我也有同样的问题，然后想出了一个很好用的函数:

每个条目的键和值都是字符串，并且相同。 每个条目的值都是从键派生出来的。(即。“不要重复你自己”，不像字符串值的常规枚举) TypeScript类型成熟且正确。(防止拼写错误) 还有一种简单的方法可以让TS自动完成您的选项。(如。打字MyEnum。，并立即看到可用的选项) 还有其他一些优点。(见答案底部)

效用函数:

export function createStringEnum<T extends {[key: string]: 1}>(keysObj: T) {
    const optionsObj = {} as {
        [K in keyof T]: keyof T
        // alternative; gives narrower type for MyEnum.XXX
        //[K in keyof T]: K
    };
    const keys = Object.keys(keysObj) as Array<keyof T>;
    const values = keys; // could also check for string value-overrides on keysObj
    for (const key of keys) {
        optionsObj[key] = key;
    }
    return [optionsObj, values] as const;
}

用法:

// if the "Fruit_values" var isn't useful to you, just omit it
export const [Fruit, Fruit_values] = createStringEnum({
    apple: 1,
    pear: 1,
});
export type Fruit = keyof typeof Fruit; // "apple" | "pear"
//export type Fruit = typeof Fruit_values[number]; // alternative

// correct usage (with correct types)
let fruit1 = Fruit.apple; // fruit1 == "apple"
fruit1 = Fruit.pear; // assigning a new fruit also works
let fruit2 = Fruit_values[0]; // fruit2 == "apple"

// incorrect usage (should error)
let fruit3 = Fruit.tire; // errors
let fruit4: Fruit = "mirror"; // errors

现在有人可能会问，这个“基于字符串的enum”比只使用:

type Fruit = "apple" | "pear";

有几个优点:

Auto-complete is a bit nicer (imo). For example, if you type let fruit = Fruit., Typescript will immediately list the exact set of options available. With string literals, you need to define your type explicitly, eg. let fruit: Fruit = , and then press ctrl+space afterward. (and even that results in unrelated autocomplete options being shown below the valid ones) The TSDoc metadata/description for an option is carried over to the MyEnum.XXX fields! This is useful for providing additional information about the different options. For example: You can access the list of options at runtime (eg. Fruit_values, or manually with Object.values(Fruit)). With the type Fruit = ... approach, there is no built-in way to do this, which cuts off a number of use-cases. (for example, I use the runtime values for constructing json-schemas)

Typescript中的字符串枚举:

字符串枚举是一个类似的概念，但是有一些细微的运行时差异，如下文所述。在string enum中，每个成员必须用string字面值或另一个string enum成员常量初始化。

enum Direction {
  Up = "UP",
  Down = "DOWN",
  Left = "LEFT",
  Right = "RIGHT",
}

虽然字符串枚举没有自动递增的行为，但字符串枚举的好处是它们很好地“序列化”。换句话说，如果你正在调试并且必须读取一个数值enum的运行时值，这个值通常是不透明的——它本身没有传达任何有用的含义(尽管反向映射通常会有所帮助)，字符串enum允许你在代码运行时给出一个有意义且可读的值，与枚举成员本身的名称无关。 参考链接如下。

在这里输入链接描述

@basarat的回答很棒。下面是一个你可以使用的简化但有点扩展的例子:

export type TMyEnumType = 'value1'|'value2';

export class MyEnumType {
    static VALUE1: TMyEnumType = 'value1';
    static VALUE2: TMyEnumType = 'value2';
}

console.log(MyEnumType.VALUE1); // 'value1'

const variable = MyEnumType.VALUE2; // it has the string value 'value2'

switch (variable) {
    case MyEnumType.VALUE1:
        // code...

    case MyEnumType.VALUE2:
        // code...
}

在最新版本(1.0RC)的TypeScript中，你可以像这样使用枚举:

enum States {
    New,
    Active,
    Disabled
} 

// this will show message '0' which is number representation of enum member
alert(States.Active); 

// this will show message 'Disabled' as string representation of enum member
alert(States[States.Disabled]);

更新1

要从string value中获取enum成员的number值，你可以使用这个:

var str = "Active";
// this will show message '1'
alert(States[str]);

更新2

在最新的TypeScript 2.4中，引入了字符串enum，如下所示:

enum ActionType {
    AddUser = "ADD_USER",
    DeleteUser = "DELETE_USER",
    RenameUser = "RENAME_USER",

    // Aliases
    RemoveUser = DeleteUser,
}

有关TypeScript 2.4的更多信息，请阅读MSDN上的博客。

TypeScript 2 + 4。

你现在可以直接将字符串值分配给enum成员:

enum Season {
    Winter = "winter",
    Spring = "spring",
    Summer = "summer",
    Fall = "fall"
}

更多信息见#15486。

打印稿1.8 +

在TypeScript 1.8+中，你可以创建一个字符串文字类型来定义类型，并为值列表创建一个同名的对象。它模仿字符串enum的预期行为。

这里有一个例子:

type MyStringEnum = "member1" | "member2";

const MyStringEnum = {
    Member1: "member1" as MyStringEnum,
    Member2: "member2" as MyStringEnum
};

它将像字符串enum一样工作:

// implicit typing example
let myVariable = MyStringEnum.Member1; // ok
myVariable = "member2";                // ok
myVariable = "some other value";       // error, desired

// explict typing example
let myExplicitlyTypedVariable: MyStringEnum;
myExplicitlyTypedVariable = MyStringEnum.Member1; // ok
myExplicitlyTypedVariable = "member2";            // ok
myExplicitlyTypedVariable = "some other value";   // error, desired

确保输入对象中的所有字符串!如果不这样做，那么在上面的第一个例子中，变量将不会隐式地类型化为MyStringEnum。

最近在使用TypeScript 1.0.1时遇到了这个问题，并以这种方式解决了:

enum IEvents {
        /** A click on a product or product link for one or more products. */
        CLICK,
        /** A view of product details. */
        DETAIL,
        /** Adding one or more products to a shopping cart. */
        ADD,
        /** Remove one or more products from a shopping cart. */
        REMOVE,
        /** Initiating the checkout process for one or more products. */
        CHECKOUT,
        /** Sending the option value for a given checkout step. */
        CHECKOUT_OPTION,
        /** The sale of one or more products. */
        PURCHASE,
        /** The refund of one or more products. */
        REFUND,
        /** A click on an internal promotion. */
        PROMO_CLICK
}

var Events = [
        'click',
        'detail',
        'add',
        'remove',
        'checkout',
        'checkout_option',
        'purchase',
        'refund',
        'promo_click'
];

function stuff(event: IEvents):boolean {
        // event can now be only IEvents constants
        Events[event]; // event is actually a number that matches the index of the array
}
// stuff('click') won't work, it needs to be called using stuff(IEvents.CLICK)