我想测量执行一个函数所花费的时间。我没时间工作:

import timeit
start = timeit.timeit()
print("hello")
end = timeit.timeit()
print(end - start)

当前回答

如果您想方便地对函数计时,可以使用一个简单的修饰符:

import time

def timing_decorator(func):
    def wrapper(*args, **kwargs):
        start = time.perf_counter()
        original_return_val = func(*args, **kwargs)
        end = time.perf_counter()
        print("time elapsed in ", func.__name__, ": ", end - start, sep='')
        return original_return_val

    return wrapper

您可以在您希望计时的函数上使用它,如下所示:

@timing_decorator
def function_to_time():
    time.sleep(1)

function_to_time()

无论何时调用function_to_time,它都会打印所用的时间和正在计时的函数的名称。

其他回答

如果您想方便地对函数计时,可以使用一个简单的修饰符:

import time

def timing_decorator(func):
    def wrapper(*args, **kwargs):
        start = time.perf_counter()
        original_return_val = func(*args, **kwargs)
        end = time.perf_counter()
        print("time elapsed in ", func.__name__, ": ", end - start, sep='')
        return original_return_val

    return wrapper

您可以在您希望计时的函数上使用它,如下所示:

@timing_decorator
def function_to_time():
    time.sleep(1)

function_to_time()

无论何时调用function_to_time,它都会打印所用的时间和正在计时的函数的名称。

这是另一种方法:

>> from pytictoc import TicToc
>> t = TicToc() # create TicToc instance
>> t.tic() # Start timer
>> # do something
>> t.toc() # Print elapsed time
Elapsed time is 2.612231 seconds.

与传统方式相比:

>> from time import time
>> t1 = time()
>> # do something
>> t2 = time()
>> elapsed = t2 - t1
>> print('Elapsed time is %f seconds.' % elapsed)
Elapsed time is 2.612231 seconds.

安装:

pip install pytictoc

有关详细信息,请参阅PyPi页面。

对于Python 3

如果使用时间模块,则可以获取当前时间戳,然后执行代码,然后再次获取时间戳。现在,所用时间将是第一个时间戳减去第二个时间戳:

import time

first_stamp = int(round(time.time() * 1000))

# YOUR CODE GOES HERE
time.sleep(5)

second_stamp = int(round(time.time() * 1000))

# Calculate the time taken in milliseconds
time_taken = second_stamp - first_stamp

# To get time in seconds:
time_taken_seconds = round(time_taken / 1000)
print(f'{time_taken_seconds} seconds or {time_taken} milliseconds')

我们还可以将时间转换为人类可读的时间。

import time, datetime

start = time.clock()

def num_multi1(max):
    result = 0
    for num in range(0, 1000):
        if (num % 3 == 0 or num % 5 == 0):
            result += num

    print "Sum is %d " % result

num_multi1(1000)

end = time.clock()
value = end - start
timestamp = datetime.datetime.fromtimestamp(value)
print timestamp.strftime('%Y-%m-%d %H:%M:%S')

作为lambda,获取经过的时间和时间戳:

import datetime
t_set = lambda: datetime.datetime.now().astimezone().replace(microsecond=0)
t_diff = lambda t: str(t_set() - t)
t_stamp = lambda t=None: str(t) if t else str(t_set())

在实践中:

>>> 
>>> t_set()
datetime.datetime(2021, 3, 21, 1, 25, 17, tzinfo=datetime.timezone(datetime.timedelta(days=-1, seconds=61200), 'PDT'))
>>> t = t_set()
>>> t_diff(t)
'0:00:14'
>>> t_diff(t)
'0:00:23'
>>> t_stamp()
'2021-03-21 01:25:57-07:00'
>>> t_stamp(t)
'2021-03-21 01:25:22-07:00'
>>>