如何在c#中计算两个日期之间的月差?
c#中是否有相当于VB的DateDiff()方法。我需要找出相隔数年的两个日期之间的月差。文档说我可以像这样使用TimeSpan:
TimeSpan ts = date1 - date2;
但这里的数据是以天为单位的。我不想把这个数字除以30,因为不是每个月都是30天,而且两个操作数的值相差很大,所以我担心除以30可能会得到错误的值。
有什么建议吗?
如何在c#中计算两个日期之间的月差?
c#中是否有相当于VB的DateDiff()方法。我需要找出相隔数年的两个日期之间的月差。文档说我可以像这样使用TimeSpan:
TimeSpan ts = date1 - date2;
但这里的数据是以天为单位的。我不想把这个数字除以30,因为不是每个月都是30天,而且两个操作数的值相差很大,所以我担心除以30可能会得到错误的值。
有什么建议吗?
当前回答
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
label3.Text = new DateDifference(Convert.ToDateTime("2018-09-13"), Convert.ToDateTime("2018-11-15")).ToString();
label2.Text = new DateDifference(Convert.ToDateTime("2018-10-12"), Convert.ToDateTime("2018-11-15")).ToString();
DateDifference oDateDifference = new DateDifference(Convert.ToDateTime("2018-11-12"));
label1.Text = oDateDifference.ToString();
}
}
public class DateDifference
{
public DateTime start { get; set; }
public DateTime currentDAte { get; set; }
public DateTime origstart { get; set; }
public DateTime origCurrentDAte { get; set; }
int days { get; set; }
int months { get; set; }
int years { get; set; }
public DateDifference(DateTime postedDate, DateTime currentDAte)
{
this.start = this.removeTime(postedDate);
this.currentDAte = this.removeTime(currentDAte);
this.origstart = postedDate;
this.origCurrentDAte = currentDAte;
}
public DateDifference(DateTime postedDate)
{
DateTime currentDate_ = DateTime.Now;
this.start = this.removeTime(postedDate);
this.currentDAte = this.removeTime(currentDate_);
this.origstart = postedDate;
this.origCurrentDAte = currentDate_;
if (start > this.currentDAte)
{
throw new Exception("Current date is greater than date posted");
}
this.compute();
}
void compute()
{
while (this.start.Year <= this.currentDAte.Year)
{
if (this.start.Year <= this.currentDAte.Year && (this.start.AddMonths(1) <= this.currentDAte))
{
++this.months;
this.start = this.start.AddMonths(1);
}
if ((this.start.Year == this.currentDAte.Year) && (this.start >= this.currentDAte.AddMonths(-1) && this.start <= this.currentDAte))
{
break;
}
}
while (this.start.DayOfYear < this.currentDAte.DayOfYear)
{
++this.days;
this.start = start.AddDays(1);
}
if (this.months > 11)
{
while (this.months > 11)
{
++this.years;
this.months = months - 12;
}
}
}
public override string ToString()
{
if (this.start > this.currentDAte)
{
throw new Exception("Current date is greater than date posted");
}
String ret = this.ComposeTostring();
this.reset();
return ret;
}
private String ComposeTostring()
{
this.compute();
if (this.years > 0)
{
if (this.months > 0)
{
if (this.days > 0)
{
return String.Format("{0} year{1}, {2} month{3} && {4} Day{5} ago", this.years, plural(this.years), this.months, plural(this.months), this.days, plural(this.days));
}
return String.Format("{0} year{1}, {2} month{3} ago", this.years, plural(this.years), this.months, plural(this.months));
}
else
{
if (this.days > 0)
{
return String.Format("{0} year{1},{2} day{3} ago", this.years, plural(this.years), this.days, plural(this.days));
}
return String.Format("{0} year{1} ago", this.years, plural(this.years));
}
}
if (this.months > 0)
{
if (this.days > 0)
{
return String.Format("{0} month{1}, {2} day{3} ago", this.months, plural(this.months), this.days, plural(this.days));
}
else
{
return String.Format("{0} month{1} ago", this.months, plural(this.months));
}
}
if ((this.origCurrentDAte - this.origstart).Days > 0)
{
int daysDiff = (this.origCurrentDAte - this.origstart).Days;
this.origstart = this.origstart.AddDays(daysDiff);
int HoursDiff = (this.origCurrentDAte - this.origstart).Hours;
return String.Format("{0} day{1}, {2} hour{3} ago", daysDiff, plural(daysDiff), HoursDiff, plural(HoursDiff));
}
else if ((this.origCurrentDAte - this.origstart).Hours > 0)
