2023年起的解决方案

我们有:http://example.com?sent=yes

let searchParams = new URLSearchParams(window.location.search)

sent存在吗?

searchParams.has('sent') // true

它等于"是"吗?

let param = searchParams.get('sent')

然后比较一下。

试试这个工作演示http://jsfiddle.net/xy7cX/

火:

inArray: http://api.jquery.com/jQuery.inArray/

这应该会有帮助:)

code

var url = "http://myurl.com?sent=yes"

var pieces = url.split("?");
alert(pieces[1] + " ===== " + $.inArray("sent=yes", pieces));

只是想展示一下我的代码:

function (name) {
  name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
  var regex = new RegExp("[\\?&]" + name + "=([^&#]*)"),
  results = regex.exec(location.search);
  return results == null ? "" : decodeURIComponent(results[1].replace(/\+/g, " "));

}

我希望使用完整的简单REG Exp

  function getQueryString1(param) {
    return decodeURIComponent(
        (location.search.match(RegExp("[?|&]"+param+'=(.+?)(&|$)'))||[,null])[1]
    );
  }

函数GetRequestParam(参数) ｛ Var res = null; 尝试{ var qs = decodeURIComponent(window.location.search.substring(1));//获取then之后的所有内容'?URI中的' Var ar = q .split('&'); 美元。Each (ar, function(a, b){ Var kv = b.split('='); If (param === kv[0]){ Res = kv[1]; 返回false;//打破循环 ｝ })； }捕捉(e) {} 返回res; ｝

我希望这能有所帮助。

 <script type="text/javascript">
   function getParameters() {
     var searchString = window.location.search.substring(1),
       params = searchString.split("&"),
       hash = {};

     if (searchString == "") return {};
     for (var i = 0; i < params.length; i++) {
       var val = params[i].split("=");
       hash[unescape(val[0])] = unescape(val[1]);
     }

     return hash;
   }

    $(window).load(function() {
      var param = getParameters();
      if (typeof param.sent !== "undefined") {
        // Do something.
      }
    });
</script>