假设我有一个进程,它只生成一个子进程。现在,当父进程由于某种原因(正常或不正常,通过kill, ^C,断言失败或其他任何原因)退出时,我希望子进程死亡。如何正确地做到这一点?


关于stackoverflow的一些类似问题:

(前面问过)当父进程退出的时候,我怎么能让子进程退出呢? (稍后问)用fork()创建的子进程会在父进程被杀死时自动被杀死吗?


关于Windows的stackoverflow也有类似的问题:

如何在Windows中自动销毁子进程? 当父进程被杀死时,杀死子进程


当前回答

在Linux下,你可以在子进程中安装父进程死亡信号,例如:

#include <sys/prctl.h> // prctl(), PR_SET_PDEATHSIG
#include <signal.h> // signals
#include <unistd.h> // fork()
#include <stdio.h>  // perror()

// ...

pid_t ppid_before_fork = getpid();
pid_t pid = fork();
if (pid == -1) { perror(0); exit(1); }
if (pid) {
    ; // continue parent execution
} else {
    int r = prctl(PR_SET_PDEATHSIG, SIGTERM);
    if (r == -1) { perror(0); exit(1); }
    // test in case the original parent exited just
    // before the prctl() call
    if (getppid() != ppid_before_fork)
        exit(1);
    // continue child execution ...

请注意,在fork之前存储父进程id,并在prctl()之后在子进程中测试它,消除了prctl()和调用子进程的退出之间的竞争条件。

还要注意,子进程的父进程死亡信号在新创建的子进程中被清除。它不受execve()的影响。

如果我们确定负责收养所有孤儿的系统进程PID为1,这个测试就可以简化:

pid_t pid = fork();
if (pid == -1) { perror(0); exit(1); }
if (pid) {
    ; // continue parent execution
} else {
    int r = prctl(PR_SET_PDEATHSIG, SIGTERM);
    if (r == -1) { perror(0); exit(1); }
    // test in case the original parent exited just
    // before the prctl() call
    if (getppid() == 1)
        exit(1);
    // continue child execution ...

但是,依赖于系统进程的初始化和PID 1是不可移植的。posix . 1的授权- 2008指定:

调用进程的所有现有子进程和僵尸进程的父进程ID应设置为实现定义的系统进程的进程ID。也就是说,这些进程应该由一个特殊的系统进程继承。

传统上,采用所有孤儿进程的系统进程是PID 1,即init -它是所有进程的祖先。

在像Linux或FreeBSD这样的现代系统上,另一个进程可能具有这个角色。例如,在Linux上,一个进程可以调用prctl(PR_SET_CHILD_SUBREAPER, 1)来将自己建立为继承其任何后代的所有孤儿的系统进程(参见Fedora 25上的一个例子)。

其他回答

Historically, from UNIX v7, the process system has detected orphanity of processes by checking a process' parent id. As I say, historically, the init(8) system process is a special process by only one reason: It cannot die. It cannot die because the kernel algorithm to deal with assigning a new parent process id, depends on this fact. when a process executes its exit(2) call (by means of a process system call or by external task as sending it a signal or the like) the kernel reassigns all children of this process the id of the init process as their parent process id. This leads to the most easy test, and most portable way of knowing if a process has got orphan. Just check the result of the getppid(2) system call and if it is the process id of the init(2) process then the process got orphan before the system call.

这种方法会产生两个问题:

first, we have the possibility of changing the init process to any user process, so How can we assure that the init process will always be parent of all orphan processes? Well, in the exit system call code there's a explicit check to see if the process executing the call is the init process (the process with pid equal to 1) and if that's the case, the kernel panics (It should not be able anymore to maintain the process hierarchy) so it is not permitted for the init process to do an exit(2) call. second, there's a race condition in the basic test exposed above. Init process' id is assumed historically to be 1, but that's not warranted by the POSIX approach, that states (as exposed in other response) that only a system's process id is reserved for that purpose. Almost no posix implementation does this, and you can assume in original unix derived systems that having 1 as response of getppid(2) system call is enough to assume the process is orphan. Another way to check is to make a getppid(2) just after the fork and compare that value with the result of a new call. This simply doesn't work in all cases, as both call are not atomic together, and the parent process can die after the fork(2) and before the first getppid(2) system call. The processparent id only changes once, when its parent does anexit(2)call, so this should be enough to check if thegetppid(2)result changed between calls to see that parent process has exit. This test is not valid for the actual children of the init process, because they are always children ofinit(8)`, but you can assume safely these processes as having no parent either (except when you substitute in a system the init process)

如果父母去世,孤儿的PPID变为1 -你只需要检查你自己的PPID。 在某种程度上,这就是上面提到的轮询。 这是它的外壳部分:

check_parent () {
      parent=`ps -f|awk '$2=='$PID'{print $3 }'`
      echo "parent:$parent"
      let parent=$parent+0
      if [[ $parent -eq 1 ]]; then
        echo "parent is dead, exiting"
        exit;
      fi
}


PID=$$
cnt=0
while [[ 1 = 1 ]]; do
  check_parent
  ... something
done

安装一个陷阱处理程序来捕获SIGINT,如果你的子进程还活着,它就会杀死它,尽管其他的帖子是正确的,它不会捕获SIGKILL。

以独占访问的方式打开一个.lockfile,并让子进程尝试打开它——如果打开成功,子进程应该退出

以防它与任何人相关,当我从c++派生子进程中的JVM实例时,我可以让JVM实例在父进程完成后正确终止的唯一方法是执行以下操作。如果这不是最好的方法,希望有人能在评论中提供反馈。

1)在通过execv启动Java应用程序之前,在fork子进程上调用prctl(PR_SET_PDEATHSIG, SIGHUP)

2)在Java应用程序中添加一个shutdown钩子,轮询直到其父PID等于1,然后执行一个硬的Runtime.getRuntime().halt(0)。轮询是通过启动运行ps命令的单独shell来完成的(参见:如何在Linux上的Java或JRuby中找到我的PID ?)

130118年编辑:

这似乎不是一个可靠的解决方案。我仍然在努力理解发生的事情的细微差别,但在屏幕/SSH会话中运行这些应用程序时,有时仍然会遇到孤立的JVM进程。

Instead of polling for the PPID in the Java app, I simply had the shutdown hook perform cleanup followed by a hard halt as above. Then I made sure to invoke waitpid in the C++ parent app on the spawned child process when it was time to terminate everything. This seems to be a more robust solution, as the child process ensures that it terminates, while the parent uses existing references to make sure that its children terminate. Compare this to the previous solution which had the parent process terminate whenever it pleased, and had the children try to figure out if they had been orphaned before terminating.

子进程是否有连接父进程的管道?如果是这样,那么写入时会收到SIGPIPE,读取时会收到EOF——这些情况都可以检测到。