在.NET中，GetHashCode方法在整个.NET基类库的许多地方都使用。正确执行它对于在集合中或确定相等时快速查找项目尤为重要。
对于如何为自定义类实现GetHashCode，是否有标准算法或最佳实践，以便不会降低性能？
当前回答
使用System.HashCode
如果使用的是.NET Standard 2.1或更高版本，则可以使用System.HashCode结构。在早期的框架中，它可以从Microsoft.Bcl.HashCode包中获得。有两种使用方法：
HashCode.Combine
Combine方法可用于创建哈希代码，最多可提供八个对象。
public override int GetHashCode() => HashCode.Combine(this.object1, this.object2);
HashCode.添加
Add方法帮助您处理集合：
public override int GetHashCode()
{
var hashCode = new HashCode();
hashCode.Add(this.object1);
foreach (var item in this.collection)
{
hashCode.Add(item);
}
return hashCode.ToHashCode();
}
GetHashCode变得简单
System.HashCode的替代品，超级容易使用，但速度仍然很快。您可以阅读完整的博客文章“GetHashCode Made Easy”以了解更多详细信息和评论。
用法示例
public class SuperHero
{
public int Age { get; set; }
public string Name { get; set; }
public List<string> Powers { get; set; }
public override int GetHashCode() =>
HashCode.Of(this.Name).And(this.Age).AndEach(this.Powers);
}
实施
public struct HashCode : IEquatable<HashCode>
{
private const int EmptyCollectionPrimeNumber = 19;
private readonly int value;
private HashCode(int value) => this.value = value;
public static implicit operator int(HashCode hashCode) => hashCode.value;
public static bool operator ==(HashCode left, HashCode right) => left.Equals(right);
public static bool operator !=(HashCode left, HashCode right) => !(left == right);
public static HashCode Of<T>(T item) => new HashCode(GetHashCode(item));
public static HashCode OfEach<T>(IEnumerable<T> items) =>
items == null ? new HashCode(0) : new HashCode(GetHashCode(items, 0));
public HashCode And<T>(T item) =>
new HashCode(CombineHashCodes(this.value, GetHashCode(item)));
public HashCode AndEach<T>(IEnumerable<T> items)
{
if (items == null)
{
return new HashCode(this.value);
}
return new HashCode(GetHashCode(items, this.value));
}
public bool Equals(HashCode other) => this.value.Equals(other.value);
public override bool Equals(object obj)
{
if (obj is HashCode)
{
return this.Equals((HashCode)obj);
}
return false;
}
public override int GetHashCode() => this.value.GetHashCode();
private static int CombineHashCodes(int h1, int h2)
{
unchecked
{
// Code copied from System.Tuple a good way to combine hashes.
return ((h1 << 5) + h1) ^ h2;
}
}
private static int GetHashCode<T>(T item) => item?.GetHashCode() ?? 0;
private static int GetHashCode<T>(IEnumerable<T> items, int startHashCode)
{
var temp = startHashCode;
var enumerator = items.GetEnumerator();
if (enumerator.MoveNext())
{
temp = CombineHashCodes(temp, GetHashCode(enumerator.Current));
while (enumerator.MoveNext())
{
temp = CombineHashCodes(temp, GetHashCode(enumerator.Current));
}
}
else
{
temp = CombineHashCodes(temp, EmptyCollectionPrimeNumber);
}
return temp;
}
}
什么是好算法？
表演
计算哈希码的算法需要很快。简单的算法通常会更快。不分配额外内存的内存也会减少垃圾收集的需求，这反过来也会提高性能。
具体来说，在C#哈希函数中，您经常使用unchecked关键字来停止溢出检查以提高性能。
确定性
哈希算法需要是确定性的，即给定相同的输入，它必须始终产生相同的输出。
减少碰撞
计算哈希代码的算法需要将哈希冲突保持在最小值。哈希冲突是在两个不同对象上对GetHashCode的两次调用产生相同哈希代码时发生的情况。请注意，碰撞是允许的（有些人认为不允许），但应将其保持在最低限度。
许多哈希函数包含像17或23这样的幻数。这些是特殊的素数，与使用非素数相比，由于其数学财产有助于减少散列冲突。
哈希一致性
一个好的哈希函数应该在其输出范围内尽可能均匀地映射期望的输入，即，它应该基于均匀分布的输入输出广泛的哈希。它应该具有哈希一致性。
阻止的DoS
