在iOS 7中,苹果增加了一个新的默认导航行为。你可以从屏幕的左边缘滑动回到导航堆栈。但在我的应用程序中,这种行为与我的自定义左侧菜单冲突。那么,是否有可能在UINavigationController中禁用这个新手势?


当前回答

只需从NavigationController中删除手势识别器。在iOS 8中工作。

if ([self.navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)])
    [self.navigationController.view removeGestureRecognizer:self.navigationController.interactivePopGestureRecognizer];

其他回答

对于Swift 4,这是有效的:

class MyViewController: UIViewController, UIGestureRecognizerDelegate {

    override func viewDidLoad() {
        super.viewDidLoad()

        self.navigationController?.interactivePopGestureRecognizer?.gesture.delegate = self
    }

    override func viewWillAppear(_ animated: Bool) {
        super.viewWillAppear(true)

        self.navigationController?.interactivePopGestureRecognizer?.gesture.isEnabled = false
    }

}

这是Swift 3的方式

对我有用

    self.navigationController?.interactivePopGestureRecognizer?.isEnabled = false

我找到了一个解决方案:

objective - c:

if ([self.navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
    self.navigationController.interactivePopGestureRecognizer.enabled = NO;
}

斯威夫特3 +: self.navigationController?.interactivePopGestureRecognizer?.isEnabled = false

我的方法。一个手势识别器来统治它们:

class DisabledGestureViewController: UIViewController: UIGestureRecognizerDelegate {
    override func viewDidLoad() {
        super.viewDidLoad()
        navigationController!.interactivePopGestureRecognizer!.delegate = self
    }

    func gestureRecognizerShouldBegin(gestureRecognizer: UIGestureRecognizer) -> Bool {
        // Prevent going back to the previous view
        return !(navigationController!.topViewController is DisabledGestureViewController)
    }
}

重要:不要在导航堆栈的任何地方重置委托:navigationController!.interactivePopGestureRecognizer!.delegate = nil

它适用于我的ios 10和更高版本:

- (void)viewWillAppear:(BOOL)animated {
    if ([self.navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
        self.navigationController.interactivePopGestureRecognizer.enabled = NO;
    }

}

它在viewDidLoad()方法上不起作用。