另一种方法是使用神奇的__set方法并将枚举设为私有。

e.g.

class Human{
    private $gender;

    public function __set($key, $value){
        if($key == 'day' && !in_array($value, array('Man', 'Woman')){
            new Exception('Wrong value for '.__CLASS__.'->'.$key);
        }
        else{
            $this->$key = $value;
        }
        ...
    }
}

每当类本身之外的代码试图设置类属性时，就会调用这个神奇的方法。 这是从PHP5 - 8工作。

我知道这是一个旧线程，然而没有一个我所见过的解决方法真的看起来像枚举，因为几乎所有的解决方法都需要你手动分配值给枚举项，或者它需要你传递一个枚举键数组到一个函数。所以我创造了自己的解决方案。

要使用我的解决方案创建枚举类，可以简单地扩展下面的enum类，创建一堆静态变量(不需要初始化它们)，并在枚举类定义的下面调用yourEnumClass::init()。

edit: This only works in php >= 5.3, but it can probably be modified to work in older versions as well /** * A base class for enums. * * This class can be used as a base class for enums. * It can be used to create regular enums (incremental indices), but it can also be used to create binary flag values. * To create an enum class you can simply extend this class, and make a call to <yourEnumClass>::init() before you use the enum. * Preferably this call is made directly after the class declaration. * Example usages: * DaysOfTheWeek.class.php * abstract class DaysOfTheWeek extends Enum{ * static $MONDAY = 1; * static $TUESDAY; * static $WEDNESDAY; * static $THURSDAY; * static $FRIDAY; * static $SATURDAY; * static $SUNDAY; * } * DaysOfTheWeek::init(); * * example.php * require_once("DaysOfTheWeek.class.php"); * $today = date('N'); * if ($today == DaysOfTheWeek::$SUNDAY || $today == DaysOfTheWeek::$SATURDAY) * echo "It's weekend!"; * * Flags.class.php * abstract class Flags extends Enum{ * static $FLAG_1; * static $FLAG_2; * static $FLAG_3; * } * Flags::init(Enum::$BINARY_FLAG); * * example2.php * require_once("Flags.class.php"); * $flags = Flags::$FLAG_1 | Flags::$FLAG_2; * if ($flags & Flags::$FLAG_1) * echo "Flag_1 is set"; * * @author Tiddo Langerak */ abstract class Enum{ static $BINARY_FLAG = 1; /** * This function must be called to initialize the enumeration! * * @param bool $flags If the USE_BINARY flag is provided, the enum values will be binary flag values. Default: no flags set. */ public static function init($flags = 0){ //First, we want to get a list of all static properties of the enum class. We'll use the ReflectionClass for this. $enum = get_called_class(); $ref = new ReflectionClass($enum); $items = $ref->getStaticProperties(); //Now we can start assigning values to the items. if ($flags & self::$BINARY_FLAG){ //If we want binary flag values, our first value should be 1. $value = 1; //Now we can set the values for all items. foreach ($items as $key=>$item){ if (!isset($item)){ //If no value is set manually, we should set it. $enum::$$key = $value; //And we need to calculate the new value $value *= 2; } else { //If there was already a value set, we will continue starting from that value, but only if that was a valid binary flag value. //Otherwise, we will just skip this item. if ($key != 0 && ($key & ($key - 1) == 0)) $value = 2 * $item; } } } else { //If we want to use regular indices, we'll start with index 0. $value = 0; //Now we can set the values for all items. foreach ($items as $key=>$item){ if (!isset($item)){ //If no value is set manually, we should set it, and increment the value for the next item. $enum::$$key = $value; $value++; } else { //If a value was already set, we'll continue from that value. $value = $item+1; } } } } }

提出的解决方案效果很好。干净光滑。

然而，如果你想要强类型的枚举，你可以使用这个:

class TestEnum extends Enum
{
    public static $TEST1;
    public static $TEST2;
}
TestEnum::init(); // Automatically initializes enum values

枚举类如下所示:

class Enum
{
    public static function parse($enum)
    {
        $class = get_called_class();
        $vars = get_class_vars($class);
        if (array_key_exists($enum, $vars)) {
            return $vars[$enum];
        }
        return null;
    }

    public static function init()
    {
        $className = get_called_class();
        $consts = get_class_vars($className);
        foreach ($consts as $constant => $value) {
            if (is_null($className::$$constant)) {
                $constantValue = $constant;
                $constantValueName = $className . '::' . $constant . '_VALUE';
                if (defined($constantValueName)) {
                    $constantValue = constant($constantValueName);
                }
                $className::$$constant = new $className($constantValue);
            }
        }
    }

    public function __construct($value)
    {
        $this->value = $value;
    }
}

这样，枚举值是强类型的和

$TEST1 == TEST1::parse('TEST1') // true语句

公认的答案是要走的路，实际上这是我所做的简单。枚举提供了大多数优点(可读、快速等)。然而，这里缺少一个概念:类型安全。在大多数语言中，枚举也用于限制允许的值。下面是一个通过使用私有构造函数、静态实例化方法和类型检查来获得类型安全的例子:

class DaysOfWeek{
 const Sunday = 0;
 const Monday = 1;
 // etc.