在.NETCore中，每次重新启动应用程序时，都会得到不同的哈希代码。这是防止拒绝服务攻击（DoS）的安全功能。对于.NET Framework，应通过添加以下App.config文件来启用此功能：
<?xml version ="1.0"?>
<configuration>
<runtime>
<UseRandomizedStringHashAlgorithm enabled="1" />
</runtime>
</configuration>
由于此特性，哈希代码不应在创建它们的应用程序域之外使用，也不应将其用作集合中的关键字段，也不应该持久化。
请在此处阅读更多信息。
加密安全？
算法不必是加密哈希函数。这意味着它不必满足以下条件：
生成生成给定哈希值的消息是不可行的。找到具有相同哈希值的两个不同消息是不可行的。对消息进行一次小的更改应该会对哈希值进行广泛的更改，以使新的哈希值看起来与旧的哈希值不相关（雪崩效应）。
其他回答
我在使用上面选择的实现时遇到了浮点和小数的问题。
此测试失败（浮点数；哈希值相同，即使我将2个值切换为负值）：
var obj1 = new { A = 100m, B = 100m, C = 100m, D = 100m};
var obj2 = new { A = 100m, B = 100m, C = -100m, D = -100m};
var hash1 = ComputeHash(obj1.A, obj1.B, obj1.C, obj1.D);
var hash2 = ComputeHash(obj2.A, obj2.B, obj2.C, obj2.D);
Assert.IsFalse(hash1 == hash2, string.Format("Hashcode values should be different hash1:{0} hash2:{1}",hash1,hash2));
但是这个测试通过了（int）：
var obj1 = new { A = 100m, B = 100m, C = 100, D = 100};
var obj2 = new { A = 100m, B = 100m, C = -100, D = -100};
var hash1 = ComputeHash(obj1.A, obj1.B, obj1.C, obj1.D);
var hash2 = ComputeHash(obj2.A, obj2.B, obj2.C, obj2.D);
Assert.IsFalse(hash1 == hash2, string.Format("Hashcode values should be different hash1:{0} hash2:{1}",hash1,hash2));
我改变了我的实现，不再对原始类型使用GetHashCode，它似乎工作得更好
private static int InternalComputeHash(params object[] obj)
{
unchecked
{
var result = (int)SEED_VALUE_PRIME;
for (uint i = 0; i < obj.Length; i++)
{
var currval = result;
var nextval = DetermineNextValue(obj[i]);
result = (result * MULTIPLIER_VALUE_PRIME) + nextval;
}
return result;
}
}
private static int DetermineNextValue(object value)
{
unchecked
{
int hashCode;
if (value is short
|| value is int
|| value is byte
|| value is sbyte
|| value is uint
|| value is ushort
|| value is ulong
|| value is long
|| value is float
|| value is double
|| value is decimal)
{
return Convert.ToInt32(value);
}
else
{
return value != null ? value.GetHashCode() : 0;
}
}
}
微软引领了几种哈希方法。。。
//for classes that contain a single int value
return this.value;
//for classes that contain multiple int value
return x ^ y;
//for classes that contain single number bigger than int
return ((int)value ^ (int)(value >> 32));
//for classes that contain class instance fields which inherit from object
return obj1.GetHashCode();
//for classes that contain multiple class instance fields which inherit from object
return obj1.GetHashCode() ^ obj2.GetHashCode() ^ obj3.GetHashCode();
我可以猜测，对于多个大整数，您可以使用这个：
int a=((int)value1 ^ (int)(value1 >> 32));
int b=((int)value2 ^ (int)(value2 >> 32));
int c=((int)value3 ^ (int)(value3 >> 32));
return a ^ b ^ c;
对于多类型也是如此：首先使用GetHashCode（）将所有类型转换为int然后int值将被xor'ed，结果是您的哈希值。
对于那些使用哈希作为ID（我的意思是一个唯一的值）的人来说，哈希自然被限制在数字个数，我认为哈希算法是5个字节，至少是MD5。
您可以将多个值转换为哈希值，其中一些值是相同的，因此不要将其用作标识符。（也许有一天我会使用你的组件）
我想把我的最新发现添加到我经常提到的这个主题中。
我当前的visual studio/项目设置提供了将元组自动重构为结构的功能。这将生成如下GetHashCode函数：
public override int GetHashCode()
{
int hashCode = -2088324004;
hashCode = hashCode * -1521134295 + AuftragGesperrt.GetHashCode();
hashCode = hashCode * -1521134295 + Auftrag_gesperrt_von.GetHashCode();
hashCode = hashCode * -1521134295 + Auftrag_gesperrt_am.GetHashCode();
return hashCode;
}
