下面是运行任意命令返回其标准输出数据的Python代码，或在非零退出码上引发异常:
proc = subprocess.Popen(
cmd,
stderr=subprocess.STDOUT, # Merge stdout and stderr
stdout=subprocess.PIPE,
shell=True)
communication用于等待进程退出:
stdoutdata, stderrdata = proc.communicate()
子进程模块不支持超时——杀死运行超过X秒的进程的能力——因此，通信可能需要很长时间才能运行。
在Windows和Linux上运行的Python程序中实现超时的最简单方法是什么?
当前回答
对于python 2.6+，使用gevent
from gevent.subprocess import Popen, PIPE, STDOUT
def call_sys(cmd, timeout):
p= Popen(cmd, shell=True, stdout=PIPE)
output, _ = p.communicate(timeout=timeout)
assert p.returncode == 0, p. returncode
return output
call_sys('./t.sh', 2)
# t.sh example
sleep 5
echo done
exit 1
其他回答
我有一个问题，我想终止一个多线程子进程，如果它花费的时间超过给定的超时长度。我想在Popen()中设置一个超时，但它不起作用。然后，我意识到Popen().wait()等于call()，所以我有了在.wait(timeout=xxx)方法中设置超时的想法，这最终工作了。因此，我是这样解决的:
import os
import sys
import signal
import subprocess
from multiprocessing import Pool
cores_for_parallelization = 4
timeout_time = 15 # seconds
def main():
jobs = [...YOUR_JOB_LIST...]
with Pool(cores_for_parallelization) as p:
p.map(run_parallel_jobs, jobs)
def run_parallel_jobs(args):
# Define the arguments including the paths
initial_terminal_command = 'C:\\Python34\\python.exe' # Python executable
function_to_start = 'C:\\temp\\xyz.py' # The multithreading script
final_list = [initial_terminal_command, function_to_start]
final_list.extend(args)
# Start the subprocess and determine the process PID
subp = subprocess.Popen(final_list) # starts the process
pid = subp.pid
# Wait until the return code returns from the function by considering the timeout.
# If not, terminate the process.
try:
returncode = subp.wait(timeout=timeout_time) # should be zero if accomplished
except subprocess.TimeoutExpired:
# Distinguish between Linux and Windows and terminate the process if
# the timeout has been expired
if sys.platform == 'linux2':
os.kill(pid, signal.SIGTERM)
elif sys.platform == 'win32':
subp.terminate()
if __name__ == '__main__':
main()
没想到居然没人提到超时
Timeout 5 ping -c 3 somehost
显然，这并不适用于每个用例，但如果您处理的是一个简单的脚本，那么这是很难克服的。
mac用户也可以通过homebrew在coreutils中使用gtimeout。
在Python 3.7.8中超时测试后捕获的输出示例:
try:
return subprocess.run(command, shell=True, capture_output=True, timeout=20, cwd=cwd, universal_newlines=True)
except subprocess.TimeoutExpired as e:
print(e.output.decode(encoding="utf-8", errors="ignore"))
assert False;
异常子进程。TimeoutExpired有输出和其他成员:
cmd -用于生成子进程的命令。 timeout -超时时间，单位为秒。 output -子进程的输出，如果它是由run()或 check_output()。否则,没有。 stdout -输出的别名，用于与stderr对称。 stderr -子进程的stderr输出，如果它被捕获 run()。否则,没有。
更多信息:https://docs.python.org/3/library/subprocess.html#subprocess.TimeoutExpired
如果你用的是Unix，
import signal
...
class Alarm(Exception):
pass
def alarm_handler(signum, frame):
raise Alarm
signal.signal(signal.SIGALRM, alarm_handler)
signal.alarm(5*60) # 5 minutes
try:
stdoutdata, stderrdata = proc.communicate()
signal.alarm(0) # reset the alarm
except Alarm:
print "Oops, taking too long!"
# whatever else
有一个想法是子类化Popen类并用一些简单的方法装饰器来扩展它。我们叫它ExpirablePopen吧。
from logging import error
from subprocess import Popen
from threading import Event
from threading import Thread
class ExpirablePopen(Popen):
def __init__(self, *args, **kwargs):
self.timeout = kwargs.pop('timeout', 0)
self.timer = None
self.done = Event()
Popen.__init__(self, *args, **kwargs)
def __tkill(self):
timeout = self.timeout
if not self.done.wait(timeout):
error('Terminating process {} by timeout of {} secs.'.format(self.pid, timeout))
self.kill()
def expirable(func):
def wrapper(self, *args, **kwargs):
# zero timeout means call of parent method
if self.timeout == 0:
return func(self, *args, **kwargs)
# if timer is None, need to start it
if self.timer is None:
self.timer = thr = Thread(target=self.__tkill)
thr.daemon = True
thr.start()
result = func(self, *args, **kwargs)
self.done.set()
return result
return wrapper
wait = expirable(Popen.wait)
communicate = expirable(Popen.communicate)
if __name__ == '__main__':
from subprocess import PIPE
print ExpirablePopen('ssh -T git@bitbucket.org', stdout=PIPE, timeout=1).communicate()
