这是基于Gazoris的答案，但URL解码了参数，因此当它们包含除数字和字母以外的数据时可以使用:

function urlParam(name){
    var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
    // Need to decode the URL parameters, including putting in a fix for the plus sign
    // https://stackoverflow.com/a/24417399
    return results ? decodeURIComponent(results[1].replace(/\+/g, '%20')) : null;
}

Sameer回答的咖啡脚本版本

getUrlParameter = (sParam) ->
  sPageURL = window.location.search.substring(1)
  sURLVariables = sPageURL.split('&')
  i = 0
  while i < sURLVariables.length
    sParameterName = sURLVariables[i].split('=')
    if sParameterName[0] == sParam
      return sParameterName[1]
    i++

如果你想从一个特定的url中找到一个特定的参数:

function findParam(url, param){
  var check = "" + param;
  if(url.search(check )>=0){
      return url.substring(url.search(check )).split('&')[0].split('=')[1];
  }
}  

var url = "http://www.yourdomain.com/example?id=1&order_no=114&invoice_no=254";  
alert(findParam(url,"order_no"));

试试这个工作演示http://jsfiddle.net/xy7cX/

火:

inArray: http://api.jquery.com/jQuery.inArray/

这应该会有帮助:)

code

var url = "http://myurl.com?sent=yes"

var pieces = url.split("?");
alert(pieces[1] + " ===== " + $.inArray("sent=yes", pieces));

2023年起的解决方案

我们有:http://example.com?sent=yes

let searchParams = new URLSearchParams(window.location.search)

sent存在吗?

searchParams.has('sent') // true

它等于"是"吗?

let param = searchParams.get('sent')

然后比较一下。

只是想展示一下我的代码:

function (name) {
  name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
  var regex = new RegExp("[\\?&]" + name + "=([^&#]*)"),
  results = regex.exec(location.search);
  return results == null ? "" : decodeURIComponent(results[1].replace(/\+/g, " "));

}