我喜欢使用基于NOT EXIST的解决方案来解决这个问题：

SELECT 
  id, 
  rev
  -- you can select other columns here
FROM YourTable t
WHERE NOT EXISTS (
   SELECT * FROM YourTable t WHERE t.id = id AND rev > t.rev
)

这将选择组中具有最大值的所有记录，并允许您选择其他列。

这个怎么样：

SELECT all_fields.*  
FROM (SELECT id, MAX(rev) FROM yourtable GROUP BY id) AS max_recs  
LEFT OUTER JOIN yourtable AS all_fields 
ON max_recs.id = all_fields.id

像这样吗？

SELECT yourtable.id, rev, content
FROM yourtable
INNER JOIN (
    SELECT id, max(rev) as maxrev
    FROM yourtable
    GROUP BY id
) AS child ON (yourtable.id = child.id) AND (yourtable.rev = maxrev)

下面是另一个解决方案，用于仅检索具有该字段最大值的字段的记录。这适用于我工作的平台SQL400。在本例中，字段FIELD5中具有最大值的记录将由以下SQL语句检索。

SELECT A.KEYFIELD1, A.KEYFIELD2, A.FIELD3, A.FIELD4, A.FIELD5
  FROM MYFILE A
 WHERE RRN(A) IN
   (SELECT RRN(B) 
      FROM MYFILE B
     WHERE B.KEYFIELD1 = A.KEYFIELD1 AND B.KEYFIELD2 = A.KEYFIELD2
     ORDER BY B.FIELD5 DESC
     FETCH FIRST ROW ONLY)

这是另一个解决方案，希望它能帮助某人

Select a.id , a.rev, a.content from Table1 a
inner join 
(SELECT id, max(rev) rev FROM Table1 GROUP BY id) x on x.id =a.id and x.rev =a.rev

按相反顺序对rev字段进行排序，然后按id进行分组，每个分组的第一行是rev值最高的一行。

SELECT * FROM (SELECT * FROM table1 ORDER BY id, rev DESC) X GROUP BY X.id;

测试时间：http://sqlfiddle.com/具有以下数据

CREATE TABLE table1
    (`id` int, `rev` int, `content` varchar(11));

INSERT INTO table1
    (`id`, `rev`, `content`)
VALUES
    (1, 1, 'One-One'),
    (1, 2, 'One-Two'),
    (2, 1, 'Two-One'),
    (2, 2, 'Two-Two'),
    (3, 2, 'Three-Two'),
    (3, 1, 'Three-One'),
    (3, 3, 'Three-Three')
;

这在MySql 5.5和5.6中给出了以下结果

id  rev content
1   2   One-Two
2   2   Two-Two
3   3   Three-Two