如何从我的C或c++代码中确定目录中的文件列表?
我不允许在程序中执行ls命令并解析结果。
如何从我的C或c++代码中确定目录中的文件列表?
我不允许在程序中执行ls命令并解析结果。
当前回答
Shreevardhan的答案很有效。但是如果你想在c++14中使用它,只需要更改命名空间fs = experimental::filesystem;
也就是说,
#include <string>
#include <iostream>
#include <filesystem>
using namespace std;
namespace fs = experimental::filesystem;
int main()
{
string path = "C:\\splits\\";
for (auto & p : fs::directory_iterator(path))
cout << p << endl;
int n;
cin >> n;
}
其他回答
我希望这段代码对您有所帮助。
#include <windows.h>
#include <iostream>
#include <string>
#include <vector>
using namespace std;
string wchar_t2string(const wchar_t *wchar)
{
string str = "";
int index = 0;
while(wchar[index] != 0)
{
str += (char)wchar[index];
++index;
}
return str;
}
wchar_t *string2wchar_t(const string &str)
{
wchar_t wchar[260];
int index = 0;
while(index < str.size())
{
wchar[index] = (wchar_t)str[index];
++index;
}
wchar[index] = 0;
return wchar;
}
vector<string> listFilesInDirectory(string directoryName)
{
WIN32_FIND_DATA FindFileData;
wchar_t * FileName = string2wchar_t(directoryName);
HANDLE hFind = FindFirstFile(FileName, &FindFileData);
vector<string> listFileNames;
listFileNames.push_back(wchar_t2string(FindFileData.cFileName));
while (FindNextFile(hFind, &FindFileData))
listFileNames.push_back(wchar_t2string(FindFileData.cFileName));
return listFileNames;
}
void main()
{
vector<string> listFiles;
listFiles = listFilesInDirectory("C:\\*.txt");
for each (string str in listFiles)
cout << str << endl;
}
试试来自direct .h的scandir()
男人scandir ()
char **getKeys(char *data_dir, char* tablename, int *num_keys)
{
char** arr = malloc(MAX_RECORDS_PER_TABLE*sizeof(char*));
int i = 0;
for (;i < MAX_RECORDS_PER_TABLE; i++)
arr[i] = malloc( (MAX_KEY_LEN+1) * sizeof(char) );
char *buf = (char *)malloc( (MAX_KEY_LEN+1)*sizeof(char) );
snprintf(buf, MAX_KEY_LEN+1, "%s/%s", data_dir, tablename);
DIR* tableDir = opendir(buf);
struct dirent* getInfo;
readdir(tableDir); // ignore '.'
readdir(tableDir); // ignore '..'
i = 0;
while(1)
{
getInfo = readdir(tableDir);
if (getInfo == 0)
break;
strcpy(arr[i++], getInfo->d_name);
}
*(num_keys) = i;
return arr;
}
为什么不使用glob()?
#include <glob.h>
glob_t glob_result;
glob("/your_directory/*",GLOB_TILDE,NULL,&glob_result);
for(unsigned int i=0; i<glob_result.gl_pathc; ++i){
cout << glob_result.gl_pathv[i] << endl;
}
您可以使用std::experimental:: filesystem::directory_iterator()来获取根目录下的所有直接文件。然后,读取这些路径文件的名称。
#include <iostream>
#include <filesystem>
#include <string>
#include <direct.h>
using namespace std;
namespace fs = std::experimental::filesystem;
void ShowListFile(string path)
{
for(auto &p: fs::directory_iterator(path)) /*get directory */
cout<<p.path().filename()<<endl; // get file name
}
int main() {
ShowListFile("C:/Users/dell/Pictures/Camera Roll/");
getchar();
return 0;
}