是否有可能终止一个正在运行的线程而不设置/检查任何标志/信号/等等?


当前回答

实现一个线程是绝对可能的。方法,如下例代码所示:

import sys
import threading
import time


class StopThread(StopIteration):
    pass

threading.SystemExit = SystemExit, StopThread


class Thread2(threading.Thread):

    def stop(self):
        self.__stop = True

    def _bootstrap(self):
        if threading._trace_hook is not None:
            raise ValueError('Cannot run thread with tracing!')
        self.__stop = False
        sys.settrace(self.__trace)
        super()._bootstrap()

    def __trace(self, frame, event, arg):
        if self.__stop:
            raise StopThread()
        return self.__trace


class Thread3(threading.Thread):

    def _bootstrap(self, stop_thread=False):
        def stop():
            nonlocal stop_thread
            stop_thread = True
        self.stop = stop

        def tracer(*_):
            if stop_thread:
                raise StopThread()
            return tracer
        sys.settrace(tracer)
        super()._bootstrap()

###############################################################################


def main():
    test1 = Thread2(target=printer)
    test1.start()
    time.sleep(1)
    test1.stop()
    test1.join()
    test2 = Thread2(target=speed_test)
    test2.start()
    time.sleep(1)
    test2.stop()
    test2.join()
    test3 = Thread3(target=speed_test)
    test3.start()
    time.sleep(1)
    test3.stop()
    test3.join()


def printer():
    while True:
        print(time.time() % 1)
        time.sleep(0.1)


def speed_test(count=0):
    try:
        while True:
            count += 1
    except StopThread:
        print('Count =', count)

if __name__ == '__main__':
    main()

Thread3类运行代码的速度似乎比Thread2类快大约33%。

其他回答

实现一个线程是绝对可能的。方法,如下例代码所示:

import sys
import threading
import time


class StopThread(StopIteration):
    pass

threading.SystemExit = SystemExit, StopThread


class Thread2(threading.Thread):

    def stop(self):
        self.__stop = True

    def _bootstrap(self):
        if threading._trace_hook is not None:
            raise ValueError('Cannot run thread with tracing!')
        self.__stop = False
        sys.settrace(self.__trace)
        super()._bootstrap()

    def __trace(self, frame, event, arg):
        if self.__stop:
            raise StopThread()
        return self.__trace


class Thread3(threading.Thread):

    def _bootstrap(self, stop_thread=False):
        def stop():
            nonlocal stop_thread
            stop_thread = True
        self.stop = stop

        def tracer(*_):
            if stop_thread:
                raise StopThread()
            return tracer
        sys.settrace(tracer)
        super()._bootstrap()

###############################################################################


def main():
    test1 = Thread2(target=printer)
    test1.start()
    time.sleep(1)
    test1.stop()
    test1.join()
    test2 = Thread2(target=speed_test)
    test2.start()
    time.sleep(1)
    test2.stop()
    test2.join()
    test3 = Thread3(target=speed_test)
    test3.start()
    time.sleep(1)
    test3.stop()
    test3.join()


def printer():
    while True:
        print(time.time() % 1)
        time.sleep(0.1)


def speed_test(count=0):
    try:
        while True:
            count += 1
    except StopThread:
        print('Count =', count)

if __name__ == '__main__':
    main()

Thread3类运行代码的速度似乎比Thread2类快大约33%。

如果您确实需要终止子任务的能力,请使用另一种实现。Multiprocessing和gevent都支持不加选择地杀死一个“线程”。

Python的线程不支持取消。不要尝试。你的代码很可能死锁、损坏或泄漏内存,或者有其他意想不到的“有趣的”难以调试的效果,这种情况很少发生,而且不确定。

有一个图书馆就是为了这个目的而建的,别说了。尽管这里列出的一些注意事项仍然适用,但至少这个库提供了一种常规的、可重复的技术来实现既定的目标。

假设,你想有多个线程的同一个函数,这是IMHO最简单的实现通过id停止一个:

import time
from threading import Thread

def doit(id=0):
    doit.stop=0
    print("start id:%d"%id)
    while 1:
        time.sleep(1)
        print(".")
        if doit.stop==id:
            doit.stop=0
            break
    print("end thread %d"%id)

t5=Thread(target=doit, args=(5,))
t6=Thread(target=doit, args=(6,))

t5.start() ; t6.start()
time.sleep(2)
doit.stop =5  #kill t5
time.sleep(2)
doit.stop =6  #kill t6

这里的好处是,你可以有多个相同或不同的函数,并通过functionname。stop来停止它们

如果你想只有一个线程的函数,那么你不需要记住id。如果做了,就停下来。停止> 0。

另一种方法是使用signal.pthread_kill发送一个停止信号。

from signal import pthread_kill, SIGTSTP
from threading import Thread
from itertools import count
from time import sleep

def target():
    for num in count():
        print(num)
        sleep(1)

thread = Thread(target=target)
thread.start()
sleep(5)
pthread_kill(thread.ident, SIGTSTP)

结果

0
1
2
3
4

[14]+  Stopped