如何从月份编号中获得月份名称?

例如,如果我有3,我想返回march

date.tm_month()

如何获得弦乐进行曲?


当前回答

import datetime
mydate = datetime.datetime.now()
mydate.strftime("%B") # 'December'
mydate.strftime("%b") # 'dec'

其他回答

如果(像我一样)你在数据框架中有一列月份数字,我会提供这个:

df['monthName'] = df['monthNumer'].apply(lambda x: calendar.month_name[x])

如果你只需要知道给定数字(1 - 12)的月份名称,这就不太有用了,因为当前日期并不重要。

calendar.month_name[我]

or

calendar.month_abbr[我]

在这里更有用。

这里有一个例子:

import calendar

for month_idx in range(1, 13):
    print (calendar.month_name[month_idx])
    print (calendar.month_abbr[month_idx])
    print ("")

样例输出:

January
Jan

February
Feb

March
Mar

...

datetime -基本日期和时间类型- Python文档

所有strftime格式代码的列表。月份的名称,以及格式化左零填充之类的好东西。阅读整页的内容,比如“天真”参数的规则。以下是清单的简要内容:

%a  Sun, Mon, …, Sat 
%A  Sunday, Monday, …, Saturday 
%w  Weekday as number, where 0 is Sunday 
%d  Day of the month 01, 02, …, 31
%b  Jan, Feb, …, Dec
%B  January, February, …, December
%m  Month number as a zero-padded 01, 02, …, 12
%y  2 digit year zero-padded 00, 01, …, 99
%Y  4 digit Year 1970, 1988, 2001, 2013
%H  Hour (24-hour clock) zero-padded 00, 01, …, 23
%I  Hour (12-hour clock) zero-padded 01, 02, …, 12
%p  AM or PM.
%M  Minute zero-padded 00, 01, …, 59
%S  Second zero-padded 00, 01, …, 59
%f  Microsecond zero-padded 000000, 000001, …, 999999
%z  UTC offset in the form +HHMM or -HHMM   +0000, -0400, +1030
%Z  Time zone name  UTC, EST, CST
%j  Day of the year zero-padded 001, 002, …, 366
%U  Week number of the year zero padded, Days before the first Sunday are week 0
%W  Week number of the year (Monday as first day)
%c  Locale’s date and time representation. Tue Aug 16 21:30:00 1988
%x  Locale’s date representation. 08/16/1988 (en_US)
%X  Locale’s time representation. 21:30:00 
%%  literal '%' character.
import datetime
mydate = datetime.datetime.now()
mydate.strftime("%B") # 'December'
mydate.strftime("%b") # 'dec'

'01'到'Jan'

from datetime import datetime

datetime.strptime('01', "%m").strftime("%b")