 private $intVal;
 private function __construct($intVal){
   $this->intVal = $intVal;
 }

 //static instantiation methods
 public static function MONDAY(){
   return new self(self::Monday);
 }
 //etc.
}

//function using type checking
function printDayOfWeek(DaysOfWeek $d){ //compiler can now use type checking
  // to something with $d...
}

//calling the function is safe!
printDayOfWeek(DaysOfWeek::MONDAY());

我们甚至可以更进一步:在DaysOfWeek类中使用常量可能会导致误用:例如，人们可能会这样错误地使用它:

printDayOfWeek(DaysOfWeek::Monday); //triggers a compiler error.

这是错误的(调用整数常量)。我们可以使用私有静态变量而不是常量来防止这种情况:

class DaysOfWeeks{

  private static $monday = 1;
  //etc.

  private $intVal;
  //private constructor
  private function __construct($intVal){
    $this->intVal = $intVal;
  }

  //public instantiation methods
  public static function MONDAY(){
    return new self(self::$monday);
  }
  //etc.


  //convert an instance to its integer value
  public function intVal(){
    return $this->intVal;
  }

}

当然，不可能访问整数常量(这实际上是目的)。intVal方法允许将DaysOfWeek对象转换为其整数表示形式。

请注意，我们甚至可以进一步在实例化方法中实现缓存机制，以在广泛使用枚举的情况下节省内存…

希望这能有所帮助

编辑:从PHP 8.1开始，支持枚举:https://www.php.net/manual/en/language.types.enumerations.php

—

根据用例，我通常会使用如下简单的代码:

abstract class DaysOfWeek
{
    const Sunday = 0;
    const Monday = 1;
    // etc.
}

$today = DaysOfWeek::Sunday;

然而，其他用例可能需要对常量和值进行更多的验证。根据下面关于反射的评论和其他一些注意事项，下面是一个扩展的示例，它可能更好地适用于更广泛的情况:

abstract class BasicEnum {
    private static $constCacheArray = NULL;

    private static function getConstants() {
        if (self::$constCacheArray == NULL) {
            self::$constCacheArray = [];
        }
        $calledClass = get_called_class();
        if (!array_key_exists($calledClass, self::$constCacheArray)) {
            $reflect = new ReflectionClass($calledClass);
            self::$constCacheArray[$calledClass] = $reflect->getConstants();
        }
        return self::$constCacheArray[$calledClass];
    }

    public static function isValidName($name, $strict = false) {
        $constants = self::getConstants();

        if ($strict) {
            return array_key_exists($name, $constants);
        }

        $keys = array_map('strtolower', array_keys($constants));
        return in_array(strtolower($name), $keys);
    }

    public static function isValidValue($value, $strict = true) {
        $values = array_values(self::getConstants());
        return in_array($value, $values, $strict);
    }
}

通过创建一个扩展BasicEnum的简单枚举类，你现在可以使用方法进行简单的输入验证:

abstract class DaysOfWeek extends BasicEnum {
    const Sunday = 0;
    const Monday = 1;
    const Tuesday = 2;
    const Wednesday = 3;
    const Thursday = 4;
    const Friday = 5;
    const Saturday = 6;
}

DaysOfWeek::isValidName('Humpday');                  // false
DaysOfWeek::isValidName('Monday');                   // true
DaysOfWeek::isValidName('monday');                   // true
DaysOfWeek::isValidName('monday', $strict = true);   // false
DaysOfWeek::isValidName(0);                          // false

DaysOfWeek::isValidValue(0);                         // true
DaysOfWeek::isValidValue(5);                         // true
DaysOfWeek::isValidValue(7);                         // false
DaysOfWeek::isValidValue('Friday');                  // false

作为旁注，任何时候我在一个静态/const类上至少使用一次反射，其中数据不会改变(例如在enum中)，我都会缓存那些反射调用的结果，因为每次使用新的反射对象最终都会有明显的性能影响(存储在多个enum的关联数组中)。

现在大多数人已经升级到至少5.3版本，而且也有了脾脏，这当然也是一个可行的选择——只要你不介意在你的代码库中使用实际枚举实例化这种传统的不直观的概念。在上面的例子中，BasicEnum和DaysOfWeek根本不能被实例化，也不应该被实例化。

我所见过的PHP中枚举最常见的解决方案是创建一个通用枚举类，然后扩展它。你可以看看这个。

更新:或者，我从phpclasses.org找到了这个。