下面是一个处理负秒和超过1天的秒的一行程序。

sprintf("%s:%'02s:%'02s\n", intval($seconds/60/60), abs(intval(($seconds%3600) / 60)), abs($seconds%60));

例如:

$seconds= -24*60*60 - 2*60*60 - 3*60 - 4; // minus 1 day 2 hours 3 minutes 4 seconds
echo sprintf("%s:%'02s:%'02s\n", intval($seconds/60/60), abs(intval(($seconds%3600) / 60)), abs($seconds%60));

输出:26:03:04

试试这个:

date("H:i:s",-57600 + 685);

从 http://bytes.com/topic/php/answers/3917-seconds-converted-hh-mm-ss

使用DateTime的一个简单方法是:

    $time = 60; //sec.
    $now = time();
    $rep = new DateTime('@'.$now);
    $diff = new DateTime('@'.($now+$time));
    $return = $diff->diff($rep)->format($format);

    //output:  01:04:65

这是一个简单的解决方案，让您能够使用DateTime的格式方法。

给你

function format_time($t,$f=':') // t = seconds, f = separator 
{
  return sprintf("%02d%s%02d%s%02d", floor($t/3600), $f, ($t/60)%60, $f, $t%60);
}

echo format_time(685); // 00:11:25

我已经在这里解释过了 把答案也粘贴到这里

在23:59:59小时之前，您可以使用PHP默认函数

echo gmdate("H:i:s", 86399);

只会返回结果直到23:59:59

如果你的秒数大于86399 在@VolkerK的帮助下回答

$time = round($seconds);
echo sprintf('%02d:%02d:%02d', ($time/3600),($time/60%60), $time%60);

将是使用…的最佳选择。

写这样的函数返回一个数组

function secondsToTime($seconds) {

  // extract hours
  $hours = floor($seconds / (60 * 60));

  // extract minutes
  $divisor_for_minutes = $seconds % (60 * 60);
  $minutes = floor($divisor_for_minutes / 60);

  // extract the remaining seconds
  $divisor_for_seconds = $divisor_for_minutes % 60;
  $seconds = ceil($divisor_for_seconds);

  // return the final array
  $obj = array(
      "h" => (int) $hours,
      "m" => (int) $minutes,
      "s" => (int) $seconds,
   );

  return $obj;
}

然后像这样简单地调用函数:

secondsToTime(100);

输出是

Array ( [h] => 0 [m] => 1 [s] => 40 )