编辑：为了澄清AuftragGesperrt、Auftrag _gesperrt_von和Auftrag-gesperrt _am是财产。如果微软的开发人员使用这个功能，这可能是一个不错的解决方案。
这是我的哈希码助手。它的优点是它使用泛型类型参数，因此不会导致装箱：
public static class HashHelper
{
public static int GetHashCode<T1, T2>(T1 arg1, T2 arg2)
{
unchecked
{
return 31 * arg1.GetHashCode() + arg2.GetHashCode();
}
}
public static int GetHashCode<T1, T2, T3>(T1 arg1, T2 arg2, T3 arg3)
{
unchecked
{
int hash = arg1.GetHashCode();
hash = 31 * hash + arg2.GetHashCode();
return 31 * hash + arg3.GetHashCode();
}
}
public static int GetHashCode<T1, T2, T3, T4>(T1 arg1, T2 arg2, T3 arg3,
T4 arg4)
{
unchecked
{
int hash = arg1.GetHashCode();
hash = 31 * hash + arg2.GetHashCode();
hash = 31 * hash + arg3.GetHashCode();
return 31 * hash + arg4.GetHashCode();
}
}
public static int GetHashCode<T>(T[] list)
{
unchecked
{
int hash = 0;
foreach (var item in list)
{
hash = 31 * hash + item.GetHashCode();
}
return hash;
}
}
public static int GetHashCode<T>(IEnumerable<T> list)
{
unchecked
{
int hash = 0;
foreach (var item in list)
{
hash = 31 * hash + item.GetHashCode();
}
return hash;
}
}
/// <summary>
/// Gets a hashcode for a collection for that the order of items
/// does not matter.
/// So {1, 2, 3} and {3, 2, 1} will get same hash code.
/// </summary>
public static int GetHashCodeForOrderNoMatterCollection<T>(
IEnumerable<T> list)
{
unchecked
{
int hash = 0;
int count = 0;
foreach (var item in list)
{
hash += item.GetHashCode();
count++;
}
return 31 * hash + count.GetHashCode();
}
}
/// <summary>
/// Alternative way to get a hashcode is to use a fluent
/// interface like this:<br />
/// return 0.CombineHashCode(field1).CombineHashCode(field2).
/// CombineHashCode(field3);
/// </summary>
public static int CombineHashCode<T>(this int hashCode, T arg)
{
unchecked
{
return 31 * hashCode + arg.GetHashCode();
}
}
此外，它还具有扩展方法来提供流畅的界面，因此您可以这样使用它：
public override int GetHashCode()
{
return HashHelper.GetHashCode(Manufacturer, PartN, Quantity);
}
或者像这样：
public override int GetHashCode()
{
return 0.CombineHashCode(Manufacturer)
.CombineHashCode(PartN)
.CombineHashCode(Quantity);
}
与夜编码器的解决方案非常相似，只是如果你想提高素数更容易。
PS：这是你嘴里吐出一点东西的时候之一，因为你知道这可以用9个默认值重构成一个方法，但它会更慢，所以你闭上眼睛，试着忘掉它。
/// <summary>
/// Try not to look at the source code. It works. Just rely on it.
/// </summary>
public static class HashHelper
{
private const int PrimeOne = 17;
private const int PrimeTwo = 23;
public static int GetHashCode<T1, T2, T3, T4, T5, T6, T7, T8, T9, T10>(T1 arg1, T2 arg2, T3 arg3, T4 arg4, T5 arg5, T6 arg6, T7 arg7, T8 arg8, T9 arg9, T10 arg10)
{
unchecked
{
int hash = PrimeOne;
hash = hash * PrimeTwo + arg1.GetHashCode();
hash = hash * PrimeTwo + arg2.GetHashCode();
hash = hash * PrimeTwo + arg3.GetHashCode();
hash = hash * PrimeTwo + arg4.GetHashCode();
hash = hash * PrimeTwo + arg5.GetHashCode();
hash = hash * PrimeTwo + arg6.GetHashCode();
hash = hash * PrimeTwo + arg7.GetHashCode();
hash = hash * PrimeTwo + arg8.GetHashCode();
hash = hash * PrimeTwo + arg9.GetHashCode();
hash = hash * PrimeTwo + arg10.GetHashCode();
return hash;
}
}
public static int GetHashCode<T1, T2, T3, T4, T5, T6, T7, T8, T9>(T1 arg1, T2 arg2, T3 arg3, T4 arg4, T5 arg5, T6 arg6, T7 arg7, T8 arg8, T9 arg9)
