这两种方法都有什么优势吗?
示例1:
class A {
B b = new B();
}
示例2:
class A {
B b;
A() {
b = new B();
}
}
这两种方法都有什么优势吗?
示例1:
class A {
B b = new B();
}
示例2:
class A {
B b;
A() {
b = new B();
}
}
当前回答
第二个例子是惰性初始化。第一个是更简单的初始化,它们本质上是一样的。
其他回答
例2不太灵活。如果您添加了另一个构造函数,则需要记住在该构造函数中实例化字段。直接实例化字段,或者在getter中引入延迟加载。
如果实例化需要的不仅仅是一个简单的new,请使用初始化块。不管使用的构造函数是什么,这个函数都将运行。如。
public class A {
private Properties properties;
{
try {
properties = new Properties();
properties.load(Thread.currentThread().getContextClassLoader().getResourceAsStream("file.properties"));
} catch (IOException e) {
throw new ConfigurationException("Failed to load properties file.", e); // It's a subclass of RuntimeException.
}
}
// ...
}
我认为例2更可取。我认为最佳实践是在构造函数外部声明,并在构造函数中初始化。
我个人的“原则”(几乎从未被打破)是:
的开头声明所有变量 一块 使所有变量为final,除非它们 不能 每行声明一个变量 永远不要在某处初始化变量 宣布 只初始化a中的东西 构造函数时使用 的构造函数 初始化
我的代码是这样的:
public class X
{
public static final int USED_AS_A_CASE_LABEL = 1; // only exception - the compiler makes me
private static final int A;
private final int b;
private int c;
static
{
A = 42;
}
{
b = 7;
}
public X(final int val)
{
c = val;
}
public void foo(final boolean f)
{
final int d;
final int e;
d = 7;
// I will eat my own eyes before using ?: - personal taste.
if(f)
{
e = 1;
}
else
{
e = 2;
}
}
}
This way I am always 100% certain where to look for variables declarations (at the start of a block), and their assignments (as soon as it makes sense after the declaration). This winds up potentially being more efficient as well since you never initialize a variable with a value that is not used (for example declare and init vars and then throw an exception before half of those vars needed to have a value). You also do not wind up doing pointless initialization (like int i = 0; and then later on, before "i" is used, do i = 5;.
我非常重视一致性,所以遵循这个“规则”是我一直在做的事情,它使处理代码变得更容易,因为你不需要到处寻找东西。
你的里程可能会有所不同。
我今天以一种有趣的方式被烧伤了:
class MyClass extends FooClass {
String a = null;
public MyClass() {
super(); // Superclass calls init();
}
@Override
protected void init() {
super.init();
if (something)
a = getStringYadaYada();
}
}
看到错误了吗?结果是,在父类构造函数被调用之后才调用a = null初始化式。由于超类构造函数调用init(), a的初始化之后是a = null初始化。
另一种选择是使用依赖注入。
class A{
B b;
A(B b) {
this.b = b;
}
}
This removes the responsibility of creating the B object from the constructor of A. This will make your code more testable and easier to maintain in the long run. The idea is to reduce the coupling between the two classes A and B. A benefit that this gives you is that you can now pass any object that extends B (or implements B if it is an interface) to A's constructor and it will work. One disadvantage is that you give up encapsulation of the B object, so it is exposed to the caller of the A constructor. You'll have to consider if the benefits are worth this trade-off, but in many cases they are.