{
int HoursDiff = (this.origCurrentDAte - this.origstart).Hours;
this.origstart = this.origstart.AddHours(HoursDiff);
int MinDiff = (this.origCurrentDAte - this.origstart).Minutes;
return String.Format("{0} hour{1}, {2} minute{3} ago", HoursDiff, plural(HoursDiff), MinDiff, plural(MinDiff));
}
else if ((this.origCurrentDAte - this.origstart).Minutes > 0)
{
int MinDiff = (this.origCurrentDAte - this.origstart).Minutes;
this.origstart = this.origstart.AddMinutes(MinDiff);
int SecDiff = (this.origCurrentDAte - this.origstart).Seconds;
return String.Format("{0} minute{1}, {2} second{3} ago", MinDiff, plural(MinDiff), SecDiff, plural(SecDiff));
}
else if ((this.origCurrentDAte - this.origstart).Seconds > 0)
{
int sec = (this.origCurrentDAte - this.origstart).Seconds;
return String.Format("{0} second{1}", sec, plural(sec));
}
return "";
}
String plural(int val)
{
return (val > 1 ? "s" : String.Empty);
}
DateTime removeTime(DateTime dtime)
{
dtime = dtime.AddHours(-dtime.Hour);
dtime = dtime.AddMinutes(-dtime.Minute);
dtime = dtime.AddSeconds(-dtime.Second);
return dtime;
}
public void reset()
{
this.days = 0;
this.months = 0;
this.years = 0;
this.start = DateTime.MinValue;
this.currentDAte = DateTime.MinValue;
this.origstart = DateTime.MinValue;
this.origCurrentDAte = DateTime.MinValue;
}
}
其他回答
在这个问题上没有很多明确的答案,因为你总是在假设事情。
这个解决方案在两个日期之间进行计算,假设您想保存一个月中的某一天进行比较,(这意味着在计算中考虑了这个月中的某一天)
例如,如果你的日期是2012年1月30日,2012年2月29日就不是一个月,但2013年3月1日就不是一个月。
它经过了相当彻底的测试,可能稍后我们会在使用时清理它,但这里:
private static int TotalMonthDifference(DateTime dtThis, DateTime dtOther)
{
int intReturn = 0;
bool sameMonth = false;
if (dtOther.Date < dtThis.Date) //used for an error catch in program, returns -1
intReturn--;
int dayOfMonth = dtThis.Day; //captures the month of day for when it adds a month and doesn't have that many days
int daysinMonth = 0; //used to caputre how many days are in the month
while (dtOther.Date > dtThis.Date) //while Other date is still under the other
{
dtThis = dtThis.AddMonths(1); //as we loop, we just keep adding a month for testing
daysinMonth = DateTime.DaysInMonth(dtThis.Year, dtThis.Month); //grabs the days in the current tested month
if (dtThis.Day != dayOfMonth) //Example 30 Jan 2013 will go to 28 Feb when a month is added, so when it goes to march it will be 28th and not 30th
{
if (daysinMonth < dayOfMonth) // uses day in month max if can't set back to day of month
dtThis.AddDays(daysinMonth - dtThis.Day);
else
dtThis.AddDays(dayOfMonth - dtThis.Day);
}
if (((dtOther.Year == dtThis.Year) && (dtOther.Month == dtThis.Month))) //If the loop puts it in the same month and year
{
if (dtOther.Day >= dayOfMonth) //check to see if it is the same day or later to add one to month
intReturn++;
sameMonth = true; //sets this to cancel out of the normal counting of month
}
if ((!sameMonth)&&(dtOther.Date > dtThis.Date))//so as long as it didn't reach the same month (or if i started in the same month, one month ahead, add a month)
intReturn++;
}
return intReturn; //return month
}
能够计算以月为单位的两个日期之间的差异是一件非常符合逻辑的事情,并且在许多业务应用程序中都需要它。这里的几个程序员提供了一些评论,比如“2010年5月1日”和“2010年6月16日”之间的月份有什么不同,2010年12月31日和2011年1月1日之间的月份有什么不同?——无法理解商业应用的基本知识。
以下是以上2条评论的答案——2010年5月1日至2010年6月16日之间的月数为1个月,2010年12月31日至2011年1月1日之间的月数为0。如上面的程序员所建议的那样,将它们计算为1.5个月零1秒是非常愚蠢的。
从事过信用卡、抵押贷款处理、税务处理、租金处理、每月利息计算和其他各种业务解决方案的人会同意这一点。
问题是c#或VB中不包含这样的函数。NET。Datediff只考虑年份或月份组件,因此实际上是无用的。
下面是一些现实生活中的例子,你需要正确地计算月份:
你从2月18日到8月23日住在短租公寓里。你在那里呆了几个月?答案很简单——6个月
你有一个银行账户,每月月底计算并支付利息。您在6月10日存入,同年10月29日取出。你有多少个月的利息?非常简单的答案——4个月(额外的日子也没关系)
在业务应用中,大多数情况下,当您需要计算月份时,是因为您需要根据人类计算时间的方式了解“完整的”月份;而不是基于一些抽象/无关的想法。
这个简单的静态函数计算两个Datetimes之间的月份分数。
1.1. 到31.1。= 1.0 1.4. 到15.4。= 0.5 16.4. 到30.4。= 0.5 1.3. 到1.4。= 1 + 1/30
该函数假设第一个日期比第二个日期小。要处理负时间间隔,可以通过在开始时引入符号和变量交换来轻松地修改函数。
