我必须递归地重命名一个完整的文件夹树，这样就不会出现大写字母(这是c++源代码，但这无关紧要)。
忽略CVS和Subversion版本控制文件/文件夹的加分项。首选的方法是shell脚本，因为shell应该在任何Linux机器上可用。
关于文件重命名的细节有一些有效的争论。
I think files with the same lowercase names should be overwritten; it's the user's problem. When checked out on a case-ignoring file system, it would overwrite the first one with the latter, too.
I would consider A-Z characters and transform them to a-z, everything else is just calling for problems (at least with source code).
The script would be needed to run a build on a Linux system, so I think changes to CVS or Subversion version control files should be omitted. After all, it's just a scratch checkout. Maybe an "export" is more appropriate.
下面是我的次优解决方案，使用Bash shell脚本:
#!/bin/bash
# First, rename all folders
for f in `find . -depth ! -name CVS -type d`; do
g=`dirname "$f"`/`basename "$f" | tr '[A-Z]' '[a-z]'`
if [ "xxx$f" != "xxx$g" ]; then
echo "Renaming folder $f"
mv -f "$f" "$g"
fi
done
# Now, rename all files
for f in `find . ! -type d`; do
g=`dirname "$f"`/`basename "$f" | tr '[A-Z]' '[a-z]'`
if [ "xxx$f" != "xxx$g" ]; then
echo "Renaming file $f"
mv -f "$f" "$g"
fi
done
文件夹都正确地重命名，mv在权限不匹配时不会询问问题，CVS文件夹也不会重命名(不幸的是，该文件夹内的CVS控制文件仍然会重命名)。
由于“find -depth”和“find | sort -r”都以可用于重命名的顺序返回文件夹列表，我更喜欢使用“-depth”来搜索文件夹。
如果你使用Arch Linux，你可以从AUR安装rename)包，它提供了renamexm命令作为/usr/bin/renamexm可执行文件和一个手册页面。
它是一个非常强大的工具，可以快速重命名文件和目录。
转换为小写字母
rename -l Developers.mp3 # or --lowcase
转换为大写
rename -u developers.mp3 # or --upcase, long option
其他选项
-R --recursive # directory and its children
-t --test # Dry run, output but don't rename
-o --owner # Change file owner as well to user specified
-v --verbose # Output what file is renamed and its new name
-s/str/str2 # Substitute string on pattern
--yes # Confirm all actions
如果需要，您可以从这里获取示例Developers.mp3文件;)
