如何保持onItemSelected从发射上一个新实例化的旋转器?

我想过一些不那么优雅的方法来解决这个问题，但我知道我一定遗漏了什么。

我的onItemSelected立即启动，没有与用户进行任何交互，这是不希望的行为。我希望UI能够等到用户选择某样东西后再执行任何操作。

我甚至尝试在onResume()中设置监听器，希望能有所帮助，但它没有。

我怎样才能阻止它在用户可以触摸控件之前发射?

public class CMSHome extends Activity { 

private Spinner spinner;

@Override
    public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    // Heres my spinner ///////////////////////////////////////////
    spinner = (Spinner) findViewById(R.id.spinner);
    ArrayAdapter<CharSequence> adapter = ArrayAdapter.createFromResource(
            this, R.array.pm_list, android.R.layout.simple_spinner_item);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    spinner.setAdapter(adapter);
    };

public void onResume() {
    super.onResume();
    spinner.setOnItemSelectedListener(new MyOnItemSelectedListener());
}

    public class MyOnItemSelectedListener implements OnItemSelectedListener {

    public void onItemSelected(AdapterView<?> parent,
        View view, int pos, long id) {

     Intent i = new Intent(CMSHome.this, ListProjects.class);
     i.putExtra("bEmpID", parent.getItemAtPosition(pos).toString());
        startActivity(i);

        Toast.makeText(parent.getContext(), "The pm is " +
          parent.getItemAtPosition(pos).toString(), Toast.LENGTH_LONG).show();
    }

    public void onNothingSelected(AdapterView parent) {
      // Do nothing.
    }
}
}

当前回答

我用最简单的方法做到了:

private AdapterView.OnItemSelectedListener listener;
private Spinner spinner;

onCreate ();

spinner = (Spinner) findViewById(R.id.spinner);

listener = new AdapterView.OnItemSelectedListener() {
        @Override
        public void onItemSelected(AdapterView<?> adapterView, View view, int position, long l) {

            Log.i("H - Spinner selected position", position);
        }

        @Override
        public void onNothingSelected(AdapterView<?> adapterView) {

        }
    };

 spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
        @Override
        public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) {
            spinner.setOnItemSelectedListener(listener);
        }

        @Override
        public void onNothingSelected(AdapterView<?> adapterView) {

        }
    });

Done

2015-04-13 09:45:12

其他回答

没有不必要的事件从布局阶段，如果你推迟添加监听器，直到布局完成:

spinner.getViewTreeObserver().addOnGlobalLayoutListener(
    new ViewTreeObserver.OnGlobalLayoutListener() {
        @Override
        public void onGlobalLayout() {
            // Ensure you call it only once works for JELLY_BEAN and later
            spinner.getViewTreeObserver().removeOnGlobalLayoutListener(this);

            // add the listener
            spinner.setOnItemSelectedListener(new OnItemSelectedListener() {

                @Override
                public void onItemSelected(AdapterView<?> parent, View view, int pos, long id) {
                    // check if pos has changed
                    // then do your work
                }

                @Override
                public void onNothingSelected(AdapterView<?> arg0) {
                }

            });

        }
    });

2015-07-29 15:22:57

这不是一个特别优雅的解决方案，但我发现它工作可靠。简单地在onResume中设置一个延迟线程上的侦听器。然后你可以自由地做任何你喜欢的初始化，UI会做出任何布局的改变，然后设置监听器。

Thread t = new Thread(){
            public void run() {
                try{                
                    Thread.sleep(1000);
                    getActivity().runOnUiThread(new Runnable() {                        
                        @Override
                        public void run() {
                            setSpinnerListeners();

                        }
                    });
                }
                catch(Exception e){
                    e.printStackTrace();
                }
            };
        };
        t.start();

2015-07-08 17:56:55

if () {        
       spinner.setSelection(0);// No reaction to create spinner !!!
     } else {
        spinner.setSelection(intPosition);
     }


spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {

    @Override
    public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {

         if (position > 0) {
           // real selection
         }

      }

    @Override
    public void onNothingSelected(AdapterView<?> parent) {

     }
});

2015-09-13 14:39:12

这不是一个完美的解决方案，但如果你喜欢将起始字符串作为一个占位符，你可以添加占位符弹簧值("Day_of_Work_Out")

  @Override
        public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
            String name = (String) parent.getItemAtPosition(position);
            if (name.equals("Day_of_Work_Out")) {

            }else {

                workOutD = name;
                Intent intent = new Intent();
                workOutNam = workOutName.getText().toString();

                if (workOutNam == null) {

                    startActivity(intent);
                    Log.i("NewWorkOutActivity","Name is null");

                }else {
                    Log.i("NewWorkOutActivity","Name Not null");
                    Toast.makeText(NewWorkOutActivity.this, "Please Select a Day", Toast.LENGTH_LONG).show();
                }


            }
        }

2017-04-26 22:41:35

我会尽量打电话的

spinner.setOnItemSelectedListener(new MyOnItemSelectedListener());

在调用setAdapter()之后。还可以尝试在适配器之前进行调用。

您总是有子类化的解决方案，在子类化中，您可以将一个布尔标志包装到覆盖的setAdapter方法以跳过事件。

2010-04-01 18:26:30

如何保持onItemSelected从发射上一个新实例化的旋转器?

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