如何从月份编号中获得月份名称?
例如,如果我有3,我想返回march
date.tm_month()
如何获得弦乐进行曲?
如何从月份编号中获得月份名称?
例如,如果我有3,我想返回march
date.tm_month()
如何获得弦乐进行曲?
当前回答
这就是我要做的:
from datetime import *
months = ["Unknown",
"January",
"Febuary",
"March",
"April",
"May",
"June",
"July",
"August",
"September",
"October",
"November",
"December"]
now = (datetime.now())
year = (now.year)
month = (months[now.month])
print(month)
输出:
>>> September
(这是我写这篇文章的真实日期)
其他回答
这就是我要做的:
from datetime import *
months = ["Unknown",
"January",
"Febuary",
"March",
"April",
"May",
"June",
"July",
"August",
"September",
"October",
"November",
"December"]
now = (datetime.now())
year = (now.year)
month = (months[now.month])
print(month)
输出:
>>> September
(这是我写这篇文章的真实日期)
如果(像我一样)你在数据框架中有一列月份数字,我会提供这个:
df['monthName'] = df['monthNumer'].apply(lambda x: calendar.month_name[x])
日历火
从那里你可以看到那个日历。month_name[3]将返回March,数组索引为0是空字符串,因此也不需要担心零索引。
import datetime
mydate = datetime.datetime.now()
mydate.strftime("%B")
返回:12月
更多信息请访问Python文档网站
[编辑:来自@GiriB的精彩评论]你也可以使用%b,它返回月份名称的简短符号。
mydate.strftime("%b")
对于上面的例子,它将返回12月12日。
一次打印所有月份:
import datetime
monthint = list(range(1,13))
for X in monthint:
month = datetime.date(1900, X , 1).strftime('%B')
print(month)