当我们网站上的用户丢失密码并转到丢失密码页面时,我们需要给他一个新的临时密码。我并不介意这有多随机,或者它是否符合所有“所需的”强密码规则,我想做的只是给他们一个他们以后可以更改的密码。
该应用程序是用c#编写的Web应用程序。所以我想刻薄一点,走一条简单的路线,用Guid的一部分。即。
Guid.NewGuid().ToString("d").Substring(1,8)
Suggesstions吗?想法吗?
当我们网站上的用户丢失密码并转到丢失密码页面时,我们需要给他一个新的临时密码。我并不介意这有多随机,或者它是否符合所有“所需的”强密码规则,我想做的只是给他们一个他们以后可以更改的密码。
该应用程序是用c#编写的Web应用程序。所以我想刻薄一点,走一条简单的路线,用Guid的一部分。即。
Guid.NewGuid().ToString("d").Substring(1,8)
Suggesstions吗?想法吗?
当前回答
在我的网站上,我使用这个方法:
//Symb array
private const string _SymbolsAll = "~`!@#$%^&*()_+=-\\|[{]}'\";:/?.>,<";
//Random symb
public string GetSymbol(int Length)
{
Random Rand = new Random(DateTime.Now.Millisecond);
StringBuilder result = new StringBuilder();
for (int i = 0; i < Length; i++)
result.Append(_SymbolsAll[Rand.Next(0, _SymbolsAll.Length)]);
return result.ToString();
}
编辑字符串_SymbolsAll为你的数组列表。
其他回答
我一直对KeePass内置的密码生成器非常满意。因为KeePass是一个。net程序,而且是开源的,所以我决定深入研究一下它的代码。最后,我只是在我的项目中引用了标准应用程序安装中提供的KeePass.exe副本,并编写了下面的代码。多亏了KeePass,你可以看到它是多么灵活。你可以指定长度,包含/不包含哪些字符,等等。
using KeePassLib.Cryptography.PasswordGenerator;
using KeePassLib.Security;
public static string GeneratePassword(int passwordLength, bool lowerCase, bool upperCase, bool digits,
bool punctuation, bool brackets, bool specialAscii, bool excludeLookAlike)
{
var ps = new ProtectedString();
var profile = new PwProfile();
profile.CharSet = new PwCharSet();
profile.CharSet.Clear();
if (lowerCase)
profile.CharSet.AddCharSet('l');
if(upperCase)
profile.CharSet.AddCharSet('u');
if(digits)
profile.CharSet.AddCharSet('d');
if (punctuation)
profile.CharSet.AddCharSet('p');
if (brackets)
profile.CharSet.AddCharSet('b');
if (specialAscii)
profile.CharSet.AddCharSet('s');
profile.ExcludeLookAlike = excludeLookAlike;
profile.Length = (uint)passwordLength;
profile.NoRepeatingCharacters = true;
KeePassLib.Cryptography.PasswordGenerator.PwGenerator.Generate(out ps, profile, null, _pool);
return ps.ReadString();
}
由于Random是不安全的,RNGCryptoServiceProvider是过时的,我最终这样做:
// possible characters that password can have
private const string passChars =
"ABCDEFGHIJKLMNOPQRSTUVWXYZ" +
"abcdefghijklmnopqrstuvwxyz" +
"0123456789" +
"!@#$%.-_"
;
public static string GetRandomPassword(int length)
{
char[] p = new char[length];
for (int i = 0; i < length; i++)
p[i] = passChars[RandomNumberGenerator.GetInt32(0, passChars.Length)];
return new string(p);
}
public string GenerateToken(int length)
{
using (RNGCryptoServiceProvider cryptRNG = new RNGCryptoServiceProvider())
{
byte[] tokenBuffer = new byte[length];
cryptRNG.GetBytes(tokenBuffer);
return Convert.ToBase64String(tokenBuffer);
}
}
(你也可以让这个方法所在的类实现IDisposable,持有对RNGCryptoServiceProvider的引用,并正确地处理它,以避免重复实例化它。)
It's been noted that as this returns a base-64 string, the output length is always a multiple of 4, with the extra space using = as a padding character. The length parameter specifies the length of the byte buffer, not the output string (and is therefore perhaps not the best name for that parameter, now I think about it). This controls how many bytes of entropy the password will have. However, because base-64 uses a 4-character block to encode each 3 bytes of input, if you ask for a length that's not a multiple of 3, there will be some extra "space", and it'll use = to fill the extra.
If you don't like using base-64 strings for any reason, you can replace the Convert.ToBase64String() call with either a conversion to regular string, or with any of the Encoding methods; eg. Encoding.UTF8.GetString(tokenBuffer) - just make sure you pick a character set that can represent the full range of values coming out of the RNG, and that produces characters that are compatible with wherever you're sending or storing this. Using Unicode, for example, tends to give a lot of Chinese characters. Using base-64 guarantees a widely-compatible set of characters, and the characteristics of such a string shouldn't make it any less secure as long as you use a decent hashing algorithm.
我创建的这个方法类似于会员资格提供程序中可用的方法。如果你不想在某些应用程序中添加web引用,这是很有用的。
效果很好。
public static string GeneratePassword(int Length, int NonAlphaNumericChars)
{
string allowedChars = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ0123456789";
string allowedNonAlphaNum = "!@#$%^&*()_-+=[{]};:<>|./?";
Random rd = new Random();
if (NonAlphaNumericChars > Length || Length <= 0 || NonAlphaNumericChars < 0)
throw new ArgumentOutOfRangeException();
char[] pass = new char[Length];
int[] pos = new int[Length];
int i = 0, j = 0, temp = 0;
bool flag = false;
//Random the position values of the pos array for the string Pass
while (i < Length - 1)
{
j = 0;
flag = false;
temp = rd.Next(0, Length);
for (j = 0; j < Length; j++)
if (temp == pos[j])
{
flag = true;
j = Length;
}
if (!flag)
{
pos[i] = temp;
i++;
}
}
//Random the AlphaNumericChars
for (i = 0; i < Length - NonAlphaNumericChars; i++)
pass[i] = allowedChars[rd.Next(0, allowedChars.Length)];
//Random the NonAlphaNumericChars
for (i = Length - NonAlphaNumericChars; i < Length; i++)
pass[i] = allowedNonAlphaNum[rd.Next(0, allowedNonAlphaNum.Length)];
//Set the sorted array values by the pos array for the rigth posistion
char[] sorted = new char[Length];
for (i = 0; i < Length; i++)
sorted[i] = pass[pos[i]];
string Pass = new String(sorted);
return Pass;
}
Generate random password of specified length with
- Special characters
- Number
- Lowecase
- Uppercase
public static string CreatePassword(int length = 12)
{
const string lower = "abcdefghijklmnopqrstuvwxyz";
const string upper = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const string number = "1234567890";
const string special = "!@#$%^&*";
var middle = length / 2;
StringBuilder res = new StringBuilder();
Random rnd = new Random();
while (0 < length--)
{
if (middle == length)
{
res.Append(number[rnd.Next(number.Length)]);
}
else if (middle - 1 == length)
{
res.Append(special[rnd.Next(special.Length)]);
}
else
{
if (length % 2 == 0)
{
res.Append(lower[rnd.Next(lower.Length)]);
}
else
{
res.Append(upper[rnd.Next(upper.Length)]);
}
}
}
return res.ToString();
}