如果你使用MFC，你可以使用CString

CString nameAge = "";
nameAge.Format("%s%d", "John", 21);

托管c++也有一个 字符串格式化程序。

常见答案:itoa()

这很糟糕。正如这里指出的，Itoa是非标准的。

#include <iostream>
#include <string>
#include <sstream>
using namespace std;
string itos(int i) // convert int to string
{
    stringstream s;
    s << i;
    return s.str();
}

无耻地从http://www.research.att.com/~bs/bs_faq2.html窃取。

下面是如何使用IOStreams库中的解析和格式化aspect将int附加到字符串的实现。

#include <iostream>
#include <locale>
#include <string>

template <class Facet>
struct erasable_facet : Facet
{
    erasable_facet() : Facet(1) { }
    ~erasable_facet() { }
};

void append_int(std::string& s, int n)
{
    erasable_facet<std::num_put<char,
                                std::back_insert_iterator<std::string>>> facet;
    std::ios str(nullptr);

    facet.put(std::back_inserter(s), str,
                                     str.fill(), static_cast<unsigned long>(n));
}

int main()
{
    std::string str = "ID: ";
    int id = 123;

    append_int(str, id);

    std::cout << str; // ID: 123
}

在我看来，最简单的答案是使用sprintf函数:

sprintf(outString,"%s%d",name,age);

这个问题可以用许多方法解决。我将以两种方式展示它:

Convert the number to string using to_string(i). Using string streams. Code: #include <string> #include <sstream> #include <bits/stdc++.h> #include <iostream> using namespace std; int main() { string name = "John"; int age = 21; string answer1 = ""; // Method 1). string s1 = to_string(age). string s1=to_string(age); // Know the integer get converted into string // where as we know that concatenation can easily be done using '+' in C++ answer1 = name + s1; cout << answer1 << endl; // Method 2). Using string streams ostringstream s2; s2 << age; string s3 = s2.str(); // The str() function will convert a number into a string string answer2 = ""; // For concatenation of strings. answer2 = name + s3; cout << answer2 << endl; return 0; }