我想测量执行一个函数所花费的时间。我没时间工作:

import timeit
start = timeit.timeit()
print("hello")
end = timeit.timeit()
print(end - start)

当前回答

作为lambda,获取经过的时间和时间戳:

import datetime
t_set = lambda: datetime.datetime.now().astimezone().replace(microsecond=0)
t_diff = lambda t: str(t_set() - t)
t_stamp = lambda t=None: str(t) if t else str(t_set())

在实践中:

>>> 
>>> t_set()
datetime.datetime(2021, 3, 21, 1, 25, 17, tzinfo=datetime.timezone(datetime.timedelta(days=-1, seconds=61200), 'PDT'))
>>> t = t_set()
>>> t_diff(t)
'0:00:14'
>>> t_diff(t)
'0:00:23'
>>> t_stamp()
'2021-03-21 01:25:57-07:00'
>>> t_stamp(t)
'2021-03-21 01:25:22-07:00'
>>> 

其他回答

这种独特的基于类的方法提供了可打印的字符串表示、可自定义的舍入,以及以字符串或浮点形式方便地访问经过的时间。它是用Python 3.7开发的。

import datetime
import timeit


class Timer:
    """Measure time used."""
    # Ref: https://stackoverflow.com/a/57931660/

    def __init__(self, round_ndigits: int = 0):
        self._round_ndigits = round_ndigits
        self._start_time = timeit.default_timer()

    def __call__(self) -> float:
        return timeit.default_timer() - self._start_time

    def __str__(self) -> str:
        return str(datetime.timedelta(seconds=round(self(), self._round_ndigits)))

用法:

# Setup timer
>>> timer = Timer()

# Access as a string
>>> print(f'Time elapsed is {timer}.')
Time elapsed is 0:00:03.
>>> print(f'Time elapsed is {timer}.')
Time elapsed is 0:00:04.

# Access as a float
>>> timer()
6.841332235
>>> timer()
7.970274425

作为lambda,获取经过的时间和时间戳:

import datetime
t_set = lambda: datetime.datetime.now().astimezone().replace(microsecond=0)
t_diff = lambda t: str(t_set() - t)
t_stamp = lambda t=None: str(t) if t else str(t_set())

在实践中:

>>> 
>>> t_set()
datetime.datetime(2021, 3, 21, 1, 25, 17, tzinfo=datetime.timezone(datetime.timedelta(days=-1, seconds=61200), 'PDT'))
>>> t = t_set()
>>> t_diff(t)
'0:00:14'
>>> t_diff(t)
'0:00:23'
>>> t_stamp()
'2021-03-21 01:25:57-07:00'
>>> t_stamp(t)
'2021-03-21 01:25:22-07:00'
>>> 

测量小代码片段的执行时间。

时间单位:以秒为单位,以浮点数表示

import timeit
t = timeit.Timer('li = list(map(lambda x:x*2,[1,2,3,4,5]))')
t.timeit()
t.repeat()
>[1.2934070999999676, 1.3335035000000062, 1.422568500000125]

repeat()方法可以方便地多次调用timeit()并返回结果列表。重复(重复=3)¶有了这个列表,我们可以计算所有时间的平均值。默认情况下,timeit()在计时期间暂时关闭垃圾收集。time.Timer()解决了这个问题。赞成的意见:timeit.Timer()使独立计时更具可比性。gc可能是被测函数性能的重要组成部分。如果是,gc(垃圾收集器)可以作为设置字符串中的第一条语句重新启用。例如:timeit.Timer('li=列表(映射(lambda x:x*2,[1,2,3,4,5])',设置='gc.enable()')

源Python文档!

print_elapsed_time函数如下

def print_elapsed_time(prefix=''):
    e_time = time.time()
    if not hasattr(print_elapsed_time, 's_time'):
        print_elapsed_time.s_time = e_time
    else:
        print(f'{prefix} elapsed time: {e_time - print_elapsed_time.s_time:.2f} sec')
        print_elapsed_time.s_time = e_time

用这种方式

print_elapsed_time()
.... heavy jobs ...
print_elapsed_time('after heavy jobs')
.... tons of jobs ...
print_elapsed_time('after tons of jobs')

结果是

after heavy jobs elapsed time: 0.39 sec
after tons of jobs elapsed time: 0.60 sec  

这个函数的优点和缺点是你不需要经过开始时间

下面是另一个用于计时代码的上下文管理器-

用法:

from benchmark import benchmark

with benchmark("Test 1+1"):
    1+1
=>
Test 1+1 : 1.41e-06 seconds

或者,如果您需要时间值

with benchmark("Test 1+1") as b:
    1+1
print(b.time)
=>
Test 1+1 : 7.05e-07 seconds
7.05233786763e-07

基准.py:

from timeit import default_timer as timer

class benchmark(object):

    def __init__(self, msg, fmt="%0.3g"):
        self.msg = msg
        self.fmt = fmt

    def __enter__(self):
        self.start = timer()
        return self

    def __exit__(self, *args):
        t = timer() - self.start
        print(("%s : " + self.fmt + " seconds") % (self.msg, t))
        self.time = t

改编自http://dabeaz.blogspot.fr/2010/02/context-manager-for-timing-benchmarks.html