写这样的函数返回一个数组

function secondsToTime($seconds) {

  // extract hours
  $hours = floor($seconds / (60 * 60));

  // extract minutes
  $divisor_for_minutes = $seconds % (60 * 60);
  $minutes = floor($divisor_for_minutes / 60);

  // extract the remaining seconds
  $divisor_for_seconds = $divisor_for_minutes % 60;
  $seconds = ceil($divisor_for_seconds);

  // return the final array
  $obj = array(
      "h" => (int) $hours,
      "m" => (int) $minutes,
      "s" => (int) $seconds,
   );

  return $obj;
}

然后像这样简单地调用函数:

secondsToTime(100);

输出是

Array ( [h] => 0 [m] => 1 [s] => 40 )

See:

    /** 
     * Convert number of seconds into hours, minutes and seconds 
     * and return an array containing those values 
     * 
     * @param integer $inputSeconds Number of seconds to parse 
     * @return array 
     */ 

    function secondsToTime($inputSeconds) {

        $secondsInAMinute = 60;
        $secondsInAnHour  = 60 * $secondsInAMinute;
        $secondsInADay    = 24 * $secondsInAnHour;

        // extract days
        $days = floor($inputSeconds / $secondsInADay);

        // extract hours
        $hourSeconds = $inputSeconds % $secondsInADay;
        $hours = floor($hourSeconds / $secondsInAnHour);

        // extract minutes
        $minuteSeconds = $hourSeconds % $secondsInAnHour;
        $minutes = floor($minuteSeconds / $secondsInAMinute);

        // extract the remaining seconds
        $remainingSeconds = $minuteSeconds % $secondsInAMinute;
        $seconds = ceil($remainingSeconds);

        // return the final array
        $obj = array(
            'd' => (int) $days,
            'h' => (int) $hours,
            'm' => (int) $minutes,
            's' => (int) $seconds,
        );
        return $obj;
    }

From:将秒转换为日、时、分和秒

试试这个:

date("H:i:s",-57600 + 685);

从 http://bytes.com/topic/php/answers/3917-seconds-converted-hh-mm-ss

$given = 685;

 /*
 * In case $given == 86400, gmdate( "H" ) will convert it into '00' i.e. midnight.
 * We would need to take this into consideration, and so we will first
 * check the ratio of the seconds i.e. $given:$number_of_sec_in_a_day
 * and then after multiplying it by the number of hours in a day (24), we
 * will just use "floor" to get the number of hours as the rest would
 * be the minutes and seconds anyways.
 *
 * We can also have minutes and seconds combined in one variable,
 * e.g. $min_sec = gmdate( "i:s", $given );
 * But for versatility sake, I have taken them separately.
 */

$hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );

$min = gmdate( "i", $given );

$sec = gmdate( "s", $given );

echo $formatted_string = $hours.':'.$min.':'.$sec;

将其转换为函数:

function getHoursFormat( $given ){

 $hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );

 $min = gmdate( "i", $given );

 $sec = gmdate( "s", $given );

 $formatted_string = $hours.':'.$min.':'.$sec;

 return $formatted_string;

}

写这样的函数返回一个数组

function secondsToTime($seconds) {

  // extract hours
  $hours = floor($seconds / (60 * 60));

  // extract minutes
  $divisor_for_minutes = $seconds % (60 * 60);
  $minutes = floor($divisor_for_minutes / 60);

  // extract the remaining seconds
  $divisor_for_seconds = $divisor_for_minutes % 60;
  $seconds = ceil($divisor_for_seconds);

  // return the final array
  $obj = array(
      "h" => (int) $hours,
      "m" => (int) $minutes,
      "s" => (int) $seconds,
   );

  return $obj;
}

然后像这样简单地调用函数:

secondsToTime(100);

输出是

Array ( [h] => 0 [m] => 1 [s] => 40 )

使用DateTime的一个简单方法是:

    $time = 60; //sec.
    $now = time();
    $rep = new DateTime('@'.$now);
    $diff = new DateTime('@'.($now+$time));
    $return = $diff->diff($rep)->format($format);

    //output:  01:04:65

这是一个简单的解决方案，让您能够使用DateTime的格式方法。