FragmentB with @+id/fragment_b. Then I deleted FragmentA and renamed FragmentB to FragmentA. So after that node of FragmentA still stayed in navigation graph, and android:name of FragmentB's node was renamed path.to.FragmentA. I had two nodes with the same android:name and different android:id, and the action I needed were defined on node of removed class.

我写了这个扩展

fun Fragment.navigateAction(action: NavDirections) {
    val navController = this.findNavController()
    if (navController.currentDestination?.getAction(action.actionId) == null) {
        return
    } else {
        navController.navigate(action)
    }
}

在我的情况下，我通过验证所有导航操作都正确地管理到各自的图形中，并更新了设备后退按钮的代码来解决这个问题，如下所示:

 onBackPressedDispatcher.addCallback(this /* lifecycle owner */, object : OnBackPressedCallback(true) {
        override fun handleOnBackPressed() {
            // Back is pressed... Finishing the activity
            if (navHostFragment.childFragmentManager.backStackEntryCount == 0) {
                // First fragment is open, backstack is empty
               finish()
            } else {
                navHostFragment.navController.popBackStack()
            }
        }
    })

更新到@AlexNuts回答以支持导航到嵌套图。当一个动作使用一个嵌套图作为目的地时，如下所示:

<action
    android:id="@+id/action_foo"
    android:destination="@id/nested_graph"/>

此操作的目的ID不能与当前目的进行比较，因为当前目的不能是图形。必须解析嵌套图的起始目的地。

fun NavController.navigateSafe(directions: NavDirections) {
    // Get action by ID. If action doesn't exist on current node, return.
    val action = (currentDestination ?: graph).getAction(directions.actionId) ?: return
    var destId = action.destinationId
    val dest = graph.findNode(destId)
    if (dest is NavGraph) {
        // Action destination is a nested graph, which isn't a real destination.
        // The real destination is the start destination of that graph so resolve it.
        destId = dest.startDestination
    }
    if (currentDestination?.id != destId) {
        navigate(directions)
    }
}

然而，这将防止导航到同一目的地两次，这是有时需要的。为了允许这一点，你可以添加一个检查action.navOptions?. shouldlaunchsingletop()，并添加app:launchSingleTop="true"的动作，你不希望重复的目的地。

还有另一种解决快速点击导航崩溃问题的方法:

fun NavController.doIfCurrentDestination(@IdRes destination: Int, action: NavController.()-> Unit){
    if(this.currentDestination?.id == destination){action()}
}

然后像这样使用:

findNavController().doIfCurrentDestination(R.id.my_destination){ navigate(...) }

这种解决方案的好处是，您可以轻松地用您已经使用的任何签名包装任何现有的naagte()调用，而不需要进行一百万次重载

您可以在导航控制器的当前目标中检查请求的操作。

更新 为安全导航增加了全局操作的使用。

fun NavController.navigateSafe(
        @IdRes resId: Int,
        args: Bundle? = null,
        navOptions: NavOptions? = null,
        navExtras: Navigator.Extras? = null
) {
    val action = currentDestination?.getAction(resId) ?: graph.getAction(resId)
    if (action != null && currentDestination?.id != action.destinationId) {
        navigate(resId, args, navOptions, navExtras)
    }
}