public string GenerateToken(int length)
{
    using (RNGCryptoServiceProvider cryptRNG = new RNGCryptoServiceProvider())
    {
        byte[] tokenBuffer = new byte[length];
        cryptRNG.GetBytes(tokenBuffer);
        return Convert.ToBase64String(tokenBuffer);
    }
}

(你也可以让这个方法所在的类实现IDisposable，持有对RNGCryptoServiceProvider的引用，并正确地处理它，以避免重复实例化它。)

It's been noted that as this returns a base-64 string, the output length is always a multiple of 4, with the extra space using = as a padding character. The length parameter specifies the length of the byte buffer, not the output string (and is therefore perhaps not the best name for that parameter, now I think about it). This controls how many bytes of entropy the password will have. However, because base-64 uses a 4-character block to encode each 3 bytes of input, if you ask for a length that's not a multiple of 3, there will be some extra "space", and it'll use = to fill the extra.

If you don't like using base-64 strings for any reason, you can replace the Convert.ToBase64String() call with either a conversion to regular string, or with any of the Encoding methods; eg. Encoding.UTF8.GetString(tokenBuffer) - just make sure you pick a character set that can represent the full range of values coming out of the RNG, and that produces characters that are compatible with wherever you're sending or storing this. Using Unicode, for example, tends to give a lot of Chinese characters. Using base-64 guarantees a widely-compatible set of characters, and the characteristics of such a string shouldn't make it any less secure as long as you use a decent hashing algorithm.

我使用此代码生成密码与字母，数字和非字母数字字符的平衡组合。

public static string GeneratePassword(int Length, int NonAlphaNumericChars)
    {
        string allowedChars = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ0123456789";
        string allowedNonAlphaNum = "!@#$%^&*()_-+=[{]};:<>|./?";
        string pass = "";
        Random rd = new Random(DateTime.Now.Millisecond);
        for (int i = 0; i < Length; i++)
        {
            if (rd.Next(1) > 0 && NonAlphaNumericChars > 0)
            {
                pass += allowedNonAlphaNum[rd.Next(allowedNonAlphaNum.Length)];
                NonAlphaNumericChars--;
            }
            else
            {
                pass += allowedChars[rd.Next(allowedChars.Length)];
            }
        }
        return pass;
    }

我创建的这个类使用RNGCryptoServiceProvider，它是灵活的。例子:

var generator = new PasswordGenerator(minimumLengthPassword: 8,
                                      maximumLengthPassword: 15,
                                      minimumUpperCaseChars: 2,
                                      minimumNumericChars: 3,
                                      minimumSpecialChars: 2);
string password = generator.Generate();

由于Random是不安全的，RNGCryptoServiceProvider是过时的，我最终这样做:

  // possible characters that password can have
  private const string passChars =
       "ABCDEFGHIJKLMNOPQRSTUVWXYZ" +
       "abcdefghijklmnopqrstuvwxyz" +
       "0123456789" +
       "!@#$%.-_"
       ;

    public static string GetRandomPassword(int length)
    {
        char[] p = new char[length];
        for (int i = 0; i < length; i++)
            p[i] = passChars[RandomNumberGenerator.GetInt32(0, passChars.Length)];
        return new string(p);
    }

我喜欢生成密码，就像生成软件密钥一样。您应该从遵循良好实践的字符数组中进行选择。采用@Radu094回答的内容并修改它以遵循良好的实践。不要把每个字母都放在字符数组中。有些信在电话里更难读懂。

您还应该考虑对生成的密码使用校验和，以确保它是由您生成的。实现这一点的一个好方法是使用LUHN算法。

我不喜欢Membership.GeneratePassword()创建的密码，因为它们太丑了，有太多特殊字符。

这段代码生成一个10位不太难看的密码。

string password = Guid.NewGuid().ToString("N").ToLower()
                      .Replace("1", "").Replace("o", "").Replace("0","")
                      .Substring(0,10);

当然，我可以使用一个Regex来做所有的替换，但这是更具可读性和可维护性的IMO。