{
unchecked
{
int hash = PrimeOne;
hash = hash * PrimeTwo + arg1.GetHashCode();
hash = hash * PrimeTwo + arg2.GetHashCode();
hash = hash * PrimeTwo + arg3.GetHashCode();
hash = hash * PrimeTwo + arg4.GetHashCode();
hash = hash * PrimeTwo + arg5.GetHashCode();
hash = hash * PrimeTwo + arg6.GetHashCode();
hash = hash * PrimeTwo + arg7.GetHashCode();
hash = hash * PrimeTwo + arg8.GetHashCode();
hash = hash * PrimeTwo + arg9.GetHashCode();
return hash;
}
}
public static int GetHashCode<T1, T2, T3, T4, T5, T6, T7, T8>(T1 arg1, T2 arg2, T3 arg3, T4 arg4, T5 arg5, T6 arg6, T7 arg7, T8 arg8)
{
unchecked
{
int hash = PrimeOne;
hash = hash * PrimeTwo + arg1.GetHashCode();
hash = hash * PrimeTwo + arg2.GetHashCode();
hash = hash * PrimeTwo + arg3.GetHashCode();
hash = hash * PrimeTwo + arg4.GetHashCode();
hash = hash * PrimeTwo + arg5.GetHashCode();
hash = hash * PrimeTwo + arg6.GetHashCode();
hash = hash * PrimeTwo + arg7.GetHashCode();
hash = hash * PrimeTwo + arg8.GetHashCode();
return hash;
}
}
public static int GetHashCode<T1, T2, T3, T4, T5, T6, T7>(T1 arg1, T2 arg2, T3 arg3, T4 arg4, T5 arg5, T6 arg6, T7 arg7)
{
unchecked
{
int hash = PrimeOne;
hash = hash * PrimeTwo + arg1.GetHashCode();
hash = hash * PrimeTwo + arg2.GetHashCode();
hash = hash * PrimeTwo + arg3.GetHashCode();
hash = hash * PrimeTwo + arg4.GetHashCode();
hash = hash * PrimeTwo + arg5.GetHashCode();
hash = hash * PrimeTwo + arg6.GetHashCode();
hash = hash * PrimeTwo + arg7.GetHashCode();
return hash;
}
}
public static int GetHashCode<T1, T2, T3, T4, T5, T6>(T1 arg1, T2 arg2, T3 arg3, T4 arg4, T5 arg5, T6 arg6)
{
unchecked
{
int hash = PrimeOne;
hash = hash * PrimeTwo + arg1.GetHashCode();
hash = hash * PrimeTwo + arg2.GetHashCode();
hash = hash * PrimeTwo + arg3.GetHashCode();
hash = hash * PrimeTwo + arg4.GetHashCode();
hash = hash * PrimeTwo + arg5.GetHashCode();
hash = hash * PrimeTwo + arg6.GetHashCode();
return hash;
}
}
public static int GetHashCode<T1, T2, T3, T4, T5>(T1 arg1, T2 arg2, T3 arg3, T4 arg4, T5 arg5)
{
unchecked
{
int hash = PrimeOne;
hash = hash * PrimeTwo + arg1.GetHashCode();
hash = hash * PrimeTwo + arg2.GetHashCode();
hash = hash * PrimeTwo + arg3.GetHashCode();
hash = hash * PrimeTwo + arg4.GetHashCode();
hash = hash * PrimeTwo + arg5.GetHashCode();
return hash;
}
}
public static int GetHashCode<T1, T2, T3, T4>(T1 arg1, T2 arg2, T3 arg3, T4 arg4)
{
unchecked
{
int hash = PrimeOne;
hash = hash * PrimeTwo + arg1.GetHashCode();
hash = hash * PrimeTwo + arg2.GetHashCode();
hash = hash * PrimeTwo + arg3.GetHashCode();
hash = hash * PrimeTwo + arg4.GetHashCode();
return hash;
}
}
public static int GetHashCode<T1, T2, T3>(T1 arg1, T2 arg2, T3 arg3)
{
unchecked
{
int hash = PrimeOne;
hash = hash * PrimeTwo + arg1.GetHashCode();
hash = hash * PrimeTwo + arg2.GetHashCode();
hash = hash * PrimeTwo + arg3.GetHashCode();
return hash;
}
}
public static int GetHashCode<T1, T2>(T1 arg1, T2 arg2)
{
unchecked
{
int hash = PrimeOne;
hash = hash * PrimeTwo + arg1.GetHashCode();
hash = hash * PrimeTwo + arg2.GetHashCode();
return hash;
}
}
}
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