我发现这很好。不将状态(方法1)定义为，例如，

const initialValue = 1;

const [state,setState] = useState(initialValue)

试试这个方法(方法2)，

const [state = initialValue,setState] = useState()

这在没有使用useEffect的情况下解决了渲染问题，因为在这种情况下我们不关心它的内部闭包方法。

附注:如果你关心在任何用例中使用旧状态，那么useState和useEffect需要使用，因为它需要那种状态，所以在这种情况下接近1应使用。

使用我库中的自定义钩子，你可以等待状态值更新:

useAsyncWatcher(…values):watcherFn(peekPrevValue: boolean)=>Promise -是一个围绕useEffect的承诺包装器，它可以等待更新并返回一个新值，如果可选的peekPrevValue参数设置为true，则可能返回一个以前的值。

(现场演示)

    import React, { useState, useEffect, useCallback } from "react";
    import { useAsyncWatcher } from "use-async-effect2";
    
    function TestComponent(props) {
      const [counter, setCounter] = useState(0);
      const [text, setText] = useState("");
    
      const textWatcher = useAsyncWatcher(text);
    
      useEffect(() => {
        setText(`Counter: ${counter}`);
      }, [counter]);
    
      const inc = useCallback(() => {
        (async () => {
          await new Promise((resolve) => setTimeout(resolve, 1000));
          setCounter((counter) => counter + 1);
          const updatedText = await textWatcher();
          console.log(updatedText);
        })();
      }, []);
    
      return (
        <div className="component">
          <div className="caption">useAsyncEffect demo</div>
          <div>{counter}</div>
          <button onClick={inc}>Inc counter</button>
        </div>
      );
    }
    
    export default TestComponent;

useAsyncDeepState是一个深度状态实现(类似于此。setState (patchObject))，它的setter可以返回一个与内部效果同步的承诺。如果调用setter时不带参数，则它不会更改状态值，而只是订阅状态更新。在这种情况下，您可以从组件内部的任何地方获取状态值，因为函数闭包不再是障碍。

(现场演示)

import React, { useCallback, useEffect } from "react";
import { useAsyncDeepState } from "use-async-effect2";

function TestComponent(props) {
  const [state, setState] = useAsyncDeepState({
    counter: 0,
    computedCounter: 0
  });

  useEffect(() => {
    setState(({ counter }) => ({
      computedCounter: counter * 2
    }));
  }, [state.counter]);

  const inc = useCallback(() => {
    (async () => {
      await new Promise((resolve) => setTimeout(resolve, 1000));
      await setState(({ counter }) => ({ counter: counter + 1 }));
      console.log("computedCounter=", state.computedCounter);
    })();
  });

  return (
    <div className="component">
      <div className="caption">useAsyncDeepState demo</div>
      <div>state.counter : {state.counter}</div>
      <div>state.computedCounter : {state.computedCounter}</div>
      <button onClick={() => inc()}>Inc counter</button>
    </div>
  );
}

I too was stuck with the same problem. As other answers above have clarified the error here, which is that useState is asynchronous and you are trying to use the value just after setState. It is not updating on the console.log() part because of the asynchronous nature of setState, it lets your further code to execute, while the value updating happens on the background. Thus you are getting the previous value. When the setState is completed on the background it will update the value and you will have access to that value on the next render.

如果有人有兴趣了解这个细节。这是一个关于这个话题的非常好的会议发言。

https://www.youtube.com/watch?v=8aGhZQkoFbQ

使用后台定时器库。它解决了我的问题。

const timeoutId = BackgroundTimer.setTimeout(() => {
    // This will be executed once after 1 seconds
    // even when the application is the background
    console.log('tac');
}, 1000);

如果我们必须只更新状态，那么更好的方法是使用push方法。

这是我的代码。我想从Firebase状态存储url。

const [imageUrl, setImageUrl] = useState([]);
const [reload, setReload] = useState(0);

useEffect(() => {
    if (reload === 4) {
        downloadUrl1();
    }
}, [reload]);


const downloadUrl = async () => {
    setImages([]);
    try {
        for (let i = 0; i < images.length; i++) {
            let url = await storage().ref(urls[i].path).getDownloadURL();
            imageUrl.push(url);
            setImageUrl([...imageUrl]);

            console.log(url, 'check', urls.length, 'length', imageUrl.length);
        }
    }
    catch (e) {
        console.log(e);
    }
};

const handleSubmit = async () => {
    setReload(4);
    await downloadUrl();
    console.log(imageUrl);
    console.log('post submitted');
};

这段代码将url置于数组状态。这可能对你也有用。

并不是说要这样做，但是没有useEffect做OP要求的事情并不难。

使用promise来解析setter函数体中的新状态:

const getState = <T>(
  setState: React.Dispatch<React.SetStateAction<T>>
): Promise<T> => {
  return new Promise((resolve) => {
    setState((currentState: T) => {
      resolve(currentState);
      return currentState;
    });
  });
};

这就是你如何使用它(示例显示了count和outOfSyncCount/syncCount在UI渲染中的比较):

const App: React.FC = () => {
  const [count, setCount] = useState(0);
  const [outOfSyncCount, setOutOfSyncCount] = useState(0);
  const [syncCount, setSyncCount] = useState(0);

  const handleOnClick = async () => {
    setCount(count + 1);

    // Doesn't work
    setOutOfSyncCount(count);

    // Works
    const newCount = await getState(setCount);
    setSyncCount(newCount);
  };

  return (
    <>
      <h2>Count = {count}</h2>
      <h2>Synced count = {syncCount}</h2>
      <h2>Out of sync count = {outOfSyncCount}</h2>
      <button onClick={handleOnClick}>Increment</button>
    </>
  );
};