这是基于Gazoris的答案，但URL解码了参数，因此当它们包含除数字和字母以外的数据时可以使用:

function urlParam(name){
    var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
    // Need to decode the URL parameters, including putting in a fix for the plus sign
    // https://stackoverflow.com/a/24417399
    return results ? decodeURIComponent(results[1].replace(/\+/g, '%20')) : null;
}

jQuery代码片段，以获取动态变量存储在url作为参数，并将它们存储为JavaScript变量，以供您的脚本使用:

$.urlParam = function(name){
    var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
    if (results==null) {
       return null;
    }
    return decodeURI(results[1]) || 0;
}

example.com ? param1 = name&param2 = id = 6

$.urlParam('param1'); // name
$.urlParam('id');        // 6
$.urlParam('param2');   // null

带有空格的参数示例

http://www.jquery4u.com?city=Gold Coast
console.log($.urlParam('city'));  
//output: Gold%20Coast



console.log(decodeURIComponent($.urlParam('city'))); 
//output: Gold Coast

Sameer回答的咖啡脚本版本

getUrlParameter = (sParam) ->
  sPageURL = window.location.search.substring(1)
  sURLVariables = sPageURL.split('&')
  i = 0
  while i < sURLVariables.length
    sParameterName = sURLVariables[i].split('=')
    if sParameterName[0] == sParam
      return sParameterName[1]
    i++

还有另一种功能……

function param(name) {
    return (location.search.split(name + '=')[1] || '').split('&')[0];
}

我总是把它写成一行。params有变量:

params={};location.search.replace(/[?&]+([^=&]+)=([^&]*)/gi,function(s,k,v){params[k]=v})

多行:

var params={};
window.location.search
  .replace(/[?&]+([^=&]+)=([^&]*)/gi, function(str,key,value) {
    params[key] = value;
  }
);

作为一个函数

function getSearchParams(k){
 var p={};
 location.search.replace(/[?&]+([^=&]+)=([^&]*)/gi,function(s,k,v){p[k]=v})
 return k?p[k]:p;
}

你可以这样用:

getSearchParams()  //returns {key1:val1, key2:val2}

or

getSearchParams("key1")  //returns val1

使用这个

$.urlParam = function(name) {
  var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
  return results[1] || 0;
}