$given = 685;

 /*
 * In case $given == 86400, gmdate( "H" ) will convert it into '00' i.e. midnight.
 * We would need to take this into consideration, and so we will first
 * check the ratio of the seconds i.e. $given:$number_of_sec_in_a_day
 * and then after multiplying it by the number of hours in a day (24), we
 * will just use "floor" to get the number of hours as the rest would
 * be the minutes and seconds anyways.
 *
 * We can also have minutes and seconds combined in one variable,
 * e.g. $min_sec = gmdate( "i:s", $given );
 * But for versatility sake, I have taken them separately.
 */

$hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );

$min = gmdate( "i", $given );

$sec = gmdate( "s", $given );

echo $formatted_string = $hours.':'.$min.':'.$sec;

将其转换为函数:

function getHoursFormat( $given ){

 $hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );

 $min = gmdate( "i", $given );

 $sec = gmdate( "s", $given );

 $formatted_string = $hours.':'.$min.':'.$sec;

 return $formatted_string;

}

See:

    /** 
     * Convert number of seconds into hours, minutes and seconds 
     * and return an array containing those values 
     * 
     * @param integer $inputSeconds Number of seconds to parse 
     * @return array 
     */ 

    function secondsToTime($inputSeconds) {

        $secondsInAMinute = 60;
        $secondsInAnHour  = 60 * $secondsInAMinute;
        $secondsInADay    = 24 * $secondsInAnHour;

        // extract days
        $days = floor($inputSeconds / $secondsInADay);

        // extract hours
        $hourSeconds = $inputSeconds % $secondsInADay;
        $hours = floor($hourSeconds / $secondsInAnHour);

        // extract minutes
        $minuteSeconds = $hourSeconds % $secondsInAnHour;
        $minutes = floor($minuteSeconds / $secondsInAMinute);

        // extract the remaining seconds
        $remainingSeconds = $minuteSeconds % $secondsInAMinute;
        $seconds = ceil($remainingSeconds);

        // return the final array
        $obj = array(
            'd' => (int) $days,
            'h' => (int) $hours,
            'm' => (int) $minutes,
            's' => (int) $seconds,
        );
        return $obj;
    }

From:将秒转换为日、时、分和秒

$given = 685;

 /*
 * In case $given == 86400, gmdate( "H" ) will convert it into '00' i.e. midnight.
 * We would need to take this into consideration, and so we will first
 * check the ratio of the seconds i.e. $given:$number_of_sec_in_a_day
 * and then after multiplying it by the number of hours in a day (24), we
 * will just use "floor" to get the number of hours as the rest would
 * be the minutes and seconds anyways.
 *
 * We can also have minutes and seconds combined in one variable,
 * e.g. $min_sec = gmdate( "i:s", $given );
 * But for versatility sake, I have taken them separately.
 */

$hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );

$min = gmdate( "i", $given );

$sec = gmdate( "s", $given );

echo $formatted_string = $hours.':'.$min.':'.$sec;

将其转换为函数:

function getHoursFormat( $given ){

 $hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );

 $min = gmdate( "i", $given );

 $sec = gmdate( "s", $given );

 $formatted_string = $hours.':'.$min.':'.$sec;

 return $formatted_string;

}

给你

function format_time($t,$f=':') // t = seconds, f = separator 
{
  return sprintf("%02d%s%02d%s%02d", floor($t/3600), $f, ($t/60)%60, $f, $t%60);
}

echo format_time(685); // 00:11:25

我已经在这里解释过了 把答案也粘贴到这里

在23:59:59小时之前，您可以使用PHP默认函数

echo gmdate("H:i:s", 86399);

只会返回结果直到23:59:59

如果你的秒数大于86399 在@VolkerK的帮助下回答

$time = round($seconds);
echo sprintf('%02d:%02d:%02d', ($time/3600),($time/60%60), $time%60);

将是使用…的最佳选择。

下面是一个处理负秒和超过1天的秒的一行程序。

sprintf("%s:%'02s:%'02s\n", intval($seconds/60/60), abs(intval(($seconds%3600) / 60)), abs($seconds%60));

例如:

$seconds= -24*60*60 - 2*60*60 - 3*60 - 4; // minus 1 day 2 hours 3 minutes 4 seconds
echo sprintf("%s:%'02s:%'02s\n", intval($seconds/60/60), abs(intval(($seconds%3600) / 60)), abs($seconds%60));

输出:26:03:04