当我们网站上的用户丢失密码并转到丢失密码页面时，我们需要给他一个新的临时密码。我并不介意这有多随机，或者它是否符合所有“所需的”强密码规则，我想做的只是给他们一个他们以后可以更改的密码。
该应用程序是用c#编写的Web应用程序。所以我想刻薄一点，走一条简单的路线，用Guid的一部分。即。
Guid.NewGuid().ToString("d").Substring(1,8)
Suggesstions吗?想法吗?
当前回答
灵感来自@kitsu的回答。但使用RandomNumberGenerator而不是Random或RNGCryptoServiceProvider(在。net 6中已弃用)，并添加了一些特殊字符。
可选参数，用于排除在使用System.Text.Json.JsonSerializer.Serialize时将转义的字符—例如&，它转义为\u0026—以便您可以保证序列化字符串的长度与密码的长度匹配。
适用于。net Core 3.0及以上版本。
public static class PasswordGenerator
{
const string lower = "abcdefghijklmnopqrstuvwxyz";
const string upper = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const string number = "1234567890";
const string special = "!@#$%^&*()[]{},.:`~_-=+"; // excludes problematic characters like ;'"/\
const string specialJsonSafe = "!@#$%^*()[]{},.:~_-="; // excludes problematic characters like ;'"/\ and &`+
const int lowerLength = 26; // lower.Length
const int upperLength = 26; // upper.Length;
const int numberLength = 10; // number.Length;
const int specialLength = 23; // special.Length;
const int specialJsonSafeLength = 20; // specialJsonSafe.Length;
public static string Generate(int length = 96, bool jsonSafeSpecialCharactersOnly = false)
{
Span<char> result = length < 1024 ? stackalloc char[length] : new char[length].AsSpan();
for (int i = 0; i < length; ++i)
{
switch (RandomNumberGenerator.GetInt32(4))
{
case 0:
result[i] = lower[RandomNumberGenerator.GetInt32(0, lowerLength)];
break;
case 1:
result[i] = upper[RandomNumberGenerator.GetInt32(0, upperLength)];
break;
case 2:
result[i] = number[RandomNumberGenerator.GetInt32(0, numberLength)];
break;
case 3:
if (jsonSafeSpecialCharactersOnly)
{
result[i] = specialJsonSafe[RandomNumberGenerator.GetInt32(0, specialJsonSafeLength)];
}
else
{
result[i] = special[RandomNumberGenerator.GetInt32(0, specialLength)];
}
break;
}
}
return result.ToString();
}
}
其他回答
我创建的这个类使用RNGCryptoServiceProvider，它是灵活的。例子:
var generator = new PasswordGenerator(minimumLengthPassword: 8,
maximumLengthPassword: 15,
minimumUpperCaseChars: 2,
minimumNumericChars: 3,
minimumSpecialChars: 2);
string password = generator.Generate();
灵感来自@kitsu的回答。但使用RandomNumberGenerator而不是Random或RNGCryptoServiceProvider(在。net 6中已弃用)，并添加了一些特殊字符。
可选参数，用于排除在使用System.Text.Json.JsonSerializer.Serialize时将转义的字符—例如&，它转义为\u0026—以便您可以保证序列化字符串的长度与密码的长度匹配。
适用于。net Core 3.0及以上版本。
public static class PasswordGenerator
{
const string lower = "abcdefghijklmnopqrstuvwxyz";
const string upper = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const string number = "1234567890";
const string special = "!@#$%^&*()[]{},.:`~_-=+"; // excludes problematic characters like ;'"/\
const string specialJsonSafe = "!@#$%^*()[]{},.:~_-="; // excludes problematic characters like ;'"/\ and &`+
const int lowerLength = 26; // lower.Length
const int upperLength = 26; // upper.Length;
const int numberLength = 10; // number.Length;
const int specialLength = 23; // special.Length;
const int specialJsonSafeLength = 20; // specialJsonSafe.Length;
public static string Generate(int length = 96, bool jsonSafeSpecialCharactersOnly = false)
{
Span<char> result = length < 1024 ? stackalloc char[length] : new char[length].AsSpan();
for (int i = 0; i < length; ++i)
{
switch (RandomNumberGenerator.GetInt32(4))
{
case 0:
result[i] = lower[RandomNumberGenerator.GetInt32(0, lowerLength)];
break;
case 1:
result[i] = upper[RandomNumberGenerator.GetInt32(0, upperLength)];
break;
case 2:
result[i] = number[RandomNumberGenerator.GetInt32(0, numberLength)];
break;
case 3:
if (jsonSafeSpecialCharactersOnly)
{
result[i] = specialJsonSafe[RandomNumberGenerator.GetInt32(0, specialJsonSafeLength)];
}
else
{
result[i] = special[RandomNumberGenerator.GetInt32(0, specialLength)];
}
break;
}
}
return result.ToString();
}
}
这是我快速拼凑的东西。
public string GeneratePassword(int len)
{
string res = "";
Random rnd = new Random();
while (res.Length < len) res += (new Func<Random, string>((r) => {
char c = (char)((r.Next(123) * DateTime.Now.Millisecond % 123));
return (Char.IsLetterOrDigit(c)) ? c.ToString() : "";
}))(rnd);
return res;
}
public string Sifre_Uret(int boy, int noalfa)
{
// 01.03.2016
// Genel amaçlı şifre üretme fonksiyonu
//Fonskiyon 128 den büyük olmasına izin vermiyor.
if (boy > 128 ) { boy = 128; }
if (noalfa > 128) { noalfa = 128; }
if (noalfa > boy) { noalfa = boy; }
string passch = System.Web.Security.Membership.GeneratePassword(boy, noalfa);
//URL encoding ve Url Pass + json sorunu yaratabilecekler pass ediliyor.
//Microsoft Garanti etmiyor. Alfa Sayısallar Olabiliyorimiş . !@#$%^&*()_-+=[{]};:<>|./?.
//https://msdn.microsoft.com/tr-tr/library/system.web.security.membership.generatepassword(v=vs.110).aspx
//URL ve Json ajax lar için filtreleme
passch = passch.Replace(":", "z");
passch = passch.Replace(";", "W");
passch = passch.Replace("'", "t");
passch = passch.Replace("\"", "r");
passch = passch.Replace("/", "+");
passch = passch.Replace("\\", "e");
passch = passch.Replace("?", "9");
passch = passch.Replace("&", "8");
passch = passch.Replace("#", "D");
passch = passch.Replace("%", "u");
passch = passch.Replace("=", "4");
passch = passch.Replace("~", "1");
passch = passch.Replace("[", "2");
passch = passch.Replace("]", "3");
passch = passch.Replace("{", "g");
passch = passch.Replace("}", "J");
//passch = passch.Replace("(", "6");
//passch = passch.Replace(")", "0");
//passch = passch.Replace("|", "p");
//passch = passch.Replace("@", "4");
//passch = passch.Replace("!", "u");
//passch = passch.Replace("$", "Z");
//passch = passch.Replace("*", "5");
//passch = passch.Replace("_", "a");
passch = passch.Replace(",", "V");
passch = passch.Replace(".", "N");
passch = passch.Replace("+", "w");
passch = passch.Replace("-", "7");
return passch;
}
这个包允许你生成一个随机密码，同时流利地指出它应该包含哪些字符(如果需要):
https://github.com/prjseal/PasswordGenerator/
例子:
var pwd = new Password().IncludeLowercase().IncludeUppercase().IncludeSpecial();
var password = pwd.Next();
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