我需要将秒转换为“小时:分钟:秒”。
例如:“685”转换为“00:11:25”
我怎样才能做到这一点呢?
我需要将秒转换为“小时:分钟:秒”。
例如:“685”转换为“00:11:25”
我怎样才能做到这一点呢?
当前回答
如果你需要在javascript中做到这一点,你可以在这里回答的一行代码中做到这一点,用javascript将秒转换为HH-MM-SS。用您想要转换的内容替换SECONDS。
var time = new Date(SECONDS * 1000).toISOString().substr(11, 8);
其他回答
function timeToSecond($time){
$time_parts=explode(":",$time);
$seconds= ($time_parts[0]*86400) + ($time_parts[1]*3600) + ($time_parts[2]*60) + $time_parts[3] ;
return $seconds;
}
function secondToTime($time){
$seconds = $time % 60;
$seconds<10 ? "0".$seconds : $seconds;
if($seconds<10) {
$seconds="0".$seconds;
}
$time = ($time - $seconds) / 60;
$minutes = $time % 60;
if($minutes<10) {
$minutes="0".$minutes;
}
$time = ($time - $minutes) / 60;
$hours = $time % 24;
if($hours<10) {
$hours="0".$hours;
}
$days = ($time - $hours) / 24;
if($days<10) {
$days="0".$days;
}
$time_arr = array($days,$hours,$minutes,$seconds);
return implode(":",$time_arr);
}
<?php
$time=3*3600 + 30*60;
$year=floor($time/(365*24*60*60));
$time-=$year*(365*24*60*60);
$month=floor($time/(30*24*60*60));
$time-=$month*(30*24*60*60);
$day=floor($time/(24*60*60));
$time-=$day*(24*60*60);
$hour=floor($time/(60*60));
$time-=$hour*(60*60);
$minute=floor($time/(60));
$time-=$minute*(60);
$second=floor($time);
$time-=$second;
if($year>0){
echo $year." year, ";
}
if($month>0){
echo $month." month, ";
}
if($day>0){
echo $day." day, ";
}
if($hour>0){
echo $hour." hour, ";
}
if($minute>0){
echo $minute." minute, ";
}
if($second>0){
echo $second." second, ";
}
试试这个:
date("H:i:s",-57600 + 685);
从 http://bytes.com/topic/php/answers/3917-seconds-converted-hh-mm-ss
不知道为什么还没有提出这个建议,但是这里有一个使用DateInterval的变体,它的优点是秒> 86400不是问题(只是不要期望小时< 24)
noteable:该函数返回DateInterval对象,因此输出格式由调用者决定
function seconds2interval($seconds) {
$s = intval($seconds);
$hrs = floor($s / 3600);
$min = floor(($s - ($hrs * 3600)) / 60);
$sec = $s % 60;
$duration = sprintf('PT%dH%dM%dS', $hrs, $min, $sec);
$d = new DateInterval($duration);
return $d;
}
$d = seconds2interval(93837.3113);
echo $d->format('%H:%I:%s'); // 26:03:57
$given = 685;
/*
* In case $given == 86400, gmdate( "H" ) will convert it into '00' i.e. midnight.
* We would need to take this into consideration, and so we will first
* check the ratio of the seconds i.e. $given:$number_of_sec_in_a_day
* and then after multiplying it by the number of hours in a day (24), we
* will just use "floor" to get the number of hours as the rest would
* be the minutes and seconds anyways.
*
* We can also have minutes and seconds combined in one variable,
* e.g. $min_sec = gmdate( "i:s", $given );
* But for versatility sake, I have taken them separately.
*/
$hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );
$min = gmdate( "i", $given );
$sec = gmdate( "s", $given );
echo $formatted_string = $hours.':'.$min.':'.$sec;
将其转换为函数:
function getHoursFormat( $given ){
$hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );
$min = gmdate( "i", $given );
$sec = gmdate( "s", $given );
$formatted_string = $hours.':'.$min.':'.$sec;
return $formatted_string;
}