如果你想从一个特定的url中找到一个特定的参数:

function findParam(url, param){
  var check = "" + param;
  if(url.search(check )>=0){
      return url.substring(url.search(check )).split('&')[0].split('=')[1];
  }
}  

var url = "http://www.yourdomain.com/example?id=1&order_no=114&invoice_no=254";  
alert(findParam(url,"order_no"));

$.urlParam = function(name) {
  var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
  return results[1] || 0;
}

我总是把它写成一行。params有变量:

params={};location.search.replace(/[?&]+([^=&]+)=([^&]*)/gi,function(s,k,v){params[k]=v})

多行:

var params={};
window.location.search
  .replace(/[?&]+([^=&]+)=([^&]*)/gi, function(str,key,value) {
    params[key] = value;
  }
);

作为一个函数

function getSearchParams(k){
 var p={};
 location.search.replace(/[?&]+([^=&]+)=([^&]*)/gi,function(s,k,v){p[k]=v})
 return k?p[k]:p;
}

你可以这样用:

getSearchParams()  //returns {key1:val1, key2:val2}

or

getSearchParams("key1")  //returns val1

还有另一种功能……

function param(name) {
    return (location.search.split(name + '=')[1] || '').split('&')[0];
}

我用了这个，很管用。 http://codesheet.org/codesheet/NF246Tzs

function getUrlVars() {
    var vars = {};
    var parts = window.location.href.replace(/[?&]+([^=&]+)=([^&]*)/gi, function(m,key,value) {
    vars[key] = value;
    });
return vars;
}


var first = getUrlVars()["id"];

这个方法很简单，对我来说很管用

$.urlParam = function(name){
    var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
    return results[1] || 0;
}

如果你的url是http://www.yoursite.com?city=4

试试这个

console.log($.urlParam('city'));