用@staticmethod修饰的方法和用@classmethod修饰的方法有什么区别?


当前回答

太长,读不下去了

静态方法本质上是绑定到类(及其实例)的函数

类方法本质上是一种可继承的静态方法。

有关详细信息,请参阅其他人的优秀答案。

其他回答

静态方法是一种对所调用的类或实例一无所知的方法。它只获取传递的参数,而不是隐式的第一个参数。它在Python中基本上是无用的——您可以只使用模块函数而不是静态方法。

另一方面,类方法是一种方法,它将被调用的类或被调用的实例的类作为第一个参数传递。当您希望该方法成为类的工厂时,这很有用:因为它获得了作为第一个参数调用的实际类,所以即使涉及子类,您也可以始终实例化正确的类。例如,观察类方法dict.fromkeys()在子类上调用时如何返回子类的实例:

>>> class DictSubclass(dict):
...     def __repr__(self):
...         return "DictSubclass"
... 
>>> dict.fromkeys("abc")
{'a': None, 'c': None, 'b': None}
>>> DictSubclass.fromkeys("abc")
DictSubclass
>>> 

一个非常重要的实际差异发生在子类化时。如果你不介意的话,我会劫持@unsubu的例子:

class A: 
    def foo(self, x): 
        print("executing foo(%s, %s)" % (self, x)) 
 
    @classmethod
    def class_foo(cls, x): 
        print("executing class_foo(%s, %s)" % (cls, x))
 
    @staticmethod 
    def static_foo(x): 
        print("executing static_foo(%s)" % x)

class B(A):
    pass

在class_foo中,该方法知道它是在哪个类上调用的:

A.class_foo(1)
# => executing class_foo(<class '__main__.A'>, 1)
B.class_foo(1)
# => executing class_foo(<class '__main__.B'>, 1)

在static_foo中,无法确定它是在A还是B上调用的:

A.static_foo(1)
# => executing static_foo(1)
B.static_foo(1)
# => executing static_foo(1)

注意,这并不意味着您不能在静态方法中使用其他方法,您只需直接引用类,这意味着子类的静态方法仍将引用父类:

class A:
    @classmethod
    def class_qux(cls, x):
        print(f"executing class_qux({cls}, {x})")
    
    @classmethod
    def class_bar(cls, x):
        cls.class_qux(x)

    @staticmethod
    def static_bar(x):
        A.class_qux(x)

class B(A):
    pass

A.class_bar(1)
# => executing class_qux(<class '__main__.A'>, 1)
B.class_bar(1)
# => executing class_qux(<class '__main__.B'>, 1)
A.static_bar(1)
# => executing class_qux(<class '__main__.A'>, 1)
B.static_bar(1)
# => executing class_qux(<class '__main__.A'>, 1)

Python带有几个内置的装饰器。三大类是:

@classmethod
@staticmethod
@property

首先,让我们注意,类的任何函数都可以用这个类的实例调用(在初始化这个类之后)。

@classmethod是一种方法,它不仅可以作为类的实例调用函数,还可以直接由类本身作为其第一个参数调用函数。

@staticmethod是一种将函数放入类的方法(因为它在逻辑上属于类),同时表示它不需要访问类(因此我们不需要在函数定义中使用self)。

让我们考虑一下以下课程:

class DecoratorTest(object):

    def __init__(self):
        pass

    def doubler(self, x):
        return x*2

    @classmethod
    def class_doubler(cls, x): # we need to use 'cls' instead of 'self'; 'cls' reference to the class instead of an instance of the class
        return x*2

    @staticmethod
    def static_doubler(x): # no need adding 'self' here; static_doubler() could be just a function not inside the class
        return x*2

让我们看看它是如何工作的:

decor = DecoratorTest()

print(decor.doubler(5))
# 10

print(decor.class_doubler(5)) # a call with an instance of a class
# 10
print(DecoratorTest.class_doubler(5)) # a direct call by the class itself
# 10

# staticmethod could be called in the same way as classmethod.
print(decor.static_doubler(5)) # as an instance of the class
# 10
print(DecoratorTest.static_doubler(5)) # or as a direct call 
# 10

这里您可以看到这些方法的一些用例。

奖金:您可以在这里阅读@property decorator

我的贡献展示了@classmethod、@staticmethod和实例方法之间的区别,包括实例如何间接调用@staticmmethod。但是,与其从实例间接调用@staticmethod,不如将其私有化可能更“Python化”。这里没有演示从私有方法获取内容,但基本上是相同的概念。

#!python3

from os import system
system('cls')
# %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %

class DemoClass(object):
    # instance methods need a class instance and
    # can access the instance through 'self'
    def instance_method_1(self):
        return 'called from inside the instance_method_1()'

    def instance_method_2(self):
        # an instance outside the class indirectly calls the static_method
        return self.static_method() + ' via instance_method_2()'

    # class methods don't need a class instance, they can't access the
    # instance (self) but they have access to the class itself via 'cls'
    @classmethod
    def class_method(cls):
        return 'called from inside the class_method()'

    # static methods don't have access to 'cls' or 'self', they work like
    # regular functions but belong to the class' namespace
    @staticmethod
    def static_method():
        return 'called from inside the static_method()'
# %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %

# works even if the class hasn't been instantiated
print(DemoClass.class_method() + '\n')
''' called from inside the class_method() '''

# works even if the class hasn't been instantiated
print(DemoClass.static_method() + '\n')
''' called from inside the static_method() '''
# %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %   %

# >>>>> all methods types can be called on a class instance <<<<<
# instantiate the class
democlassObj = DemoClass()

# call instance_method_1()
print(democlassObj.instance_method_1() + '\n')
''' called from inside the instance_method_1() '''

# # indirectly call static_method through instance_method_2(), there's really no use
# for this since a @staticmethod can be called whether the class has been
# instantiated or not
print(democlassObj.instance_method_2() + '\n')
''' called from inside the static_method() via instance_method_2() '''

# call class_method()
print(democlassObj.class_method() + '\n')
'''  called from inside the class_method() '''

# call static_method()
print(democlassObj.static_method())
''' called from inside the static_method() '''

"""
# whether the class is instantiated or not, this doesn't work
print(DemoClass.instance_method_1() + '\n')
'''
TypeError: TypeError: unbound method instancemethod() must be called with
DemoClass instance as first argument (got nothing instead)
'''
"""

当存在继承时,就会出现差异。

假设有两个类——父类和子类。如果要使用@staticmethod,print_name方法应该写两次,因为类的名称应该写在打印行中。

class Parent:
   _class_name = "Parent"

   @staticmethod
   def print_name():
       print(Parent._class_name)


class Child(Parent):
   _class_name = "Child"

   @staticmethod
   def print_name():
       print(Child._class_name)


Parent.print_name()
Child.print_name()

但是,对于@classmethod,不需要编写print_name方法两次。

class Parent:
    _class_name = "Parent"

    @classmethod
    def print_name(cls):
        print(cls._class_name)


class Child(Parent):
    _class_name = "Child"


Parent.print_name()
Child.print_name()