See:

    /** 
     * Convert number of seconds into hours, minutes and seconds 
     * and return an array containing those values 
     * 
     * @param integer $inputSeconds Number of seconds to parse 
     * @return array 
     */ 

    function secondsToTime($inputSeconds) {

        $secondsInAMinute = 60;
        $secondsInAnHour  = 60 * $secondsInAMinute;
        $secondsInADay    = 24 * $secondsInAnHour;

        // extract days
        $days = floor($inputSeconds / $secondsInADay);

        // extract hours
        $hourSeconds = $inputSeconds % $secondsInADay;
        $hours = floor($hourSeconds / $secondsInAnHour);

        // extract minutes
        $minuteSeconds = $hourSeconds % $secondsInAnHour;
        $minutes = floor($minuteSeconds / $secondsInAMinute);

        // extract the remaining seconds
        $remainingSeconds = $minuteSeconds % $secondsInAMinute;
        $seconds = ceil($remainingSeconds);

        // return the final array
        $obj = array(
            'd' => (int) $days,
            'h' => (int) $hours,
            'm' => (int) $minutes,
            's' => (int) $seconds,
        );
        return $obj;
    }

From:将秒转换为日、时、分和秒

在java中你可以使用这种方法。

   private String getHmaa(long seconds) {
    String string;
    int hours = (int) seconds / 3600;
    int remainder = (int) seconds - hours * 3600;
    int mins = remainder / 60;
    //remainder = remainder - mins * 60;
    //int secs = remainder;

    if (hours < 12 && hours > 0) {
        if (mins < 10) {
            string = String.valueOf((hours < 10 ? "0" + hours : hours) + ":" + (mins > 0 ? "0" + mins : "0") + " AM");
        } else {
            string = String.valueOf((hours < 10 ? "0" + hours : hours) + ":" + (mins > 0 ? mins : "0") + " AM");
        }
    } else if (hours >= 12) {
        if (mins < 10) {
            string = String.valueOf(((hours - 12) < 10 ? "0" + (hours - 12) : ((hours - 12) == 12 ? "0" : (hours - 12))) + ":" + (mins > 0 ? "0" + mins : "0") + ((hours - 12) == 12 ? " AM" : " PM"));
        } else {
            string = String.valueOf(((hours - 12) < 10 ? "0" + (hours - 12) : ((hours - 12) == 12 ? "0" : (hours - 12))) + ":" + (mins > 0 ? mins : "0") + ((hours - 12) == 12 ? " AM" : " PM"));
        }
    } else {
        if (mins < 10) {
            string = String.valueOf("0" + ":" + (mins > 0 ? "0" + mins : "0") + " AM");
        } else {
            string = String.valueOf("0" + ":" + (mins > 0 ? mins : "0") + " AM");
        }
    }
    return string;
}

不知道为什么还没有提出这个建议，但是这里有一个使用DateInterval的变体，它的优点是秒> 86400不是问题(只是不要期望小时< 24)

noteable:该函数返回DateInterval对象，因此输出格式由调用者决定

function seconds2interval($seconds) {
    $s = intval($seconds);
    $hrs = floor($s / 3600);
    $min = floor(($s - ($hrs * 3600)) / 60);
    $sec = $s % 60;
    
    $duration = sprintf('PT%dH%dM%dS', $hrs, $min, $sec);
    $d = new DateInterval($duration);
    
    return $d;
}

$d = seconds2interval(93837.3113);  
echo $d->format('%H:%I:%s'); // 26:03:57

试试这个:

date("H:i:s",-57600 + 685);

从 http://bytes.com/topic/php/answers/3917-seconds-converted-hh-mm-ss

使用DateTime的一个简单方法是:

    $time = 60; //sec.
    $now = time();
    $rep = new DateTime('@'.$now);
    $diff = new DateTime('@'.($now+$time));
    $return = $diff->diff($rep)->format($format);

    //output:  01:04:65

这是一个简单的解决方案，让您能够使用DateTime的格式方法。

任何人在未来寻找这个，这给了最初的海报要求的格式。

$init = 685;
$hours = floor($init / 3600);
$hrlength=strlen($hours);
if ($hrlength==1) {$hrs="0".$hours;}
else {$hrs=$hours;} 

$minutes = floor(($init / 60) % 60);
$minlength=strlen($minutes);
if ($minlength==1) {$mins="0".$minutes;}
else {$mins=$minutes;} 

$seconds = $init % 60;
$seclength=strlen($seconds);
if ($seclength==1) {$secs="0".$seconds;}
else {$secs=$seconds;} 

echo "$hrs:$mins:$secs";