如果你只有月份号而没有datetime实例，你可以构建一个小函数来映射number和label，如下所示:

def monthname(m):
    d={1:'En',2:'Fe',3:'Mr',4:'Ab',5:'My',6:'Jn',7:'Jl',8:'Ag',9:'Se',10:'Oc',11:'No',12:'Di'}
    return d[m]

这个脚本展示了如何获得数据帧中月份变量/列的日历月缩写。注意，假设month列/变量的值都是数字，可能会有一些缺失的值。

# Import the calendar module
  import calendar
    
# Extract month as a number from the date column
  df['Month']=pd.DatetimeIndex(df['Date']).month

# Using list comprehension extract month abbreviations for each month number
 df['Month_abbr']=[calendar.month_abbr[int(i)] if pd.notna(i) else i for i in df['Month']]

我创建了自己的函数，将数字转换为对应的月份。

def month_name (number):
    if number == 1:
        return "January"
    elif number == 2:
        return "February"
    elif number == 3:
        return "March"
    elif number == 4:
        return "April"
    elif number == 5:
        return "May"
    elif number == 6:
        return "June"
    elif number == 7:
        return "July"
    elif number == 8:
        return "August"
    elif number == 9:
        return "September"
    elif number == 10:
        return "October"
    elif number == 11:
        return "November"
    elif number == 12:
        return "December"

然后我可以调用函数。例如:

print (month_name (12))

输出:

>>> December

如果(像我一样)你在数据框架中有一列月份数字，我会提供这个:

df['monthName'] = df['monthNumer'].apply(lambda x: calendar.month_name[x])

import datetime

monthinteger = 4

month = datetime.date(1900, monthinteger, 1).strftime('%B')

print month

4月

如果你只有月份号而没有datetime实例，你可以构建一个小函数来映射number和label，如下所示:

def monthname(m):
    d={1:'En',2:'Fe',3:'Mr',4:'Ab',5:'My',6:'Jn',7:'Jl',8:'Ag',9:'Se',10:'Oc',11:'No',12:'Di'}
    return d[m]