刚开始使用Xcode 4.5,我在控制台得到了这个错误:

警告:试图在< ViewController: 0x1ec3e000>上显示< finishViewController: 0x1e56e0a0 >,其视图不在窗口层次结构中!

视图仍在显示,应用程序中的一切都在正常工作。这是iOS 6的新功能吗?

这是我用来在视图之间更改的代码:

UIStoryboard *storyboard = self.storyboard;
finishViewController *finished = 
[storyboard instantiateViewControllerWithIdentifier:@"finishViewController"];

[self presentViewController:finished animated:NO completion:NULL];

当前回答

要将任何子视图显示到主视图,请使用以下代码

UIViewController *yourCurrentViewController = [UIApplication sharedApplication].keyWindow.rootViewController;

while (yourCurrentViewController.presentedViewController) 
{
   yourCurrentViewController = yourCurrentViewController.presentedViewController;
}

[yourCurrentViewController presentViewController:composeViewController animated:YES completion:nil];

对于从主视图中解散任何子视图,请使用以下代码

UIViewController *yourCurrentViewController = [UIApplication sharedApplication].keyWindow.rootViewController;

while (yourCurrentViewController.presentedViewController) 
{
   yourCurrentViewController = yourCurrentViewController.presentedViewController;
}

[yourCurrentViewController dismissViewControllerAnimated:YES completion:nil];

其他回答

它工作得很好,试试这个。链接

UIViewController *top = [UIApplication sharedApplication].keyWindow.rootViewController;
[top presentViewController:secondView animated:YES completion: nil];

我修复了这个错误,将最顶部的视图控制器存储为常量,这是在rootViewController的while循环中发现的:

if var topController = UIApplication.shared.keyWindow?.rootViewController {
    while let presentedViewController = topController.presentedViewController {
        topController = presentedViewController
    }
    topController.present(controller, animated: false, completion: nil)
    // topController should now be your topmost view controller
}

我在Swift 4.2上也有类似的问题,但我的观点没有从视图周期中呈现出来。我发现我有多个segue要同时呈现。所以我使用dispatchAsyncAfter。

func updateView() {

 DispatchQueue.main.asyncAfter(deadline: .now() + 0.1) { [weak self] in

// for programmatically presenting view controller 
// present(viewController, animated: true, completion: nil)

//For Story board segue. you will also have to setup prepare segue for this to work. 
 self?.performSegue(withIdentifier: "Identifier", sender: nil)
  }
}

我也有同样的问题。问题是,performSegueWithIdentifier是由通知触发的,只要我把通知放在主线程上,警告消息就消失了。

斯威夫特5

我在viewDidLayoutSubviews中调用present,因为在viewDidAppear中呈现会在模态加载之前导致视图控制器的瞬间显示,这看起来像一个丑陋的故障

确保检查窗口是否存在并只执行一次代码

var alreadyPresentedVCOnDisplay = false

override func viewDidLayoutSubviews() {
        
    super.viewDidLayoutSubviews()
    
    // we call present in viewDidLayoutSubviews as
    // presenting in viewDidAppear causes a split second showing 
    // of the view controller before the modal is loaded
    
    guard let _ = view?.window else {
        // window must be assigned
        return
    }
    
    if !alreadyPresentedVCOnDisplay {
        alreadyPresentedVCOnDisplay = true
        present(...)
    }
    
}