public static double GetDeltaMonths(DateTime t0, DateTime t1)
{
DateTime t = t0;
double months = 0;
while(t<=t1)
{
int daysInMonth = DateTime.DaysInMonth(t.Year, t.Month);
DateTime endOfMonth = new DateTime(t.Year, t.Month, daysInMonth);
int cutDay = endOfMonth <= t1 ? daysInMonth : t1.Day;
months += (cutDay - t.Day + 1) / (double) daysInMonth;
t = new DateTime(t.Year, t.Month, 1).AddMonths(1);
}
return Math.Round(months,2);
}
假设这个月的日期不相关(即2011.1.1和2010.12.31之间的差为1),date1 > date2为正值,date2 > date1为负值
((date1.Year - date2.Year) * 12) + date1.Month - date2.Month
或者,假设你想要两个日期之间的“平均月”的大致数字,下面的方法应该适用于所有日期,但日期差异非常大。
date1.Subtract(date2).Days / (365.25 / 12)
注意,如果您要使用后一种解决方案,那么您的单元测试应该声明应用程序设计使用的最宽日期范围,并相应地验证计算结果。
更新(感谢Gary)
如果使用“平均月份”方法,“每年平均天数”的更准确数字是365.2425。
似乎DateTimeSpan解决方案使许多人满意。我不知道。让我们考虑一下:
BeginDate = 1972/2/29销售= 1972/4/28。
基于DateTimeSpan的答案是:
1年(s), 2个月(s)和0天(s)
我实现了一个方法,在此基础上,答案是:
1年、1个月及28天
显然没有两个月的时间。我想说的是,因为我们在开始日期的月末,剩下的实际上是整个3月加上结束日期(4月)的月份所经过的天数,所以1个月零28天。
如果你读到这里,你有兴趣,我把方法贴在下面。我在评论中解释了我所做的假设,因为有多少个月,月份的概念是一个不断变化的目标。多次测试,看看答案是否有意义。我通常选择相邻年份的考试日期,一旦我确认了答案,我就会前后移动一两天。到目前为止,它看起来不错,我相信你会发现一些bug:D。代码可能看起来有点粗糙,但我希望它足够清楚:
static void Main(string[] args) {
DateTime EndDate = new DateTime(1973, 4, 28);
DateTime BeginDate = new DateTime(1972, 2, 29);
int years, months, days;
GetYearsMonthsDays(EndDate, BeginDate, out years, out months, out days);
Console.WriteLine($"{years} year(s), {months} month(s) and {days} day(s)");
}
/// <summary>
/// Calculates how many years, months and days are between two dates.
/// </summary>
/// <remarks>
/// The fundamental idea here is that most of the time all of us agree
/// that a month has passed today since the same day of the previous month.
/// A particular case is when both days are the last days of their respective months
/// when again we can say one month has passed.
/// In the following cases the idea of a month is a moving target.
/// - When only the beginning date is the last day of the month then we're left just with
/// a number of days from the next month equal to the day of the month that end date represent
/// - When only the end date is the last day of its respective month we clearly have a
/// whole month plus a few days after the the day of the beginning date until the end of its
/// respective months
/// In all the other cases we'll check
/// - beginingDay > endDay -> less then a month just daysToEndofBeginingMonth + dayofTheEndMonth
/// - beginingDay < endDay -> full month + (endDay - beginingDay)
/// - beginingDay == endDay -> one full month 0 days
///
/// </remarks>
///
private static void GetYearsMonthsDays(DateTime EndDate, DateTime BeginDate, out int years, out int months, out int days ) {
var beginMonthDays = DateTime.DaysInMonth(BeginDate.Year, BeginDate.Month);
var endMonthDays = DateTime.DaysInMonth(EndDate.Year, EndDate.Month);
// get the full years
years = EndDate.Year - BeginDate.Year - 1;
// how many full months in the first year
var firstYearMonths = 12 - BeginDate.Month;
// how many full months in the last year
var endYearMonths = EndDate.Month - 1;
// full months
months = firstYearMonths + endYearMonths;
days = 0;
// Particular end of month cases
if(beginMonthDays == BeginDate.Day && endMonthDays == EndDate.Day) {
months++;
}
else if(beginMonthDays == BeginDate.Day) {
days += EndDate.Day;
}
else if(endMonthDays == EndDate.Day) {
days += beginMonthDays - BeginDate.Day;
}
// For all the other cases
else if(EndDate.Day > BeginDate.Day) {
months++;
days += EndDate.Day - BeginDate.Day;
}
else if(EndDate.Day < BeginDate.Day) {
days += beginMonthDays - BeginDate.Day;
days += EndDate.Day;
}
else {
months++;
}
if(months >= 12) {
years++;
months = months - 12;
}
}