这是基于Gazoris的答案，但URL解码了参数，因此当它们包含除数字和字母以外的数据时可以使用:

function urlParam(name){
    var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
    // Need to decode the URL parameters, including putting in a fix for the plus sign
    // https://stackoverflow.com/a/24417399
    return results ? decodeURIComponent(results[1].replace(/\+/g, '%20')) : null;
}

也许太晚了。但是这种方法非常简单易行

<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript" src="jquery.url.js"></script>

<!-- URL:  www.example.com/correct/?message=done&year=1990 -->

<script type="text/javascript">
$(function(){
    $.url.attr('protocol')  // --> Protocol: "http"
    $.url.attr('path')      // --> host: "www.example.com"
    $.url.attr('query')         // --> path: "/correct/"
    $.url.attr('message')       // --> query: "done"
    $.url.attr('year')      // --> query: "1990"
});

更新 需要url插件:plugins.jquery.com/url 由于-Ripounet

使用URLSearchParams:

var params = new window.URLSearchParams(window.location.search);
console.log(params.get('name'));

注意兼容性(大多数情况下是好的，但IE和Edge，可能是不同的故事，检查这个兼容性参考:https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams)

$.urlParam = function(name) {
  var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
  return results[1] || 0;
}

对Sameer的回答略有改进，将参数缓存为闭包，以避免每次调用时解析和遍历所有参数

var getURLParam = (function() {
    var paramStr = decodeURIComponent(window.location.search).substring(1);
    var paramSegs = paramStr.split('&');
    var params = [];
    for(var i = 0; i < paramSegs.length; i++) {
        var paramSeg = paramSegs[i].split('=');
        params[paramSeg[0]] = paramSeg[1];
    }
    console.log(params);
    return function(key) {
        return params[key];
    }
})();

从字符串中获取参数:

Object.defineProperty(String.prototype, 'urlParam', {

    value: function (param) {

    "use strict";

    var str = this.trim();

    var regex = "[\?&]" + param + "=([^&#]*)";

    var results = new RegExp(regex, "i").exec(str);

    return (results !== null) ? results[1] : '';

    }
});

使用方法:

var src = 'http://your-url.com/?param=value'

console.log(src.urlParam(param)); // returns 'value'