Update my_table set my_field = CEILING((RAND(CAST(NEWID() AS varbinary)) * 10))

1到10之间的数字。

您需要为每一行调用RAND()。这里有一个很好的例子

https://web.archive.org/web/20090216200320/http://dotnet.org.za/calmyourself/archive/2007/04/13/sql-rand-trap-same-value-per-row.aspx

如果你想生成一个1到14之间的随机数。

SELECT CONVERT(int, RAND() * (14 - 1) + 1)

OR

SELECT ABS(CHECKSUM(NewId())) % (14 -1) + 1

如果你需要一个特定的随机数你可以使用递归CTE:

;WITH A AS (
        SELECT 1 X, RAND() R
    UNION ALL
        SELECT X + 1, RAND(R*100000) --Change the seed
        FROM A
        WHERE X < 1000 --How many random numbers you need
    )
SELECT
    X
    , RAND_BETWEEN_1_AND_14 = FLOOR(R * 14 + 1)
FROM A
OPTION (MAXRECURSION 0) --If you need more than 100 numbers

尝试在RAND中使用种子值(seedInt)。RAND()每条语句只执行一次，这就是为什么每次都看到相同的数字。

select ABS(CAST(CAST(NEWID() AS VARBINARY) AS INT)) as [Randomizer]

一直对我有效吗